Now in Britain , wines take up four times as much ______ in the storehouse as both beer and spiritsA) block B) land C) patch D) space

题目

Now in Britain  , wines take up four times as much ______ in the storehouse as both beer and spirits

A) block           B) land                    C) patch        D) space      

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更多“Now in Britain , wines take up four times as much ”相关问题

  • 第1题：

    A) times above

    B) time

    C) times in

    D) times


    正确答案：D
    答案：D
    [试题分析]语法知识的运用。
    [详细解答]表示倍数，直接用…times，后不用加任何介词，直接跟比较的对象，故答案为D。

  • 第2题：

    __________

    A.number
    B.amount
    C.many
    D.much

    答案：A
    解析：

  • 第3题：

    200 times 365 times 20 is（).

    A．200*365*20

    B．200+365+20


    B

  • 第4题：

    2． The clean-up．day is only two weeks _______ now，so we must action quickly．

    A． from

    B． since

    C． to

    D． for


    正确答案：A
    2.A【解析】由句意可知，clean-up day离现在还有两周，应用from。

  • 第5题：

    下列给字符串二维数组进行赋值的语句中，错误的是（）。

    A．String s[ ] [ ] = new String [ ] [ ] { { “One “ , “ Two “ }, { “ Three “ , “ Four “ } } ;

    B．String s[ ] [ ] = { { “ One “ , “Two “},{ “ Three “ , “ Four “ } } ;

    C．String s[ ] [ ] = new String [ ] [ ] { { “Zero”} , { “ One ” , “Two” , “ Three” , “ Four” } } ;

    D．String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;


    String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;

  • 第6题：

    1、利用艾拉托斯特尼筛法无穷素数列表primes （参见讲义第8章) 获得介于100000和200000之间素数的方法是

    A．take 200000 (take 100000 primes)

    B．take 100000 (take 200000 primes)

    C．take 100000 (drop 100000 primes)

    D．takeWhile (\x -> x <= 200000) (dropWhile (\x -> x <= 100000) primes)

    E．takeWhile (\x -> x <= 200000) (take 200000 primes)

    F．[x | x <- primes, x >100000, x < 200000]

    G．[x | x <- take 200000 primes, x >100000, x < 200000]


    Sieve(n，P)． 输入：正整数n． 输出：小于等于n的所有素数P． ①if n=1 then P← ，计算结束； ②P←{2}； ③a←2； ④if n=a then计算结束； ⑤b←min{a 2 ，n}； ⑥Q←{x|a＜x≤b}； ⑦for P中的每一个x ⑧for Q中的每一个y ⑨ then从Q中删去y； ⑩P←P∪Q； (11)a←b； (12)转④．

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