Assumethatcountryissetforeachclass.Given：10.publicclassMoney{11.privateStringcountry，name；12.publicgetCountry（）{returncountry；}13.}and：24.classYenextendsMoney{25.publicStringgetCountry（）{returnsuper.country；}26.}27.28.classEuroextendsMoney{29.publicString

题目

Assumethatcountryissetforeachclass.Given：10.publicclassMoney{11.privateStringcountry，name；12.publicgetCountry（）{returncountry；}13.}and：24.classYenextendsMoney{25.publicStringgetCountry（）{returnsuper.country；}26.}27.28.classEuroextendsMoney{29.publicStringgetCountry（StringtimeZone）{30.returnsuper.getCountry（）；31.}32.}Whichtwoarecorrect？（）

A.Yenreturnscorrectvalues.

B.Euroreturnscorrectvalues.

C.Anexceptionisthrownatruntime.

D.YenandEurobothreturncorrectvalues.

E.Compilationfailsbecauseofanerroratline25.

F.Compilationfailsbecauseofanerroratline30.

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参考答案和解析
参考答案：B, E
更多“Assumethatcountryissetforeachclass.Given:10.publicclassMoney{11.privateStringcountry,name; ”相关问题

  • 第1题：

    Examine the structure of the EMPLOYEES table:Column name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyLAST_NAME VARCNAR2(30)FIRST_NAME VARCNAR2(30)JOB_ID NUMBERSAL NUMBERMGR_ID NUMBER References EMPLOYEE_ID column DEPARTMENT_ID NUMBERYou need to create an index called NAME_IDX on the first name and last name fields of the EMPLOYEES table. Which SQL statement would you use to perform this task? （）

    A. CREATE INDEX NAME _IDX (first_name, last_name);

    B. CREATE INDEX NAME _IDX (first_name, AND last_name)

    C. CREATE INDEX NAME_IDX ON (First_name, last_name);

    D. CREATE INDEX NAME_IDX ON employees (First_name, AND last_name);

    E. CREATE INDEX NAME_IDX ON employees (First_name, last_name);

    F. CREATE INDEX NAME_IDX FOR employees (First_name, last_name);


    参考答案：E

  • 第2题：

    html语言中,创建一个位于文档内部的锚点的语句是()。

    A.<name=“NAME”>

    B.<name=“NAME”></name>

    C.<aname=“NAME”></a>

    D.<aname=“NAME”></a>


    正确答案：C

  • 第3题：

    康唑类药品的药名词干是

    A．#NAME?

    B．#NAME?

    C．#NAME?

    D．#NAME?

    E．#NAME?


    正确答案：C

  • 第4题：

    Which syntax turns an existing constraint on? ()

    A. ALTER TABLE table_name ENABLE constraint_name;

    B. ALTER TABLE table_name STATUS = ENABLE CONSTRAINT constraint _ name;

    C. ALTER TABLE table_name ENABLE CONSTRAINT constraint _ name;

    D. ALTER TABLE table_name TURN ON CONSTRAINT constraint _ name;


    参考答案：C

  • 第5题：

    有以下程序段

    char．name[20]；int num；

    scanf(“name=％s num=％d”，name，＆num)；

    当执行上述程序段，并从键盘输入：name=Lili num=1001<回车>后，name的值为

    A．Lill

    B．name=Lili

    C．Lili．num=

    D．name=Lili num—1001


    正确答案：A
    解析：scanf函数巾的格式控制字符串是为了输入数据用的．尤论其中有什么字符．也不会输出到屏幕上。输入数据时要按照一一对应的位置原样输入这些字符，包括字符的大小写、字符间的间隔等必须与scanf巾的完全一致。故执行程序后name的值为Lli。

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