Dr. Smith, together with his wife, ( ) to arrive in the evening flight.A. areB. are going toC. isD. will be

题目

Dr. Smith, together with his wife, ( ) to arrive in the evening flight.

A. are

B. are going to

C. is

D. will be

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更多“Dr. Smith, together with his wife, ( ) to arrive in the evening flight. A. are B. are ”相关问题

  • 第1题：

    He often works in ( )evening.

    A. a

    B. /

    C. the


    答案：C

  • 第2题：

    有以下程序#include <stdio.h>void fun(char **p){ p=p+2; printf("%s\n",*p);}main(){ char *a[]={"Morning","Afternoon","Evening","Night"}; fun(a);}程序的运行结果是A．rningB．afternoonC．ternoon D．Evening


    正确答案：D
    本题主要考查指向指针的指针。在程序中，首先定义了一个fun函数，函数无返回类型，函数的形参是一个指向指针的指针变量p，在该函数体中，首先将变量p的值加2，并保存在p中，根据指针变量的特性，这个加2是使指针变量往后移两个单位，如果开始指向第一个元素，现在则指向第三个元素（注意：这里并不是指移动两个字节）。然后输出*p，由于p是一个指向指针的变量，那么*p输出的也不是单个数组，而是一个首地址对应的字符串或数组，在本题中输出的是字符串。
    在主函数中，定义一个指针数组a，并赋初值，然后调用函数fun，实参为a，输出的应该是指针数组中第3个指针对应的字符串，即Evening。

  • 第3题：

    What does Mary Unger say she will do?

    A. Set up the equipment by herself

    B. Arrive 30 minutes early on Thursday

    C. Make copies of her presentation materials

    D. E-mail the presentation schedule later that day.

    答案：C
    解析：

  • 第4题：

    以下程序的输出结果是()。includevoid func(char**m) {＋＋m:cout<<*m<

    以下程序的输出结果是( )。 #include＜iostream.h＞ void func(char**m) { ++m： cout＜＜*m＜＜endl； } void main() { static char*a[]={"MORNING","AFTERTOON","EVENING"}； char**n； n=a： func(n)； }

    A．为空

    B．MORNING

    C．AFTERTOON

    D．EVENING


    正确答案：C

  • 第5题：

    Wife. Do you have any idea for the weekend?

    Husband: ______?


    正确答案：H

  • 第6题：

    在接听酒店外线电话，且对方是说英语的客人，我们该如何应对？

    A.Good morning /afternoon/ evening.#B.Hello, this is XX hotel.#C.Morning, what can I do for you？#D.Good morning /afternoon/ evening, XXX hotel. Thanks for your calling. How may I assist you？
    Good morning /afternoon/ evening, XXX hotel. Thanks for your calling. How may I assist you?

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