The boy has been taking piano lessons from my neighbor ( ) he was 12.A、ever sinceB、ever whenC、from whenD、from since

题目
The boy has been taking piano lessons from my neighbor ( ) he was 12.

A、ever since

B、ever when

C、from when

D、from since

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更多“The boy has been taking piano lessons from my neighbor ( ) he was 12. ”相关问题

  • 第1题：

    Which configuration command establishes an EBGP session to a peer in AS 300?()

    A. neighbor 200.16.1.2 remote-as 300

    B. bgp-neighbor 200.16.1.2 remote-as 300

    C. ebgp-neighbor 200.16.1.2 remote-as 300

    D. neighbor 200.16.1.2 remote-as 300 connection-type ebgp


    参考答案：A

  • 第2题：

    Based on the show ip bgp summary output, which two statements are true?()

    A. The BGP session to the 10.3.3.3 neighbor is established, but the router has not received any BGP routing updates from the 10.3.3.3 neighbor.

    B. The router is attempting to establish a BGP peering session with the 10.2.2.2 neighbor.

    C. The router is attempting to establish a BGP peering session with the 10.1.1.1 neighbor.

    D. The BGP session to the 10.3.3.3 neighbor is established.

    E. The BGP session to the 10.2.2.2 neighbor is established.

    F. The BGP session to the 10.1.1.1 neighbor is established.


    参考答案：B, F

  • 第3题：

    --Where do you think______he______the computer?---Sorry．I have no idea．

    A.has;bought
    B.不填;bought
    C.did;buy
    D.不填;buys

    答案：B
    解析：
    暂无解析

  • 第4题：

    R1 in ASN 1 with loopback1 address 1.1.1.1 needs to be configured with an iBGP connection to R2 with loopback2 IP address 2.2.2.2. The connection should use the loopbacks.Which o f the following commands is required on R1?（）

    A. neighbor 1.1.1.1 remote- as 1

    B. neighbor 2.2.2.2 remote- as 2

    C. neighbor 2.2.2.2 update - source loopback1

    D. neighbor 2.2.2.2 ibgp -multihop 2

    E. neighbor 2.2.2.2 ibgp - mode


    参考答案：C

  • 第5题：

    （ ）

    A．math

    B．English

    C．Chinese

    D．lessons


    正确答案：D

  • 第6题：

    对字符串"Boy"进行完整赋值的操作是（）。

    A．char s[3] = {'B','o','y'};

    B．char s[] = "Boy";

    C．char s[3] = {"Boy"};

    D．char s[3]; s="Boy";


    C选项A、B的空间不够；选项D中字符串存储要有结束符ˊ＼0ˊ，且要占用一个空间，printf用来输出

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