129.35.12.0
129.35.16.0
129.35.52.0
129.35.128.0
第1题:
AclassBnetwork129.35has4subnetsandanetmaskof255.255.252.0(11111111.11111111.11111100.00000000).TowhichofthefollowingsubnetswilltheclassBnetworkdeliverapacketofaddress129.35.14.04(10000001.00100011.00001110.00000100)?()
A.129.35.12.0
B.129.35.16.0
C.129.35.52.0
D.129.35.128.0
第2题:
A.201.57.78.33
B.201.57.78.64
C.201.57.78.97
D.201.56.78.97
E.201.57.78.159
F.201.57.78.254
第3题:
A Class C network address has been subnetted with a /27 mask.Which of the following addresses is a broadcast address for one of the resulting subnets?()
第4题:
Which of the following class networks represents a possibility of being further subnetted into 2 subnets of 128 hosts per subnet?()
第5题:
Your network uses the172.12.0.0 class B address. You need to support 459 hosts per subnet, while accommodating the maximum number of subnets. Which mask wouldyou use?()
第6题:
When dividing an existing Class B network into 2 subnets of 32,766 hosts each, which of the following subnet masks should be used?()
第7题:
What is the purpose of a network mask?()
第8题:
There are 254 usable subnets.
There are 256 usable hosts per subnet.
There are 50 usable subnets.
There are 254 usable hosts per subnet.
There are 24 usable hosts per subnet.
There is one usable network.
第9题:
225.225.224.0.
225.225.240.0.
225.225.255.0.
255.255.255.224
225.225.255.240
第10题:
201.57.78.33
201.57.78.64
201.57.78.97
201.56.78.97
201.57.78.159
201.57.78.254
第11题:
255.255.128.0 (11111111.11111111.10000000.00000000)
255.255.192.0 (11111111.11111111.11000000.00000000)
255.255.224.0 (11111111.11111111.11100000.00000000)
255.255.240.0 (11111111.11111111.11110000.00000000)
第12题:
255.255.0.0
255.255.224.0
255.255.254.0
255.255.255.0
255.255.255.224
第13题:
Ezonexam has a Class C network and you need ten subnets. You wish to have as many addresses available for hosts as possible. Which one of the following subnet masks should you use?
A.255.255.255.192
B.255.255.255.224
C.255.255.255.240
D.255.255.255.248
E.None of the above
第14题:
A. It corresponds to a Class A address with 13 bits borrowed.
B. It corresponds to a Class B address with 4 bits borrowed.
C. The network address of the last subnet will have 248 in the 3rd octet.
D. The first 21 bits make the host portion of the address.
E. This subnet mask allows for 16 total subnets to be created.
F. The subnetwork numbers will be in multiples of 8.
第15题:
You have a class C network, and you need to design it for 5 usable subnets with each subnet handling a minimum of 18 hosts each. Which of the following network masks should you use?()
第16题:
Given that you have a class B IP address network range, which of the subnet masks below will allow for 100 subnets with 500 usable host addresses per subnet?()
第17题:
You have a class B network with a 255.255.255.0 mask. Which of the statements below are true of this network?()
第18题:
A class B network 129.35 has 4 subnets and a netmask of 255.255.252.0 (11111111.11111111.11111100.00000000). To which of the following subnets will the class B network deliver a packet of address 129.35.14.04 (10000001.00100011.00001110.00000100)?()
第19题:
A class B network 129.35 has 10 subnets. Which of the following options is the correct subnet mask?()
第20题:
128.0.0.0
255.128.0.0
255.254.0.0
255.255.128.0
第21题:
129.35.12.0
129.35.16.0
129.35.52.0
129.35.128.0
第22题:
It is used in conjunction with the wildcard mask to determine the number of hosts on a network
It is used to define which parts of the IP address are allocated to host addresses and network prefixes
It is used to hide subnets from external networks by masking the subnets with NAT
It is used to differentiate a network as a classful network or a classless network
第23题:
It corresponds to a Class A address with 13 bits borrowed.
It corresponds to a Class B address with 4 bits borrowed.
The network address of the last subnet will have 248 in the 3rd octet.
The first 21 bits make the host portion of the address.
This subnet mask allows for 16 total subnets to be created.
The subnetwork numbers will be in multiples of 8.
第24题:
255.255.0.0.
255.255.128.0.
255.255.224.0.
255.255.254.0.