单选题OFDM的英文全称是（）A Orthogonal Frequency Division MultiplexingB Outstanding Frequency Division MultiplexingC Overwhelming Frequency Division MultiplexingD Orthogonal Frequency Division Modulation

题目
单选题
OFDM的英文全称是（）
A

Orthogonal Frequency Division Multiplexing

B

Outstanding Frequency Division Multiplexing

C

Overwhelming Frequency Division Multiplexing

D

Orthogonal Frequency Division Modulation

相似考题

1.在通信专业中，WDM的英文全称是（ ），“吞吐量”英文通常翻译为（ ）。[1分]A.Wierless Digital ModulationB.Wave Division MultiplexingC.Wavelength Division MultiplexingD.Wireless Data Modulation

2.Which of the following could serve as an appropriate title for the passage ?A．The Theory of Division of LaborB．Adam Smith as the Discoverer of Division of LaborC．Adam Smith, the English EconomistD．Division of Labor, an Efficient Way of Organizing Work

3.在LTE系统中，为了支持成对的和不成对的频谱，支持频分双工(Frequency Division Duplex，FDD)模式和时分双工(Time Division Duplex，TDD)模式。LTE支持两种类型的无线帧结构：类型1，适应于全双工和半双工的FDD模式，类型2适应于TDD模式。()

4.TDD表示的含义( )。A. transfer control protocolB. time division duplexC. time division synchronous CDMAD. time division multiple access

更多“单选题OFDM的英文全称是（）A Orthogonal Frequency Division MultiplexingB Outstanding Frequency Division MultiplexingC Overwhelming Frequency Division MultiplexingD Orthogonal Frequency Division Modulation”相关问题

  • 第1题：

    在通信专业中，WDM的英文全称是（），“吞吐量”英文通常翻译为（）。

    A．Wierless Digital Modulation B．Wave Division Multiplexing C．Wavelength Division Multiplexing D．Wireless Data Modulation A．traffic flow B．rate C．throughout D．throughput


    正确答案：C,D

  • 第2题：

    F－OFDM英文全称是Flexible Orthogonal Frequency Division Multiplexing,中文叫灵活的正交频分复用。()

    此题为判断题(对，错)。


    答案：错

  • 第3题：

    OFDM的英文是()

    A.OverloadFrequencyDivisionMultiplexing

    B.Orthogonal?Frequency?Division?Multiplexing

    C.Overwhelming?Frequency?DivisionMultiplexing

    D.Outstanding?Frequency?Division?Multiplexing


    正确答案：B

  • 第4题：


    What did the sentence“The other countries had respected this division so long as they remained Catholic”imply？( )

    A.It implied this division could not be respected long.
    B.It implied this division would not face a challenge.
    C.It implied this division would be respected forever.
    D.It implied the power of the Pope would never decline.

    答案：A
    解析：
    推理题。第三段的最后两句话指出“1494年，哥伦布首次远航美洲后的两年，教皇亚历山大六世就把这块大洋彼岸未曾勘探的世界分给西班牙和葡萄牙作为对他们业绩的褒奖(赏赐)并制止他们开战。只要其他国家依然信仰天主教，他们就会尊重这种瓜分”。题目中as long as是一个条件，一旦这个条件不存在，那就不会再尊重。另一方面也说明教皇不仅统治宗教，在其他方面也有至高无上的权力。所以B项“不会面临挑战”、C项“永远得到尊重”和D项“教皇权力永不衰退”均不符合题意。

  • 第5题：

    frequency division multiplexing频分多路复用


    正确答案: 一种常用的多路复用技术，容许多个发送方通过公共介质发送。由于每个发送方使用不同的频率，多个发送方能同时发送而不会冲突。

  • 第6题：

    对于LTE物理层的多址方案，在下行方向上采用基于循环前缀（Cyclic Prefix，CP）的正交频分复用（Orthogonal Frequency Division Multiplexing，OFDM），在上行方向上采用基于循环前缀的单载波频分多址（Single Carrrier-Frequency Division Multiplexing Access，SC-FDMA）。在上行方向上采用基于循环前缀的单载波频分多址（Single Carrrier-Frequency Division Multiplexing Access，SC-FDMA）。


    正确答案:正确

  • 第7题：

    射频识别技术的英文全称是Radio Frequency Identification缩写（）


    正确答案:RFID

  • 第8题：

    802.11b是基于正交频分复用（Orthogonal Frequency Division Multiplexing，简称OFDM）技术的协议。


    正确答案:错误

  • 第9题：

    跳频为（）。

    • A、frequency hopping
    • B、frequency spreading
    • C、frequency sequence
    • D、chirp

    正确答案:A

  • 第10题：

    DWDM全称为（）。

    • A、dense wavelength division multiplexing
    • B、dense waveguide division multiplexing
    • C、divided wavelength dimension multiplexing
    • D、divided waveguide dimension mode

    正确答案:A

  • 第11题：

    单选题
    TDD表示的含义（）。
    A

    transfer control protocol

    B

    time division duplex

    C

    time division synchronous CDMA

    D

    time division multiple access


    正确答案： A
    解析： 暂无解析

  • 第12题：

    判断题
    802.11b是基于正交频分复用（Orthogonal Frequency Division Multiplexing，简称OFDM）技术的协议。
    A

    对

    B

    错


    正确答案： 错
    解析： 暂无解析

  • 第13题：

    对于LTE物理层的多址方案，在下行方向上采用基于循环前缀(Cyclic Prefix，CP)的正交频分复用(Orthogonal Frequency Division Multiplexing，OFDM)，在上行方向上采用基于循环前缀的单载波频分多址(Single Carrrier-Frequency Division Multiplexing Access，SC-FDMA)。()


    标准答案：对

  • 第14题：

    A manufacturing company, Man Co, has two divisions: Division L and Division M. Both divisions make a single standardised product. Division L makes component L, which is supplied to both Division M and external customers.

    Division M makes product M using one unit of component L and other materials. It then sells the completed

    product M to external customers. To date, Division M has always bought component L from Division L.

    The following information is available:

    Division L charges the same price for component L to both Division M and external customers. However, it does not incur the selling and distribution costs when transferring internally.

    Division M has just been approached by a new supplier who has offered to supply it with component L for $37 per unit. Prior to this offer, the cheapest price which Division M could have bought component L for from outside the group was $42 per unit.

    It is head office policy to let the divisions operate autonomously without interference at all.

    Required:

    (a) Calculate the incremental profit/(loss) per component for the group if Division M accepts the new supplier’s

    offer and recommend how many components Division L should sell to Division M if group profits are to be

    maximised. (3 marks)

    (b) Using the quantities calculated in (a) and the current transfer price, calculate the total annual profits of each division and the group as a whole. (6 marks)

    (c) Discuss the problems which will arise if the transfer price remains unchanged and advise the divisions on a suitable alternative transfer price for component L. (6 marks)


    正确答案：
    (a)MaximisinggroupprofitDivisionLhasenoughcapacitytosupplybothDivisionManditsexternalcustomerswithcomponentL.Therefore,incrementalcostofDivisionMbuyingexternallyisasfollows:CostperunitofcomponentLwhenboughtfromexternalsupplier:$37CostperunitforDivisionLofmakingcomponentL:$20.ThereforeincrementalcosttogroupofeachunitofcomponentLbeingboughtinbyDivisionMratherthantransferredinternally:$17($37–20).Fromthegroup’spointofview,themostprofitablecourseofactionisthereforethatall120,000unitsofcomponentLshouldbetransferredinternally.(b)CalculatingtotalgroupprofitTotalgroupprofitswillbeasfollows:DivisionL:Contributionearnedpertransferredcomponent=$40–$20=$20Profitearnedpercomponentsoldexternally=$40–$24=$16(c)ProblemswithcurrenttransferpriceandsuggestedalternativeTheproblemisthatthecurrenttransferpriceof$40perunitisnowtoohigh.Whilstthishasnotbeenaproblembeforesinceexternalsupplierswerecharging$42perunit,itisaproblemnowthatDivisionMhasbeenofferedcomponentLfor$37perunit.IfDivisionMnowactsinitsowninterestsratherthantheinterestsofthegroupasawhole,itwillbuycomponentLfromtheexternalsupplierratherthanfromDivisionL.ThiswillmeanthattheprofitsofthegroupwillfallsubstantiallyandDivisionLwillhavesignificantunusedcapacity.Consequently,DivisionLneedstoreduceitsprice.Thecurrentpricedoesnotreflectthefactthattherearenosellinganddistributioncostsassociatedwithtransferringinternally,i.e.thecostofsellinginternallyis$4lessforDivisionLthansellingexternally.So,itcouldreducethepriceto$36andstillmakethesameprofitonthesesalesasonitsexternalsales.ThiswouldthereforebethesuggestedtransferpricesothatDivisionMisstillsaving$1perunitcomparedtotheexternalprice.Atransferpriceof$37wouldalsopresumablybeacceptabletoDivisionMsincethisisthesameastheexternalsupplierisoffering.

  • 第15题：

    The traditional way of allocating a single channel among multiple competing users is to chop up its ( ) by using one of the multiplexing schemes such as FDM (Frequency Division Multiplexing). If there are N users, the bandwidth is divided into N equal-sized portions, with each user being assigned one portion. Since each user has a private frequency ( ), there is no interference among users.When there is only a small and constant number of users, each of which has a steady stream or a heavy load of ( 本 题 ), this division is a simple and efficient allocation mechanism. A wireless example is FM radio stations. Each station gets a portion of the FM band and uses it most of the time to broadcast its signal.However, when the number of senders is large and varying or the traffic is ( ), FDM presents some problems. If the spectrum is cut up into N regions while fewer than N users are currently interested in communicating, a large piece of valuable spectrum will be wasted. If more than N users want to communicate, some of them will be denied ( ) for lack of bandwidth.?

    A. traffic
    B. date
    C. bursty
    D. flow

    答案：A
    解析：

  • 第16题：

    WCDMA英文全称是Wideband Code Division Multiple Access，其系统带宽、码片速率分别是（），（）。


    正确答案:5MHz；3.84Mbps

  • 第17题：

    LTE FDD（Frequency Division Duplexing，FDD）采用的是（）

    • A、频分双工
    • B、时分双工
    • C、码间干扰
    • D、多址干扰

    正确答案:A

  • 第18题：

    FDM的英文是（）

    • A、Overload Frequency Division Multiplexing 
    • B、Orthogonal Frequency Division Multiplexing 
    • C、Overwhelming Frequency Division Multiplexing 
    • D、Outstanding Frequency Division Multiplexing

    正确答案:B

  • 第19题：

    OFDM的英文全称是（）

    • A、Orthogonal Frequency Division Multiplexing
    • B、Outstanding Frequency Division Multiplexing
    • C、Overwhelming Frequency Division Multiplexing
    • D、Orthogonal Frequency Division Modulation

    正确答案:A

  • 第20题：

    WDM与（）本质是相同的。

    • A、OFDM(optical frequency division multiplexing)
    • B、OTDM(optical time division multiplexing)
    • C、CDM(code division multiplexing)
    • D、EDFA(erbium doped fiber amplifier)

    正确答案:A

  • 第21题：

    WDM全称为（）。

    • A、wavelength division multiplexing
    • B、waveguide division multiplexing
    • C、wavelength dimension multiplexing
    • D、waveguide division mode

    正确答案:A

  • 第22题：

    单选题
    OFDM的英文全称是（）
    A

    Orthogonal Frequency Division Multiplexing

    B

    Outstanding Frequency Division Multiplexing

    C

    Overwhelming Frequency Division Multiplexing

    D

    Orthogonal Frequency Division Modulation


    正确答案： C
    解析： 暂无解析

  • 第23题：

    填空题
    射频识别技术的英文全称是Radio Frequency Identification缩写（）

    正确答案： RFID
    解析： 暂无解析

  • 第24题：

    名词解释题
    frequency division multiplexing频分多路复用

    正确答案： 一种常用的多路复用技术，容许多个发送方通过公共介质发送。由于每个发送方使用不同的频率，多个发送方能同时发送而不会冲突。
    解析： 暂无解析

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