It can be inferred from the last paragraph that Christopher______.
A.was more likely to change his mind
B.would return to his office in the bank
C.made a big success in interior design
D.was not well-prepared for his business
第1题:
已知last指向单向简单链表的尾结点,将s所指结点加在表尾,不正确的操作是____。
A.last->next=s,last=s,last->next=NULL;
B.last->next=s,s->next=NULL,last=s;
C.s->next=NULL, last->next=s, s=last;
D.s->next=NULL, last->next=s,last=s;
第2题:
已知last指向单向简单链表的尾结点,将s所指结点插入在表尾,正确的操作是____。
A.s->next=s,last=s,last->next=NULL;
B.last->next=s,s->next=NULL,last=s;
C.s->next=NULL, last->next=s, s=last;
D.s->next=last, last->next=NULL,last=s;
第3题:
2、已知last指向单向简单链表的尾结点,将s所指结点插入在表尾,正确的操作是____。
A.s->next=s,last=s,last->next=NULL;
B.last->next=s,s->next=NULL,last=s;
C.s->next=NULL, last->next=s, s=last;
D.s->next=last, last->next=NULL,last=s;
第4题:
7、已知last指向单向简单链表的尾结点,将s所指结点加在表尾,正确的操作是____。
A.s->next=s,last=s,last->next=NULL;
B.last->next=s,s->next=NULL,last=s;
C.s->next=NULL, last->next=s, s=last;
D.s->next=last, last->next=NULL,last=s;
第5题:
已知last指向单向简单链表的尾结点,将s所指结点加在表尾,正确的操作是____。
A.s->next=s,last=s,last->next=NULL;
B.last->next=s,s->next=NULL,last=s;
C.s->next=NULL, last->next=s, s=last;
D.s->next=last, last->next=NULL,last=s;
第6题:
已知last指向单向简单链表的尾结点,将s所指结点加在表尾,不正确的操作是____。
A.s->next=NULL, last->next=s,last=s;
B.s->next=NULL, last->next=s, s=last;
C.last->next=s,s->next=NULL,last=s;
D.last->next=s,last=s,last->next=NULL;