Click the Exhibit button and examine the data in the EMPLOYEES table.On the EMPLOYEES table, EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID. The JOB_ID column is a NOT NULL column.Evaluate this DELETE statement:

题目

Click the Exhibit button and examine the data in the EMPLOYEES table.On the EMPLOYEES table, EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID. The JOB_ID column is a NOT NULL column.Evaluate this DELETE statement:DELETE employee_id, salary, job_idFROM employeesWHERE dept_id = 90;Why does the DELETE statement fail when you execute it?（）

A.There is no row with dept_id 90 in the EMPLOYEES table.

B.You cannot delete the JOB_ID column because it is a NOT NULL column.

C.You cannot specify column names in the DELETE clause of the DELETE statement.

D.You cannot delete the EMPLOYEE_ID column because it is the primary key of the table.

相似考题

1.Exhibit: You are developing a Web application. The Web application uses a GridView control to display data. You build your Web Forms for the Web application by dragging and dropping tables from the Data Connections tree in Server Explorer. You need to add a connection to your data by using the Add Connection dialog box as shown in the exhibit. During the process, you need to configure the .NET Data Provider that you use to create the data source objects. What should you do?（）A. Right-click the connection, and click Properties. Modify the Provider property of the data connection.B. Click the Change button, and change the data provider for the selected data source.C. Click the Advanced button, and change the Data Source property to the target provider.D. Click the Advanced button, and change the Application Name property to the target provider.

2.Examine the data in the EMPLOYEES table:Which three subqueries work? ()A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

3.Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables.For which situation would you use a nonequijoin query?()A. To find the tax percentage for each of the employees.B. To list the name, job id, and manager name for all the employees.C. To find the name, salary, and department name of employees who are not working with Smith.D. To find the number of employees working for the Administrative department and earning less then 4000.E. To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.

4.Examine the exhibit to view the parameters set in your parameter file. (Click the Exhibit(s) button.)You restart the instance.To what value will the MEMORY_MAX_TARGET parameter be set by default?()A.120MB.320MC.480MD.600M

参考答案和解析
参考答案：C
更多“Click the Exhibit button and examine the data in the EMPLOYEES table.On the EMPLOYEES tabl ”相关问题

  • 第1题：

    Exhibit:Examine the data in the EMPLOYEES table.Examine the subquery:SELECT last_nameFROM employeesWHERE salary IN (SELECT MAX(salary)FROM employeesGROUP BY department_id);Which statement is true?()

    A. The SELECT statement is syntactically accurate.

    B. The SELECT statement does not work because there is no HAVING clause.

    C. The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.

    D. The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.


    参考答案：A

  • 第2题：

    Examine the data of the EMPLOYEES table.EMPLOYEES (EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID)Which statement lists the ID, name, and salary of the employee, and the ID and name of the employee‘s manager, for all the employees who have a manager and earn more than 4000?（）

    A.

    B.

    C.

    D.

    E.


    参考答案：C

  • 第3题：

    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables:Which UPDATE statement is valid?()

    A.

    B.

    C.

    D.


    参考答案：A

  • 第4题：

    Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? ()

    A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

    B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

    F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


    参考答案：C, D, E

  • 第5题：

    Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?（）

    A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);

    B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

    C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

    D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

    E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

    F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;


    参考答案：B

  • 第6题：

    Click the Exhibit button and examine the data from the EMP table.The COMMISSION column shows the monthly commission earned by the employee.Which two tasks would require subqueries or joins in order to be performed in a single step? （）

    A.listing the employees who earn the same amount of commission as employee 3

    B.finding the total commission earned by the employees in department 10

    C.finding the number of employees who earn a commission that is higher than the average commission of the company

    D.listing the departments whose average commission is more than 600

    E.listing the employees who do not earn commission and who are working for department 20 in descending order of the employee ID

    F.listing the employees whose annual commission is more than 6000


    参考答案：A, C

  • 第7题：

    Click the Exhibit button to examine the data of the EMPLOYEES table. Evaluate this SQL statement:SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.employee_id "Mgr_id", m.emp_name "Manager"FROM employees e JOIN employees m ON (e.mgr_id = m.employee_id)AND e.salary > 4000;What is its output?（）

    A.A

    B.B

    C.C

    D.D

    E.E


    参考答案：A

  • 第8题：

    Click the Exhibit button to examine the data of the EMPLOYEES table.Which statement lists the ID, name, and salary of the employee, and the ID and name of the employee‘s manager, for all the employees who have a manager and earn more than 4000?（）

    A.SELECT employee_id "Emp_id", emp_name "Employee", salary, employee_id "Mgr_id", emp_name "Manager" FROM employees WHERE salary > 4000;

    B.SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.employee_id "Mgr_id", m.emp_name "Manager" FROM employees e JOIN employees m WHERE e.mgr_id = m.mgr_id AND e.salary > 4000;

    C.SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.employee_id "Mgr_id", m.emp_name "Manager" FROM employees e JOIN employees m ON (e.mgr_id = m.employee_id) AND e.salary > 4000;

    D.SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.mgr_id "Mgr_id", m.emp_name "Manager" FROM employees e SELF JOIN employees m WHERE e.mgr_id = m.employee_id AND e.salary > 4000;

    E.SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.mgr_id "Mgr_id" m.emp_name "Manager" FROM employees e JOIN employees m USING (e.employee_id = m.employee_id) AND e.salary > 4000;


    参考答案：C

  • 第9题：

    Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）

    • A、SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);
    • B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • C、SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • D、SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • E、SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);
    • F、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

    正确答案:C,D,E

  • 第10题：

    多选题
    Examine the data in the EMPLOYEES table: Which three subqueries work? （）
    A

    SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

    B

    SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    C

    SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    D

    SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    E

    SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

    F

    SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


    正确答案： D,E
    解析： 暂无解析

  • 第11题：

    单选题
    You added a PHONE_NUMBER column of NUMBER data type to an existing EMPLOYEES table. The EMPLOYEES table already contains records of 100 employees. Now, you want to enter the phone numbers of each of the 100 employees into the table. Some of the employees may not have a phone number available. Which data manipulation operation do you perform?（）
    A

    MERGE

    B

    INSERT

    C

    UPDATE

    D

    ADD

    E

    ENTER

    F

    You cannot enter the phone numbers for the existing employee records.


    正确答案： D
    解析： 暂无解析

  • 第12题：

    单选题
    Exhibit: Examine the data in the EMPLOYEES table. Examine the subquery: SELECT last_name FROM employees WHERE salary IN (SELECT MAX(salary) FROM employees GROUP BY department_id); Which statement is true?（）
    A

    The SELECT statement is syntactically accurate.

    B

    The SELECT statement does not work because there is no HAVING clause.

    C

    The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.

    D

    The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.


    正确答案： C
    解析： 暂无解析

  • 第13题：

    Examine the data in the EMPLOYEES table.On the EMPLOYEES table, EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID. The JOB_ID column is a NOT NULL column.Evaluate this DELETE statement:Why does the DELETE statement fail when you execute it?（）

    A. There is no row with dept_id 90 in the EMPLOYEES table.

    B. You cannot delete the JOB_ID column because it is a NOT NULL column.

    C. You cannot specify column names in the DELETE clause of the DELETE statement.

    D. You cannot delete the EMPLOYEE_ID column because it is the primary key of the table.


    参考答案：C

  • 第14题：

    Examine the structure if the EMPLOYEES and NEW EMPLOYEES tables:Which MERGE statement is valid?()

    A.

    B.

    C.

    D.


    参考答案：A

  • 第15题：

    Examine the data in the EMPLOYEES and DEPARTMENTS tables:Also examine the SQL statements that create the EMPLOYEES and DEPARTMENTS tables:On the EMPLOYEES table, EMPLOYEE_ID is the primary key.MGR_ID is the ID of managers and refers to the EMPLOYEE_ID.DEPT_ID is foreign key to DEPARTMENT_ID column of the DEPARTMENTS table.On the DEPARTMENTS table, DEPARTMENT_ID is the primary key.Examine this DELETE statement:What happens when you execute the DELETE statement?（）

    A. Only the row with department ID 40 is deleted in the DEPARTMENTS table.

    B. The statement fails because there are child records in the EMPLOYEES table with department ID 40.

    C. The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 110 and 106 are deleted from the EMPLOYEES table.

    D. The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 106 and 110 and the employees working under employee 110 are deleted from the EMPLOYEES table.

    E. The row with department ID 40 is deleted in the DEPARTMENTS table. Also all the rows in the EMPLOYEES table are deleted.

    F. The statement fails because there are no columns specifies in the DELETE clause of the DELETE statement.


    参考答案：B

  • 第16题：

    Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? ()

    A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);

    B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);

    C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);

    D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);

    E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);

    F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));


    参考答案：C, D, E

  • 第17题：

    Click the Exhibit button to examine the structures of the EMPLOYEES, DEPARTMENTS, and TAX tables.For which situation would you use a nonequijoin query?()

    A.to find the tax percentage for each of the employees

    B.to list the name, job_id, and manager name for all the employees

    C.to find the name, salary, and the department name of employees who are not working with Smith

    D.to find the number of employees working for the Administrative department and earning less than 4000

    E.to display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned


    参考答案：A

  • 第18题：

    Click the Exhibit button and examine the data in the EMPLOYEES table.Examine the subquery:SELECT last_nameFROM employeesWHERE salary IN (SELECT MAX(salary)FROM employeesGROUP BY department_id);Which statement is true?（）

    A.The SELECT statement is syntactically accurate.

    B.The SELECT statement does not work because there is no HAVING clause.

    C.The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.

    D.The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.


    参考答案：A

  • 第19题：

    Click the Exhibit button and examine the data from the ORDERS and CUSTOMERS tables.Evaluate the SQL statement:SELECT *FROM ordersWHERE cust_id = (SELECT cust_idFROM customersWHERE cust_name = ‘Smith‘);What is the result when the query is executed?（）

    A.A

    B.B

    C.C

    D.D

    E.E


    参考答案：A

  • 第20题：

    Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?（）

    • A、SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
    • B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • C、SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • D、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • E、SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
    • F、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

    正确答案:C,D,E

  • 第21题：

    单选题
    View the Exhibit and examine the details of the EMPLOYEES table.  The query was written to format the PHONE_NUMBER for the employees.   Which option would be the correct format in the output？（）
    A

     xxx-xxx-xxxx

    B

     （xxx） xxxxxxx

    C

     （xxx） xxx-xxxx

    D

     xxx-（xxx）-xxxx


    正确答案： C
    解析： 暂无解析

  • 第22题：

    单选题
    Examine the exhibit to view the parameters set in your parameter file. (Click the Exhibit(s) button.) You restart the instance. To what value will the MEMORY_MAX_TARGET parameter be set by default?（）
    A

    120M

    B

    320M

    C

    480M

    D

    600M


    正确答案： A
    解析： 暂无解析

  • 第23题：

    单选题
    Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）
    A

    SELECT last_name, department_name FROM employees NATURAL JOIN departments;

    B

    SELECT last_name, department_name FROM employees JOIN departments ;

    C

    SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);

    D

    SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

    E

    SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);

    F

    SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);


    正确答案： B
    解析： 暂无解析

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