() suggests that people should say the right thing to the right person with the right manner at the right place and in the right situation.A、SemanticsB、SyntacticsC、PragmaticsD、Appropriacy

题目

() suggests that people should say the right thing to the right person with the right manner at the right place and in the right situation.

A、Semantics

B、Syntactics

C、Pragmatics

D、Appropriacy


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更多“() suggests that people should say the right thing to the right person with the right ”相关问题
  • 第1题:

    以下语句中存在语法错误的是( )。

    A.char ss[6][20];ss[1]="right?";

    B.char ss[][20]={"right?"};

    C.char*ss[6];ss[1]="right?";

    D.char*ss[]={"right?"};


    正确答案:A
    解析:数组赋值时需要用{}表示出来,故选项A错误。

  • 第2题:

    设指针变量p指向双向链表中节点A,指针变量s指向被插入的节点X,则在节点A的后面插入节点X的操作序列为()

    A.p->right=s;s->left=p;p->right->left=s;s->right=p->right;
    B.p->right=s;p->right->left=s;s->left=p;s->right=p->right;
    C.s->left=p;s->right=p->right;p->right=s;p->right->left=s;
    D.s->left=p;s->right=p->right;p->right->left=s;p->right=s;

    答案:D
    解析:
    为了防止在插入节点时链表断裂,在修改指针时,需要先使s的后继指针指向p原来的后继节点,然后修改p的后继指针。

  • 第3题:

    设指针变量p指向双向链表中结点A,指针变量s指向被插入的结点X,则在结点A的后面插入结点X的操作序列为()

    A.p->right=s; s->left=p; p->right->left=s; s->right=p->right;

    B.s->left=p;s->right=p->right;p->right=s; p->right->left=s;

    C.p->right=s; p->right->left=s; s->left=p; s->right=p->right;

    D.s->left=p;s->right=p->right;p->right->left=s; p->right=s;


    D

  • 第4题:

    The careless driver was fined, so because he parked his car ( ) in front the ( ) police station.

    A、rightly/ rightly

    B、rightly/ right

    C、right/ rightly

    D、right/ right


    参考答案:A

  • 第5题:

    2、在循环双链表的p所指结点之后插入s所指结点的操作是()

    A.p->right=s;s->left=p;p->right->left=s;s->right=p->right;

    B.p->right=s;p->right->left=s;s->left=p;s->right=p->right;

    C.s->left=p;s->right=p->right;p->right=s;p->right->left=s;

    D.s->left=p;s->right=p->right; p->right->left=s;p->right=s;


    s->prior=p;s->next=p->next;p->next->prior=s;p->next=s;

  • 第6题:

    在循环双链表的p所指节点之后插入s所指节点的操作是

    A.p->right=s;s->left=p;p->right->left=s;s->right=p->right;

    B.s->left=p;s->right=p->right;p->right->left=s;p->right=s;

    C.s->left=p;s->right=p->right;p->right=s;p->right->left=s;

    D.p->right=s;p->right->left=s;s->left=p;s->right=p->right;


    s->prior=p;s->next=p->next;p->next->prior=s;p->next=s;