—— ________ ?—— I have a headache, a sore throat and I’m feeling rather weak.A.What are youB.What’s the matter with youC.How are you todayD.What can I do for you

题目

—— ________ ?

—— I have a headache, a sore throat and I’m feeling rather weak.

A.What are you

B.What’s the matter with you

C.How are you today

D.What can I do for you


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更多“—— ________ ?—— I have a headache, a sore throat and I’m feeling rather weak.A.What are ”相关问题
  • 第1题:

    A: Would you like to go to the cinema?

    B: I'd_____ not.

    A. prefer

    B. like

    C. rather


    参考答案:C

  • 第2题:

    有以下程序 vold soru(int a[], int n) { int i,i,t; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(a[i]<a[j]) { t=a[i]; a[i]=a[i]; a[j]=t; } } main() { int aa[10]={1,2,3,4,5,6,7,8,9,10),i; sore(aa+2, 5); for(i=0;i<10;i++) printf("%d,",aa[i]); printf("\n"); } 程序运行后的输出结果是

    A.1,2,3,4,5,6,7,8,9,10,

    B.1,2,7,6,3,4,5,8,9,10,

    C.1,2,7,6,5,4,3,8,9,10,

    D.1,2,9,8,7,6,5,4,3,10,


    正确答案:C
    解析:先看sort()函数,它没有返回值,有两个参数,一个int型数组和一个int型变量。在函数中是一个;重循环,外循环变量i从0递增到n-2,内循环变量j从i+l递增到n-1。内循环体是一条if语句“如果a[i]

  • 第3题:

    下面()仅输出m的大于1的最小因子。

    A.for (i =2; i<=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); break; }

    B.for (i =2; i<=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); continue; }

    C.for (i =2; i<=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); }

    D.i=2; while (m % i != 0) i++; printf("%d is 最小因子n", i);


    A

  • 第4题:

    —I'd met Smith several times before.—So (have) ( ) I.


    正确答案:had

  • 第5题:

    22、假设整型变量n,m,i已经声明和赋值,且大于n>2.有如下运算规则:如果n是素数,m=0;否则,m=n。如下程序中正确实现此运算的是?

    A.m=n; for(i=2;i<n;i++) if(n%i==0){ m=0;break; }

    B.m=0; for(i=2;i<n;i++) if(n%i==0){ m=n;break; }

    C.m=0; for(i=2;i<n;i++) if(n%i==0){ m=n;continue; }

    D.m=n; for(i=2;i<n;i++) if(n%i==0){ m=0;continue; }


    m=n; for(i=2;i if(n%i==0){ m=0;break; }

  • 第6题:

    下面()是正确的判断素数程序(m>1)。

    A.j=0; for (i =2; i<=m-1; i++) if (m % i != 0) j++; if(j==m-2) printf(“%d是素数n", m);

    B.j=0; for (i =2; i<=m-1; i++) if (m % i == 0) j++; if(j==0) printf(“%d是素数n", m);

    C.flag=0; for (i =2; i<=m-1; i++) if (m % i == 0) flag=1; if(flag==0) printf(“%d是素数n", m);

    D.for (i =2; i<=m-1; i++) if (m % i == 0) i=m+2; if(i==m+3) printf(“%d是素数n", m);


    D