Will you take the responsibility of chartering a ship.()

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Will you take the responsibility of chartering a ship.()

相似考题

1.The boy (take) to hospital at once after he fell off the tree.

2.营销数据库管理的基本法则RFM法则是()的缩写。A:Recency，Finance，MonetaryB:Responsibility，Finance，MoneyC:Responsibility，Frequency，MonetaryD:Recency，Frequency，Monetary

3.(b) Explain in the context of Flavours Fine Foods, what is meant by:(i) responsibility; (4 marks)

4.It is easy to ____ a machine ____ but difficult to put it together.A、tear…apartB、take …awayC、take …apartD、bring…away

更多“Will you take the responsibility of chartering a ship.() ”相关问题

  • 第1题：

    Wu Bin considered________ (take) part in the long jump．


    正确答案：
    43. taking

  • 第2题：

    I had ______ in my secretary; she would do the right thing.

    A、dependence

    B、confidence

    C、knowledge

    D、responsibility


    参考答案：B

  • 第3题：

    This 15 his obligation to take care of the child.

    A:right'
    B: nature
    C:work
    D:responsibility

    答案：D
    解析：
    照顾好孩子是他的责任。right“权利”，如：You have no right to search my home．你没有权利搜查我家。nature“天性”，如：It is her nature that she trusts people．她很信任他人，天性使然。work“工作”，如：He works for Ministry of Commerce．他在商务部工作。responsibility“责任”，如：Doctors have responsibility to look after their patients．医生有责任照顾好患者。只有responsibility意思上和obligation最接近。

  • 第4题：

    You can ______the seat belt ____ as soon as the light overhead goes off.

    A.turn…on

    B.take…off

    C.take…out

    D.pick…out


    正确答案：C

  • 第5题：

    38________

    A.ability

    B. Time

    C. courage

    D.responsibility


    正确答案：B

  • 第6题：

    1、利用艾拉托斯特尼筛法无穷素数列表primes （参见讲义第8章) 获得介于100000和200000之间素数的方法是

    A．take 200000 (take 100000 primes)

    B．take 100000 (take 200000 primes)

    C．take 100000 (drop 100000 primes)

    D．takeWhile (\x -> x <= 200000) (dropWhile (\x -> x <= 100000) primes)

    E．takeWhile (\x -> x <= 200000) (take 200000 primes)

    F．[x | x <- primes, x >100000, x < 200000]

    G．[x | x <- take 200000 primes, x >100000, x < 200000]


    Sieve(n，P)． 输入：正整数n． 输出：小于等于n的所有素数P． ①if n=1 then P← ，计算结束； ②P←{2}； ③a←2； ④if n=a then计算结束； ⑤b←min{a 2 ，n}； ⑥Q←{x|a＜x≤b}； ⑦for P中的每一个x ⑧for Q中的每一个y ⑨ then从Q中删去y； ⑩P←P∪Q； (11)a←b； (12)转④．

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