process(bytes);
BitUtils.process(bytes);
util.BitUtils.process(bytes);
SomeApp cannot use methods in BitUtils.
import util.BitUtils.*; process(bytes);
第1题:
A. the K1 SONET byte; the K2 SONET byte
B. the K2 SONET byte;the K1 SONET byte
C. transmitter switching;receiver detection
D. Line Overhead bytes;Path Overhead bytes
E. Path Overhead bytes;Line Overhead bytes
第2题:
A.Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.
B.Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.
C.Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.
D.Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.
E.Themaximumframesizethatcantraversethisinterfaceis1500bytes.
第3题:
What are disadvantages of Network Address Translation Transparency?()
第4题:
IS-IS的NET地址至少需要()bytes,其中,()bytes的(),()bytes的()和()bytes的(),最多为()bytes.
第5题:
Given classes defined in two different files: 1. package util; 2. public class BitUtils { 3. private static void process(byte[] b) { } 4. } 1. package app; 2. public class SomeApp { 3. public static void main(String[] args) { 4. byte[] bytes = new byte[256]; 5. // insert code here 6. } 7. } What is required at line 5 in class SomeApp to use the process method of BitUtils?()
第6题:
You work as an application developer at Certkiller .com. You are required to dynamically load assemblies into an application domain. You are using the Load method of the AppDomain class. What types of files can you this use method for?()
第7题:
Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.
Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.
Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.
Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.
Themaximumframesizethatcantraversethisinterfaceis1500bytes.
第8题:
the K1 SONET byte; the K2 SONET byte
the K2 SONET byte;the K1 SONET byte
transmitter switching;receiver detection
Line Overhead bytes;Path Overhead bytes
Path Overhead bytes;Line Overhead bytes
第9题:
process(bytes);
BitUtils.process(bytes);
app.BitUtils.process(bytes);
util.BitUtils.process(bytes);
import util.BitUtils. *; process(bytes);
SomeApp cannot use the process method in BitUtils.
第10题:
Library application files (.dll).
All assembly files, no matter what there file extensions are.
Application configuration files (.config).
Standalone application files (.exe).
第11题:
Employ path MTU discovery.
Set the MTU higher than 1500 bytes.
Turn off pre-fragmentation for IPSec.
Set the MTU value to 1400 bytes.
第12题:
4 bytes for both
4 bytes, and 8 bytes respectively
8 bytes for both
24 bytes for both
第13题:
Users of a site-to-site VPN are reporting performance problems. The VPN connection employs IPSec and GRE and traverses several Ethernet segments. The VPN packets are being fragmented as they traverse the links. What would be two methods to overcome this problem?()
A. Employ path MTU discovery.
B. Set the MTU higher than 1500 bytes.
C. Turn off pre-fragmentation for IPSec.
D. Set the MTU value to 1400 bytes.
第14题:
Users of a site-to-site VPN are reporting performance problems. The VPN connection employsIPSec and GRE and traverses several Ethernet segments. The VPN packets are being fragmented as they traverse the links. What would be two methods to overcome this problem?()
第15题:
UPSR protection switching is initiated by (), while BLSR is initiated by ().
第16题:
What are the header sizes for point-to-point and multi-point GRE(also known asmGRE) with tunnel key?()
第17题:
Given classes defined in two different files: 1. package util; 2. public class BitUtils { 3. public static void process(byte[]) { /* more code here */ } 4. } 1. package app; 2. public class SomeApp { 3. public static void main(String[] args) { 4. byte[] bytes = new byte[256]; 5. // insert code here 6. } 7. } What is required at line 5 in class SomeApp to use the process method of BitUtils?()
第18题:
You are developing a Windows Communication Foundation (WCF) service. You write a method named Submit that accepts messages of the type System.ServiceModel.Channels.Message. You need to process the body of the incoming messages multiple times in the method. Which two actions should you perform? (Each correct answer presents part of the solution. Choose two.)()
第19题:
process(bytes);
BitUtils.process(bytes);
util.BitUtils.process(bytes);
SomeApp cannot use methods in BitUtils.
import util.BitUtils.*; process(bytes);
第20题:
process(bytes);
BitUtils.process(bytes);
app.BitUtils.process(bytes);
util.BitUtils.process(bytes);
import util.BitUtils.*; process(bytes);
SomeApp cannot use the process method in BitUtils.
第21题:
Employ path MTU discovery.
Set the MTU higher than 1500 bytes.
Turn off pre-fragmentation for IPSec.
Set the MTU value to 1400 bytes.
第22题:
process(bytes);
BitUtils.process(bytes);
util.BitUtils.process(bytes);
SomeApp cannot use methods in BitUtils.
import util.BitUtils.*; process(bytes);
第23题:
process(bytes);
BitUtils.process(bytes);
app.BitUtils.process(bytes);
util.BitUtils.process(bytes);
importutil.BitUtils.*;process(bytes);
SomeApp cannot use the process method in BitUtils.
第24题:
There is no disadvantage.
It will add 16 bytes per packet of overhead(8 bytes UDP header, and 8 bytes of NON-IKE Marker).
It will add 36 bytes per packet of overhead (20 bytes of IP header, 8 bytes of UDP header, 8 bytes of NON-IKE Marker).
It will require that both crypto peers support this feature in the IOS version. Both crypto peers must also have this feature enabled.