第1题:
Taxi driver: Here you are, sir. Queens Hotel.
Passenger: How much is it?
Taxi driver: Three dollars and seventy-five cents.
Passenger: Here is four dollars. _____________.
A: It ’s not necessary to give me the coins
B: Don’t giv e me the rest
C: Keep the change
D: I give up the pocket money
第2题:
A.pained
B.hurt
C.hit
D.damaged
第3题:
阅读下列说明、图和C++代码,填补空缺。
[说明]
已知对某载客车辆(Car)进行类建模,如图12-2所示,其中类Engine表示发动机引擎,类Wheel表示车轮,类Body表示车身,类Driver表示司机,类Passenger表示乘客。
const int __________ =7; //定义最多载客数
const int MAX_WHEELS=5; //定义最多轮胎数
class Body{ //此处代码省略 ); //车身类
class Passenger{ //此处代码省略}; //乘客类
Class Wheel{ //此处代码省略}; //车轮类
Class Driver{ //司机类
public:
string name; //表示第几路公交车司机
Driver(string driverName):marne( __________ ){}; //构造函数
};
class Engine{ //引擎类
public:
string engineNo; //引擎编号
Engine(string engineNo){ __________ ->engineNo=engineNo; }
//构造函数
};
Class Car{ //汽车类
protected:
Engine *engine; Driver *driver; Body body;
Wheel *wheels[MAX_WHEELS]; Passenger *passengers[MAX_PASSENGERS];
public:
Car(Driver *driver)( //构造函数
this->driver=driver;
engine=new Engine("TX653 6型号引擎");
for(int index=0; index<MAX_WHEELS; index++){
wheels[index]=new Wheel( );
}
for(int index=0; index passengers[index]=NULL;
}
}
virtual -Car( ){ //析构函数
for (int index=0; index<MAX_WHEELS; index++)
delete wheels[index];
delete __________ ;
}
int getPassengerNumber( ){ //获取车上乘客数量
//此处代码省略
}
void getonpassenger(Passenger *apassenger ){
//乘客上车
//此处代码省略
}
void run( ){ //开车
if(driver==NULL){cout<< "司机尚未上车!"; return; }
//此处代码省略
}
};
void main( ){
Driver driver("第五路公交车司机");
Car car( __________ );
Passenger passengers[MAX_PASSENGERS];
for(int index=0; index<MAX_PASSENGERS; index++)
//乘客上车处理
car. getOnPasSenger(&passengers[index]);
car. run( );
}
第4题:
You ______ cross the road when the traffic lights are red. It’s dangerous.
A. needn’t B. may not C. mustn’t
第5题:
第6题:
第7题:
第8题:
第9题:
第10题:
a passenger can go anywhere without having to pay the driver
a passenger pays two US dollars for a taxi ride
a passenger can never be turned down by the taxi driver wherever he wants to go
a passenger needs to provide good faith demonstration before they leave without paying
第11题:
the driver can be
can the driver be.
the driver be
be the driver
第12题:
Device is disabled
Device conflict
No device driver found
Device has not been digitally signed
第13题:
The passenger ( ) to the driver to stop the bus and let him get off.
A、moved
B、mentioned
C、motioned
D、motivated
第14题:
阅读下列说明、图和Java代码,将应填入(n)处的字句写在对应栏内。
【说明】
已知对某载客车辆(Car)进行类建模,如图7-1所示,其中类Engine表示发动机引擎,类Wheel表示车轮,类Body表示车身,类Driver表示司机,类Passenger表示乘客。
【Java代码】
class Body{ //此处代码省略 ); //车身类
class Passenger{ //此处代码省略 )/ //乘客类
class Wheel{ //此处代码省略 ); //车轮类
class Driver{ //司机类
public String name; //表示第几路公交车司机
public Driver(String driverName){name = driverName/) //构造函数
};
class Engine{//引擎类
public String engineNo;//引擎编号
public Engine(String engineNo){this.engineNo=engineNo;)//构造函数
};
public class Car{//汽车类
static final int(1)=7; //定义最多载客数
static final int MAX WHEELS =5; //定义最多轮胎数
protected Engine engine;
protected Driver driver;
protected Body body=new Body();
protected Wheel[] wheels;
protected Passenger[]passengers;
public Car(Driver driver){ //构造函数
(2).driver=driver;
engine=new Engine("TX6536型号引擎");
wheels=new Wheel[MAX WHEELS];
passengers=new Passenger[MAX_PASSENGERS];
for(int index=0;index<MAX_WHEELS;index++){
wheels[index]=new Wheel();
}
for(int index=0;index<MAX_PASSENGERS;index++){
passengers[index]=null;
}
}
int getPassengerNumber(){//获取车上乘客数量
//此处代码省略
}
void getOnPassenger(Passenger aPassenger){//乘客上车
//此处代码省略
}
void run(){ //开车
if((3)){System.out.println("司机尚未上车!");return;}
//此处代码省略
}
public static void main(String args[]){
Driver driver=new Driver("第五路公交车司机");
Car car=new Car((4));
for (int index = 0 ; index < MAX_PASSENGERS; index ++)
car.getOnPassenger((5) Passenger());
car.run();
}
}
第15题:
试题五(共 15 分)
阅读下列说明、图和C++代码,将应填入 (n) 处的字句写在答题纸的对应栏内。
[说明]
已知对某载客车辆(Car)进行类建模,如图 5-1所示,其中类 Engine 表示发动机引擎,类 Wheel 表示车轮,类 Body 表示车身,类 Driver 表示司机,类 Passenger 表示乘客。
[C++代码]
const int (1) = 7; //定义最多载客数
const int MAX_WHEELS = 5; //定义最多轮胎数
class Body{ //此处代码省略 }; //车身类
class Passenger{ //此处代码省略 }; //乘客类
class Wheel{ //此处代码省略 }; //车轮类
class Driver{ //司机类
public:
string name; //表示第几路公交车司机
Driver(string driverName):name( (2) ){}; //构造函数
};
class Engine{ //引擎类
public:
string engineNo; //引擎编号
Engine(string engineNo){ (3) ->engineNo = engineNo; } //构造函数
};
class Car{ //汽车类
protected:
Engine * engine; Driver * driver; Body body;
Wheel * wheels[MAX_WHEELS]; Passenger * passengers[MAX_PASSENGERS];
public:
Car(Driver *driver){ //构造函数
this->driver = driver;
engine = new Engine("TX6536 型号引擎");
for (int index = 0; index < MAX_WHEELS; index++){
wheels[index] = new Wheel();
}
for (int index = 0; index < MAX_PASSENGERS; index++){
passengers[index] = NULL;
}
}
virtual ~Car(){ //析构函数
for (int index=0; index < MAX_WHEELS; index++)
delete wheels[index];
delete (4) ;
}
int getPassengerNumber(){ //获取车上乘客数量
//此处代码省略
}
void getOnPassenger(Passenger * aPassenger ){ //乘客上车
//此处代码省略
}
void run(){ //开车
if(driver == NULL){ cout << "司机尚未上车!"; return; }
//此处代码省略
}
};
void main(){
Driver driver("第五路公交车司机");
Car car( (5) );
Passenger passengers[MAX_PASSENGERS];
for (int index = 0 ; index < MAX_PASSENGERS; index ++) //乘客上车处理
car.getOnPassenger(&passengers[index]);
car.run();
}
第16题:
If an alien stowaway is discovered aboard your vessel,his name must be placed on the ______.
A.Alien Crew List
B.Crew List
C.Passenger List
D.separate Passenger List marked stowaways
第17题:
第18题:
第19题:
第20题:
第21题:
When using Device Manager, a red ‘X” indicates which of the following?()
第22题:
can
may
must
needn't
第23题:
develop sophisticated facilities on the interstate highways
provide passenger vehicle with a variety of services
optimize the highway capabilities
improve communication between driver and the traffic monitors