A、three times as much
B、as much three times
C、much as three times
D、as three times much
第1题:
Are you a member of the()?
I' m her brother.
A. house
B. household
C. home
第2题:
B 宽度优先(种子染色法)
5.关键路径
几个定义: 顶点1为源点,n为汇点。
a. 顶点事件最早发生时间Ve[j], Ve [j] = max{ Ve [j] + w[I,j] },其中Ve (1) = 0;
b. 顶点事件最晚发生时间 Vl[j], Vl [j] = min{ Vl[j] – w[I,j] },其中 Vl(n) = Ve(n);
c. 边活动最早开始时间 Ee[I], 若边I由<j,k>表示,则Ee[I] = Ve[j];
d. 边活动最晚开始时间 El[I], 若边I由<j,k>表示,则El[I] = Vl[k] – w[j,k];
若 Ee[j] = El[j] ,则活动j为关键活动,由关键活动组成的路径为关键路径。
求解方法:
a. 从源点起topsort,判断是否有回路并计算Ve;
第3题:
—Why didn't you go to the cinema yesterday?
—I______, but my daughter returned from America the moment I was leaving.
A. did
B. would
C. was going to
D. had
16.答案为C “你昨晚为什么不去电影院?”“我本打算去,但是我正要离开时我女儿从美国回来了。”该句用过去将来时表示过去打算做某事。
第4题:
I've _____ these lines again and again but I still keep forgetting them.
A. gone off
B. gone about
C. gone over
D. gone through
第5题:
b)
main()
{
union{ /*定义一个联合*/
int i;
struct{ /*在联合中定义一个结构*/
char first;
char second;
}half;
}number;
number.i=0x4241; /*联合成员赋值*/
printf("%c%c\n", number.half.first,
mumber.half.second);
number.half.first='a'; /*联合中结构成员赋值
*/
number.half.second='b';
printf("%x\n", number.i);
getch();
}
AB (0x41 对应'A',是低位;Ox42 对应'B',
是高位)6261 (number.i 和number.half 共用一块地址空
间)
第6题: