43 Which of the following networking methods allows us to show that the last 10% of one element cannot be completed until 62% of a previous element has been completed?A. PERTB. ADMC. PDMD. All of the above.E. A and C only.

题目

43 Which of the following networking methods allows us to show that the last 10% of one element cannot be completed until 62% of a previous element has been completed?

A. PERT

B. ADM

C. PDM

D. All of the above.

E. A and C only.

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更多“43Which of the following networking methods allows us to show that the last 10% of one ele ”相关问题

  • 第1题：

    YouareevaluatingthedeploymentofaHyper-VhostnamedHost1thatwillhost10VMs.EachVMwillhavethefollowingconfigurations：-10GBofmemory-Twovirtualprocessors-One300-gigabitfixedVHD-TwovirtualnetworkadaptersYouneedtorecommendchangestothestandardserverbuildtosupporttheplanneddeployment.Whichhardwarecomponentsshouldbechanged？（）

    A.processor

    B.storage

    C.memory

    D.networking


    参考答案：C

  • 第2题：

    7、已知last指向单向简单链表的尾结点，将s所指结点加在表尾，正确的操作是____。

    A．s-＞next=s,last=s,last-＞next=NULL;

    B．last-＞next=s,s-＞next=NULL,last=s;

    C．s-＞next=NULL, last-＞next=s, s=last;

    D．s-＞next=last, last-＞next=NULL,last=s;


    s-＞next=NULL, last-＞next=s, s=last;

  • 第3题：

    已知last指向单向简单链表的尾结点，将s所指结点加在表尾，正确的操作是____。

    A．s-＞next=s,last=s,last-＞next=NULL;

    B．last-＞next=s,s-＞next=NULL,last=s;

    C．s-＞next=NULL, last-＞next=s, s=last;

    D．s-＞next=last, last-＞next=NULL,last=s;


    B

  • 第4题：

    已知last指向单向简单链表的尾结点，将s所指结点加在表尾，不正确的操作是____。

    A．last-＞next=s,last=s,last-＞next=NULL;

    B．last-＞next=s,s-＞next=NULL,last=s;

    C．s-＞next=NULL, last-＞next=s, s=last;

    D．s-＞next=NULL, last-＞next=s,last=s;


    s-＞next=NULL, last-＞next=s, s=last;

  • 第5题：

    已知last指向单向简单链表的尾结点，将s所指结点插入在表尾，正确的操作是____。

    A．s-＞next=s,last=s,last-＞next=NULL;

    B．last-＞next=s,s-＞next=NULL,last=s;

    C．s-＞next=NULL, last-＞next=s, s=last;

    D．s-＞next=last, last-＞next=NULL,last=s;


    B

  • 第6题：

    已知last指向单向简单链表的尾结点，将s所指结点加在表尾，不正确的操作是____。

    A．s-＞next=NULL, last-＞next=s,last=s;

    B．s-＞next=NULL, last-＞next=s, s=last;

    C．last-＞next=s,s-＞next=NULL,last=s;

    D．last-＞next=s,last=s,last-＞next=NULL;


    B

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