更多“Hardly_____his work when the telephone rang. ”相关问题
  • 第1题:

    10、BookStore数据库中有客户表Customer(CustomerCode, Name, Sex, Hometown, Email, Telephone, LoginDate, Password) 查询Customer表中所有客户的信息,SQL语句: SELECT ________ FROM Customer

    A.*#B.CustomerCode, Name, Hometown, Sex, Email, Telephone, LoginTime, PassWord#C.CustomerCode, Hometown, Telephone, Name, Sex, Email, LoginTime, PassWord#D.CustomerCode ~ PassWord
    LEFT(Name,1)= '刘' OR LEFT(Name,1)= '杨';Name LIKE '刘%' OR Name LIKE '杨%';Name LIKE '[刘,杨]%'

  • 第2题:

    BookStore数据库中有客户表Customer(CustomerCode, Name, Sex, Hometown, Email, Telephone, LoginDate, Password) 查询Customer表中所有客户的信息,SQL语句: SELECT ________ FROM Customer

    A.*#B.CustomerCode, Name, Hometown, Sex, Email, Telephone, LoginTime, PassWord#C.CustomerCode, Hometown, Telephone, Name, Sex, Email, LoginTime, PassWord#D.CustomerCode ~ PassWord
    *;CustomerCode,Name,Hometown,Sex,Email,Telephone,LoginTime,PassWord;CustomerCode,Hometown,Telephone,Name,Sex,Email,LoginTime,PassWord

  • 第3题:

    2、若有以下说明和语句,则引用方式不正确的是? struct worker{ int no; char *name; }work, *p=&work;

    A.work.no

    B.(*p).no

    C.p->no

    D.work->no


    work->no

  • 第4题:

    BookStore数据库中有客户表Customer(CustomerCode, Name, Sex, Hometown, Email, Telephone, LoginDate, Password) 查询Customer表中所有客户的信息,要求显示CustomerCode、Name、Hometown和Telephone字段信息。SQL语句: SELECT _________ FROM Customer

    A.*

    B.ALL

    C.CustomerCode、Name、Hometown、Telephone

    D.CustomerCode,Name,Hometown,Telephone


    D

  • 第5题:

    【多选题】BookStore数据库中有客户表Customer(CustomerCode, Name, Sex, Hometown, Email, Telephone, LoginDate, Password) 查询Customer表中所有客户的信息,SQL语句: SELECT ________ FROM Customer

    A.*#B.CustomerCode, Name, Hometown, Sex, Email, Telephone, LoginTime, PassWord#C.CustomerCode, Hometown, Telephone, Name, Sex, Email, LoginTime, PassWord#D.CustomerCode ~ PassWord
    INSERT INTO Publisher VALUES(‘66’,’群众出版社‘,’0321-76584391’)

  • 第6题:

    若有以下说明和语句,则引用方式不正确的是? struct worker{ int no; char *name; }work, *p=&work;

    A.work.no

    B.(*p).no

    C.p->no

    D.work->no


    D