● The metric assigned to each network depends on the type of protocol. Some simple protocol, like RIP, treats each network as equals. The （71） of passing through each network is the same; it is one （72） count. So if a packet passes through 10 network to r

题目

● The metric assigned to each network depends on the type of protocol. Some simple protocol, like RIP, treats each network as equals. The （71） of passing through each network is the same; it is one （72） count. So if a packet passes through 10 network to reach the destination, the total cost is 10 hop counts. Other protocols, such as OSPF, allow the administrator to assign a cost for passing through a network based on the type of service required. A （73） through a network can have different costs (metrics). For example, if maximum （74） is the desired type of service, a satellite link has a lower metric than a fiber-optic line. On the other hand, if minimum （75） is the desired type of service, a fiber-optic line has a lower metric than a satellite line. OSPF allow each router to have several routing table based on the required type of service.

（71）

A. number

B. connection

C. diagram

D. cost

（72）

A. process

B. hop

C. route

D. flow

（73）

A. flow

B. window

C. route

D. cost

（74）

A. packet

B. throughput

C. error

D. number

（75）

A. delay

B. stream

C. packet

D. cost

相似考题

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更多“● The metric assigned to each network depends on the type of protocol. Some simple protoco ”相关问题

  • 第1题：

    While trying to diagnose a routing problem in the network, you issue RIP debugging as displayed below:RtrAdebug ip ripRip protocol debugging is onRtrA1d05h: RIP: sending v1 update to 255.255.255.255 via FastEthernet0/0 (172.16.1.1)1d05h: RIP: build update entries1d05h: network 10.0.0.0 metric 11d05h: network 192.168.1.0 metric 21d05h: RIP: sending v1 update to 255.255.255.255 via Serial0/0 (10.0.8.1)1d05h: RIP: build update entries1d05h: network 172.16.0.0 metric 1RtrA1d05h: RIP: received v1 update from 10.0.15.2 on Serial0/01d05h: 192.168.1.0 in 1 hops1d05h: 192.168.0 in 16 hops (inaccessible)Based on the output of the above exhibit, which two of the following statements are true?（）

    A. A ping to 10.0.15.2 will be successful.

    B. RtrA has three interfaces that will take part in the RIP process.

    C. There are at least two routers participating in the RIP process.

    D. A ping to 192.168.168.2 will be successful.


    参考答案：A, C

  • 第2题：

    一条router－LSA可以描述多条连接,每条连接由Link ID,Data,Type和Metirc描述,下面关于Link ID,Data,Type和Metric的讨论错误的是()

    A.Type表示连接的类型

    B.Link ID表示此连接的本地标识，不同的链接类型Link ID表示的意义也不相同

    C.Data用于描述此连接的附加信息，不同的连接类型所描述的信息也不同

    D.Metric描述此连接的开销


    参考答案：B

  • 第3题：

    1、现在需要对xml文档中所有的chapter元素排序后再利用for-each进行循环，要求排序依据为chapter下名为“no”的子元素，且按数值类型进行排序。能实现该功能的选项为（）。

    A.＜for-each select="//chapter"＞ ＜sort data-type="number" select="//no" /＞ ＜/for-each＞###SXB###B.＜for-each select="//chapter"＞ ＜sort data-type="number" select="/no" /＞ ＜/for-each＞###SXB###C.＜for-each select="/chapter"＞ ＜sort data-type="number" select="no" /＞ ＜/for-each＞###SXB###D.＜for-each select="
    正确的格式；格式正确

  • 第4题：

    Followingticketconsistsofaproblemdescriptionandexistingconfigurationonthedevice.

    Figure1

    Figure2

    TroubleTicketStatement

    Client1isnotabletoreachtheWebServer.InitialtroubleshootingshowsthatDSW1canpingtheFa0/1interfaceofR4butnotthes0/0/0/0.34interface.

    ConfigurationonDSW1

    routereigrp10

    network10.1.4.40.0.0.0

    network10.2.1.10.0.0.0

    network10.2.4.130.0.0.0

    noauto-summary

    ConfigurationonDSW2

    routereigrp10

    network10.1.4.80.0.0.0

    network10.2.2.10.0.0.0

    network10.2.4.140.0.0.0

    noauto-summary

    ConfigurationonR4

    routereigrp10

    network10.1.4.50.0.0.0

    noauto-summary

    redistributeospf1metric1001025511500route-mapEIGRP_to_OSPF!

    routerospf1

    network10.1.1.80.0.0.0area34

    redistributeeigrp10subnets!

    route-mapEIGRP→OSPF

    matchipaddress1!

    access-list1permit10.0.0.00.255.255.255

    access-list1permit209.0.0.00.255.255.255

    Whatisthesolutionofthefaultcondition？（）


    参考答案：B

  • 第5题：

    有关 Assigned的说法哪个是正确的？（ ）

    A.其他三项都不对

    B.Assigned的作用是判断一个对象是否为 Nil，如果是Nil，返回 True，如果不是Nil，返回 False

    C.Assigned的参数可以是对象或者方法，或者是一个指针

    D.Assigned的作用是判断 Assign过程是否已经完成。


    正确答案：C

  • 第6题：

    现在需要对xml文档中所有的chapter元素排序后再利用for-each进行循环，要求排序依据为chapter下名为“no”的子元素，且按数值类型进行排序。能实现该功能的选项为（）。

    A．＜for-each select="//chapter"＞ ＜sort data-type="number" select="//no" /＞ ＜/for-each＞

    B．＜for-each select="//chapter"＞ ＜sort data-type="number" select="/no" /＞ ＜/for-each＞

    C．＜for-each select="/chapter"＞ ＜sort data-type="number" select="no" /＞ ＜/for-each＞

    D．＜for-each select="//chapter"＞ ＜sort data-type="number" select="no" /＞ ＜/for-each＞


    结构

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