●In the following essay，each blank has four choices．Choose the most suitable one from the four choices and write down in the answer sheet．Open Shortest Path First(OSPF)is a (66) routing algorithm that (67) work done on the OSI IS-IS intradomain routing pr

题目

●In the following essay，each blank has four choices．Choose the most suitable one from the four choices and write down in the answer sheet．

Open Shortest Path First(OSPF)is a (66) routing algorithm that (67) work done on the OSI IS-IS intradomain routing protocol．This routing，as compared to distance-vector routing，requires (68) processing power．The Dijkstra algorithm is used to calculate (69) OSPF routing table updates only take place when necessary， (70) at regular intervals．

(66) A．distance-vector

B．link-state

C．flow-based

D．selective flooding

(67) A．derived from

B．deviated from

C．was derived from

D．was deviated from

(68) A．more

B．less

C．same

D．most

(69) A．routes

B．road

C．distance

D．cost

(70) A．but rather

B．rather too

C．rather than

D．rather that

相似考题

1.How many generators does the shuttle carry?A．One.B．Two.C．Three.D．Four.

2.From the passage, how many places have the name Valencia?A. One.B. Two.C. Three.D. Four.

3.下列语句能给数组赋值而不使用for循环的是A．myArray{[1]="One";[2]="Two";[3]="Three";}B．String s[5]=new String[]{"Zero", "One", "Two", "There", "Four"};C．String s[]=new String[]{"Zero", "One", "Two", "There", "Four"};D．String s[]=new String[]=|"Zero", "One", "Two", "There", "Four"};

4.下列程序的运行结果是( )。 SET EXACT ON s="ni"+SPACE(2) IF s="ni" IF s="ni" ? "one" ELSE ? "two" ENDIF ELSE IF s="ni" ? "three" ELSE ? "four" ENDIF ENDIF RETURNA．oneB．twoC．threeD．four

更多“●In the following essay,each blank has four choices.Choose the most suitable one from the ”相关问题

  • 第1题：

    How many approaches are mentioned to define a narrative?

    A．One.

    B．Two.

    C．Three.

    D．Four.


    正确答案：C
    解析：细节理解题。由文章第二段中“Another”、“A third”可知定义故事的方法共有三种。

  • 第2题：

    下列程序的运行结果是（ ）。 SET EXACT ON s="ni"+SPACE(2) IF S=”ni” IF S=”ni” ?"one" ELSE ?"two" END IF ELSE IF S="ni" ?"three" ELSE ?"four" END IF END IF RETURN

    A.one

    B.two

    C.three

    D.four


    正确答案：C
    C。【解析】用==比较两个字符串时，当两个字符串完圣相同时，运算结果是逻辑真．T．。用=比较两个字符串时，运算结果与SETEXACTONIOFF的设置有关：0N先在较短的字符串的尾部加上若干个空格，使两个字符串的长度相等，然后进行精确比较；当处于0FF状态时，只要右边字符串与左边字符串的前面部分内容相匹配，即可得到逻辑真．T．。所以本题运行结果为three。

  • 第3题：

    How many morphemes does the word "impossible" consist of?

    A．One.
    B．Two.
    C．Three.
    D．Four.

    答案：C
    解析：
    考查词素知识。impossible这个单词包含三个语素，分别是前缀im-，词根possi和后缀-ble。故选C。

  • 第4题：

    下列语句能给数组赋值，而不使用for循环的是

    A．myArray{[1]="One"；[2]="Two"；[3]="Three"；}

    B．String s[5]=new String[] {"Zero","One","Two","Three","Four"}；

    C．String s[]=new String[] {"Zero","One","Two","Three","Four"}；

    D．String s[]=new String[]= {"Zero","One","Two","Three","Four"}；


    正确答案：C
    解析：字符串数组赋初值的方法有两种，一种是如选项C一样初始化。另外一种是先为每个数组元素分配引用空间，再为每个数组元素分配空间并赋初值。例如还可做如下赋值：
      string s[]=new String[5]；
      s[0]="Zero"；
      s[1]="One"；
      s[2]="Two"；
      s[3]="Three"；
      s[4]="Four"；

  • 第5题：

    （ 14 ）下列程序的运行结果是

    SET EXACT ON

    s="ni"+SPACE(2)

    IF s=="ni"

    IF s="ni"

    ? "one"

    ELSE

    ? "two"

    ENDIF

    ELSE

    IF s="ni"

    ? "three"

    ELSE

    ? "four"

    ENDIF

    ENDIF

    RETURN

    A) one

    B) two

    C)three

    D)four


    正确答案：C

  • 第6题：

    下列给字符串二维数组进行赋值的语句中，错误的是（）。

    A．String s[ ] [ ] = new String [ ] [ ] { { “One “ , “ Two “ }, { “ Three “ , “ Four “ } } ;

    B．String s[ ] [ ] = { { “ One “ , “Two “},{ “ Three “ , “ Four “ } } ;

    C．String s[ ] [ ] = new String [ ] [ ] { { “Zero”} , { “ One ” , “Two” , “ Three” , “ Four” } } ;

    D．String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;


    String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;

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