An instruction is made up of operations that (1) the function to be performed and operands that represent the data to be operated on. For example, if an instruction is to perform. the operation of (2) two numbers,it must know (3) the two numbers are. The

题目

An instruction is made up of operations that (1) the function to be performed and operands that represent the data to be operated on. For example, if an instruction is to perform. the operation of (2) two numbers,it must know (3) the two numbers are. The processor's job is to.(4) instructions and operands from memory and to perform. each operation. Having done that, it signals memory to send it (5) instruction.

A.skip

B.smile

C.smoke

D.specify


相似考题
更多“An instruction is made up of operations that (1) the function to be performed and operands ”相关问题
  • 第1题:

    refers to the parts of the computer that you can see and touch.

    A.Software

    B.Hardware

    C.Hardship

    D.Instruction


    正确答案:B
    解析:硬件是计算机的组成部分,你可以看见和触摸它。

  • 第2题:

    对于典型的MIPS五级流水线处理器(不前递),下面这段代码中,哪条指令会遇到数据冒险? instruction 1: add $1, $2, $3 instruction 2: sw $2, 0($1) instruction 3: lw $1, 4($2) instruction 4: add $2, $2, $1

    A.instruction 2

    B.instruction 4

    C.instruction 1

    D.instruction 3


    lw

  • 第3题:

    在选择汽车最小传动比时,为了追求燃油经济性,哪种设计方式最好:

    A.uamax/uP > 1

    B.uamax/uP = 1

    C.uamax/uP < 1

    D.uamax/uP = 0


    u amax / u P < 1

  • 第4题:

    Though Confucius has long gone,his powerful ideas undoubtedly__________Chinese soci-ety and tradition.

    A.shaped
    B.formed
    C.1aid
    D.made

    答案:A
    解析:
    shaped意为“塑造,决定……的形成,to have animportantinfluence onthewaythat sb/sth-develops决定……的形成;影响……的发展”。formed意为“使形成,to have an influence on the way that sth-develops对……的发展有影响”;laid意为“摆放,提出,提议”;made意为“制造,制作”。从整体来考虑,A项更符合题意和情境。

  • 第5题:

    1、在选择汽车最小传动比时,为了追求燃油经济性,哪种设计方式最好:

    A.uamax/uP > 1

    B.uamax/uP = 1

    C.uamax/uP < 1

    D.uamax/uP = 0


    u amax / u P < 1

  • 第6题:

    在选择汽车最小传动比时,为了追求燃油经济性,哪种设计方式最好:()

    A.uamax/uP > 1

    B.uamax/uP = 1

    C.uamax/uP < 1

    D.uamax/uP = 0


    u amax / u P < 1