One attribute of the stack is(72).A．FIFO( First In First Out)B．LIFO( Last In First Out)C．queueD．built into their circuitry

题目

One attribute of the stack is(72).

A．FIFO( First In First Out)

B．LIFO( Last In First Out)

C．queue

D．built into their circuitry

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1.PublicclassHoltextendsThread{PrivateStringsThreadName；Publicstaticvoidmain（Stringargv[]）{Holth=newHolt（）；h.go（）；Holt（）{}；Holt（Strings）{sThreadName=s；PublicStringgetThreadName（）{returnsThreadName；}}Publicvoidgo（）{Hotfirst=newHot（"first"）；first.start（）；Hotsecond=newHot（"second"）；second.start（）；}Publicvoidstart（）{For（inti=0；i<2；i++）{System.out.print（getThreadName（）+i）；Try{Thread.sleep（100）；}catch（Exceptione）{System.out.print（e.getMessage（））；}}}}当编译运行上面代码时，将会出现（）A.编译时错误B.输出first0，second0，first0，second1C.输出first0，first1，second10，second1D.运行时错误

2.A(71)is a data type whose major attributes are determined by the roles governing the insertion and deletion of its elements. The only element that can be deleted or removed is the one that was inserted most(72). Such a structure is said to have a last-in/first-out(LIFO)behavior, or protocol.A．stackB．queuesC．pointerD．record

3.A(71) is a data type whose major attributes are determined by the rules governing the insertion and deletion of its elements. The only element that can be deleted or removed is the one that was inserted most(72). Such a structure is said to have a last-in/first-out (LIFO) behavior, or protocol.A．stackB．queuesC．pointerD．record

4.Examine the structure of the EMPLOYEES table:Column name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyLAST_NAME VARCNAR2(30)FIRST_NAME VARCNAR2(30)JOB_ID NUMBERSAL NUMBERMGR_ID NUMBER References EMPLOYEE_ID column DEPARTMENT_ID NUMBERYou need to create an index called NAME_IDX on the first name and last name fields of the EMPLOYEES table. Which SQL statement would you use to perform this task? （）A. CREATE INDEX NAME _IDX (first_name, last_name);B. CREATE INDEX NAME _IDX (first_name, AND last_name)C. CREATE INDEX NAME_IDX ON (First_name, last_name);D. CREATE INDEX NAME_IDX ON employees (First_name, AND last_name);E. CREATE INDEX NAME_IDX ON employees (First_name, last_name);F. CREATE INDEX NAME_IDX FOR employees (First_name, last_name);

更多“One attribute of the stack is(72).A.FIFO( First In First Out)B.LIFO( Last In First Out)C.q ”相关问题

  • 第1题：

    Whatarethethreemodelsofqualityofservice(QoS)inanetwork?()

    A.ResourceReservationProtocol（RSVP）

    B.first-in，first-out（FIFO）

    C.best-effort

    D.CBWFQ

    E.IntServ

    F.DiffServ


    参考答案：C, E, F

  • 第2题：

    数组q[M]存储一个循环队，first和last分别是首尾指针。如果使元素x出队操作的语句为“first=（first+1)%m, x=q[first];”。那么元素x进队的语句是_____。

    A．last=(last+1)%m,q[last]=x;

    B．x=q[last], last =(last+1)%m;

    C．q[last+1]=x;

    D．q[(last+1)%m]=x;


    (last- first+M)%M

  • 第3题：

    11、数组q[M]存储一个循环队，first和last分别是首尾指针。如果使元素x出队操作的语句为“first=（first+1)%m, x=q[first];”。那么元素x进队的语句是_____。

    A．last=(last+1)%m,q[last]=x;

    B．x=q[last], last =(last+1)%m;

    C．q[last+1]=x;

    D．q[(last+1)%m]=x;


    (last+1)%m= =first

  • 第4题：

    15、数组q[M]存储一个循环队，first和last分别是首尾指针。当前队中元素个数为_____。

    A．(last- first+M)%M

    B．last-first+1

    C．last-first-1

    D．last-first


    (last+1)%m= =first

  • 第5题：

    数组q[M]存储一个循环队，first和last分别是首尾指针。当前队中元素个数为_____。

    A．(last- first+M)%M

    B．last-first+1

    C．last-first-1

    D．last-first


    (last- first+M)%M

  • 第6题：

    1、数组q[M]存储一个循环队，first和last分别是首尾指针。当前队中元素个数为_____。

    A．(last- first+M)%M

    B．last-first+1

    C．last-first-1

    D．last-first


    4和0

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