● (66) is a channel's capacity which directly reflects the data transfer rate of the channel. (67) functions in a NetWare network which is used to define addressing schemes. (68) is a network layer device that suports multiple LAN interfaces and segments LANs into smaller collision and broadcast domains. (69) 。is the popular LAN develped under the direction of the IEEE 802.3. (70) is a device which enables digital microcomputers to communicate across analog telephone lines.
(66) A.The volume
B.The bandwidth
C.The noise
D.The delay
(67) A.NetBEUI
B.IP
C.IPX
D.NCP
(68) A.The repeater
B.The hub
C.The bridge
D.The router
(69) A.Token Ring
B.Token Bus
C.Ethernet
D.FEEI
(70) A.The repeater
B.The modem
C.The hub
D.The printer
第1题:
() .is a term for data sets that are so large or complex that traditional data processing applications are inadequate Challenges include analysis, capture, data ?curation, search, sharing, storage,transfer,visualization, querying, updating and information privacy.
A.Data market'
B.Data warehouse
C.Big data
D.BI
第2题:
Refertotheexhibit.Asanetworkadministrator,youhaveconfiguredadual-rate,dual-bucketpolicerinaccordancewithRFC2698ontheserialinterfaceofyourouter,connectingtoyourprovider.TheSLAwithyourproviderstatesthatyoushouldonlysendAF31(limitedto150kb/s),AF32(limitedto50kb/s)andAF33(besteffort).YourserviceproviderclaimsyouarenotconformingtotheSLA.Whichtwothingsarewrongwiththisconfiguration?()
A.Theconfigurationofaservicepolicyonhalf-duplexEthernetinterfacesisnotsupported.
B.Theclassclass-defaultsub-commandofthepolicy-maplimitcommandshouldbesettotheDSCPdefault.
C.Theviolateactioniswrong.
D.ThispolicerconfigurationisnotimplementingRFC2698dual-bucket,dual-rate.
E.Thepolicerisconfiguredinthewrongclass.
第3题:
第4题:
A.channel-groupautomodeon
B.channel-groupautomodeactive
C.channel-groupautomodeonsub-groupcdp
D.channel-groupautomodeonsub-groupmanual
E.channel-groupautomodeonmac-pinning
第5题:
A.67
B.68
C.64
D.65
第6题:
7、一个顺序栈S,其栈顶指针为top,则将元素e入栈的操作是()。
A.S.data[top]=e;S.top++;
B.S.top++;S.data[top]=e;
C.S.data[top]=e;
D.S.top=e;