Hello, ( )Franco Rossi speaking. Can I speak to Polly Williams?A. this isB. he isC. I am

题目

Hello, ( )Franco Rossi speaking. Can I speak to Polly Williams?

A. this is

B. he is

C. I am

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参考答案和解析
答案：A
更多“Hello, ( )Franco Rossi speaking. Can I speak to Polly Williams?A. this isB. he isC. I ”相关问题

  • 第1题：

    A:( ), Polly? B:I'd like a glass of wine, thank you.

    A. Do you want

    B. What would you like

    C. What you like


    正确答案：B

  • 第2题：

    Nicholas: Hello. May I speak to Tom?

    Tom: ______

    A、Sorry, the number is engaged. Will you hold?

    B、Hello. Who're you, please?

    C、Hello. Thank you for calling.

    D、Yes, speaking.


    参考答案：D

  • 第3题：

    3． —Hello !

    —________

    A．I'm Alice

    B．Thank you

    C．Fine

    D．Hello


    正确答案：D
    3．D[解析】用Hello问好时，前后保持一致，故选 D。

  • 第4题：

    I’d love to have a break, but I can't () the time now.

    A.spare

    B.spend

    C.speak


    正确答案：A

  • 第5题：

    下列程序执行后的输出结果是( )。 void funcl(int i); void func2(int i); char st[]="hello,friend!"; void funcl(int i) { printf("%C",st[i]); if(i＜3) { i+=2；func2(i); ) } void func2(int i) {printf("%c",st[i]); if(i＜3) { i+=2；func1(i); } } main() {int i=0;funcl(i);printf("\n"); )

    A．hlm

    B．hlo

    C．hello

    D．he1


    正确答案：B
    解析：本题定义了两个很相似的子函数互相调用，子函数首先输出st[i]，然后判断i是否小于3，是的话就让i增2后调用另一个子函数。在主函数中只调用了一次funcl(0)，funcl()输出st[0]，然后调用func2(2)，func2()输出st[2]，又调用func1(4)，此时i不小于3，所以funcl()只输出st[4]就返回了。故最终输结果为h1o，正确答案为B。

  • 第6题：

    "May I speak to your manager Mr. Williams at five o′clock tonight?"
    "I′m sorry. Mr. Williams ___________ to a conference long before then."

    A.have gone
    B.would have gone
    C.had gone
    D.will have gone

    答案：D
    解析：
    考查时态。then指代at five o’clock，由语境可知是将来时间。根据句中的时间状语at five0’clocktonight可知是将来发生的动作，再根据long before then(then指代five o’clock)可知用将来完成时。表示将来某时之前或某动作之前已经完成的动作。句意为“——我可以在今晚五点钟跟你们经理威廉姆斯先生通话吗?——很抱歉，他那时就早已经去开会了。”故选D。

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