The way to find a person with eating disorders _____.［A］ focuses on hidden symptoms［B］ varies with type of the condition［C］ is oriented at the victim’s response［D］ remains perplexing despite efforts made

题目

The way to find a person with eating disorders _____.

［A］ focuses on hidden symptoms

［B］ varies with type of the condition

［C］ is oriented at the victim’s response

［D］ remains perplexing despite efforts made

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4.18．A． makingB． stealingC． refusingD． eating

更多“The way to find a person with eating disorders _____.[A] focuses on hidden symptoms ”相关问题

  • 第1题：

    【C4】

    A．signs

    B．defects

    C．diseases

    D．symptoms


    正确答案：D
    本句可译为：“因跨越时区而导致的不适症状通常会持续数天。”D项symptoms“症状”最符合原文。首先，这种不适并不属于疾病的范畴，因此C项可以排除。A项signs意为“标志，迹象，征兆”。例如：Therearenosignsoflifeaboutthehouse．(这所房子没有住人的迹象。)B项defects通常指事物“固有的、先天的缺陷”。

  • 第2题：

    10．

    A． eat

    B． eats

    C． to eat

    D． eating


    正确答案：C
    10．C【解析】want to do sth．想要做某事。

  • 第3题：

    Person类可能的拷贝构造函数格式为：

    A．Person(){}

    B．Person(Person *p){}

    C．Person(Person &p){}

    D．Person(Person p){}


    Person(const Person& p);

  • 第4题：

    According to RFC 2328, what is the stateful order in which an OSPF router transitions to a full adjacency with a neighbor router?()

    A. Down, Init, 2 - Way, Exstart, Exchange, Loading, and Full

    B. Down, Init, 2 - Wa y, Exchange, Exstart, Loading, and Full

    C. Down, 2 - Way, Init, Loading, Exstart, Exchange, and Full

    D. Down, 2 - Way, Init, Exchange, Exstart, Loading, and Full

    E. Down, Init, 2 - Way, Loading, Exstart, Exchange, and Full

    F. Down, 2 - Way, Init, Exstart, Exch ange, Loading, and Full


    参考答案：A

  • 第5题：

    I did not mean____anything,but those apples looked so good I couldn’t resist___one.

    A.to eat…trying
    B.to eat…to trying
    C.eating…to try
    D.eating…to trying

    答案：A
    解析：

  • 第6题：

    【计算题】（6-9）定义Person类（属性有姓名，年龄)，完成如下任务： （1）在Test类中定义方法Boolean contains（Person[]per，Person temp),该方法判断Person数组是否有Person对象temp，如果数组中存在与per相同的Person对象返回boolean； （2）定义showPerson（Person[] per)输出Person对象数组所有元素； （3）对上面定义的方法进行测试。


    TestHashCode.java

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