Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables.EMPLOYEESNOT NULL, PrimaryEMPLOYEE_ID NUMBERKeyVARCHAR2EMP_NAME(30)VARCHAR2JOB_ID(20)SALARY NUMBERReferencesMGR_ID NUMBEREMPLOYEE_IDcolumnDEPARTMENT_ID NUMBER Foreign key toDEPARTMENT_IDcolumn ofthe DEPARTMENTStableDEPARTMENTSNOT NULL,DEPARTMENT_ID NUMBERPrimary KeyVARCHAR2DEPARTMENT_NAME|30|ReferencesMGR_ID columnMGR_ID NUMBERof theEMPLOYEES tableTAXMIN_SALARY NUMBERMAX_SALARY NUMBERTAX_PERCENT NUMBERFor which situation would you use a nonequijoin query?()
A. To find the tax percentage for each of the employees.
B. To list the name, job id, and manager name for all the employees.
C. To find the name, salary, and department name of employees who are not working with Smith.
D. To find the number of employees working for the Administrative department and earning less then 4000.
E. To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
第1题:
A、check
B、examine
第2题:
第3题:
检查
A.expect
B.except
C.excuse
D.examine
第4题:
( 2 )现有如下两个关系模式:
Employees ( Eid , Name , DeptNO )
Departments ( DeptNO , DeptName , TotalNumber )
Employees 关系模式描述了职工编号、姓名和所在部门编号; Departments 关系模式描述了部门编号、名称和职工总人数。
请 按 SQL Serve r 所采用 的 Tansact — SQ L 语法格式编写实现具有功能的后触发型触发器 : 每当在Employee s表中插入一行数据时,相应部门的职工总人数就加 1 。( 10 分)
第5题:
已知关系模式R的全部属性集U={A,B,C,D,E,G}及函数依赖集:
F=(AB→C,C→A,BC→D,ACD→B,D→EG,BE→C,CG→BD,CE→AG}求属性集闭包(BD)+
(2) 现有如下两个关系模式:
Employees(Eid,Name,DeptNO)
Departments(DeptNO,DeptName,TotalNumber)
Employees关系模式描述了职工编号、姓名和所在部门编号;Departments关系模式描述了部门编号、名称和职工总
第6题: