An administrator setting up software RAID 1 on a Windows Server with two volumes for two separate hard drives, but the option for mirrored is grayed out. Which of the following is the likely reason why this is occurring?()A. The disks have been setup as b

题目

An administrator setting up software RAID 1 on a Windows Server with two volumes for two separate hard drives, but the option for mirrored is grayed out. Which of the following is the likely reason why this is occurring?()

A. The disks have been setup as basic.

B. The page file must be at least 4GB to support mirrored drives.

C. The disks have been setup as dynamic.

D. Windows does not support software RAID 1.


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  • 第1题:

    有以下程序: main() { char *S[]={"one","two","three"},*p; p=s[1]; printf("%c,%s\n", *(p+1), s[0]); } 执行后输出结果是( )。

    A.n,two

    B.t,one

    C.w,one

    D.o,two


    正确答案:C
    解析:本题首先定义了一个有3个元素的指针数组s,并通过初始化列表使s[0]指向字符串“one”,s[1]指向字符串“two”,s[2]指向字符串“three”,然后通过赋值语句p=s[1],使p指向了字符串“two”,故*(p+1)就是字符‘w’。所以,C选项为所选。

  • 第2题:

    Whichofthefollowingarchitecturesisusedtosupporttheagentortheapplicationtier?()

    A.Simple

    B.Two-tier

    C.N-tier

    D.Client-server


    参考答案:A

  • 第3题:

    12. About_______ of the workers in the factory were born in the __________.

    A. two- thirds;1970

    B. two- thirds ; 1970s

    C. two-third ; 1970

    D. two-third ; 1970s


    正确答案:B
    12.B【解析】句意:工厂里大约2/3的工人出生在20世纪70年代。分数的表达为分子用基数词,分母用序数词,如果分子大于1,则分母要用复数,排除C、D,年代的表达要在年份后加s.故选B。

  • 第4题:

    有以下程序

    main()

    {char *s[]={"one","two","three"},*p;

    p=s[1];

    printf("%c,%s\n",*(p+1),s[0]);

    }

    执行后输出结果是

    A.n,two

    B.t,one

    C.w,one

    D.O,two


    正确答案:C
    解析:本题首先定义了一个有3个元素的指针数组s,并通过赋值使s[0]指向字符串“one”,s[1]指向字符串“two”,s[2]指向字符串“three”,然后通过赋值语句“p=s[1]”,使p指向了字符串“two”,故“*(p+1)”就是字符“w”。

  • 第5题:

    About ________ of the workers in the factory were born in the ________.

    A.two-thirds, 1970 B.two-thirds, 1970s C.two-third,1970 D.two-third, 1970s


    正确答案:B

  • 第6题:

    1、以下对枚举类型名的定义中正确的是()。

    A.enum a={one,two,three};

    B.enum a {one=9,two=-1,three};

    C.enum a={"one","two","three"};

    D.enum a {"one","two","three"};


    enum a {one=9,two=-1,three};