Click the Exhibit button to examine the data of the EMPLOYEES table. Evaluate this SQL statement:SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.employee_id "Mgr_id", m.emp_name "Manager"FROM employees e JOIN employees m ON (e.mgr_id = m.employee_id)AND e.salary > 4000;What is its output?()


A.A
B.B
C.C
D.D
E.E
第1题:
Examine the data in the EMPLOYEES and DEPARTMENTS tables:Also examine the SQL statements that create the EMPLOYEES and DEPARTMENTS tables:On the EMPLOYEES table, EMPLOYEE_ID is the primary key.MGR_ID is the ID of managers and refers to the EMPLOYEE_ID.DEPT_ID is foreign key to DEPARTMENT_ID column of the DEPARTMENTS table.On the DEPARTMENTS table, DEPARTMENT_ID is the primary key.Examine this DELETE statement:What happens when you execute the DELETE statement?()



A. Only the row with department ID 40 is deleted in the DEPARTMENTS table.
B. The statement fails because there are child records in the EMPLOYEES table with department ID 40.
C. The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 110 and 106 are deleted from the EMPLOYEES table.
D. The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 106 and 110 and the employees working under employee 110 are deleted from the EMPLOYEES table.
E. The row with department ID 40 is deleted in the DEPARTMENTS table. Also all the rows in the EMPLOYEES table are deleted.
F. The statement fails because there are no columns specifies in the DELETE clause of the DELETE statement.
第2题:

A.to find the tax percentage for each of the employees
B.to list the name, job_id, and manager name for all the employees
C.to find the name, salary, and the department name of employees who are not working with Smith
D.to find the number of employees working for the Administrative department and earning less than 4000
E.to display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned
第3题:
Click the Exhibit button and examine the data in the EMPLOYEES table.Examine the subquery:SELECT last_nameFROM employeesWHERE salary IN (SELECT MAX(salary)FROM employeesGROUP BY department_id);Which statement is true?()

A.The SELECT statement is syntactically accurate.
B.The SELECT statement does not work because there is no HAVING clause.
C.The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.
D.The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.
第4题:

A. static source pool
B. interface source pool
C. source pool with PAT
D. souce pool without PAT
第5题:
Click the Exhibit button and examine the data from the ORDERS and CUSTOMERS tables.Evaluate the SQL statement:SELECT *FROM ordersWHERE cust_id = (SELECT cust_idFROM customersWHERE cust_name = ‘Smith‘);What is the result when the query is executed?()

A.A
B.B
C.C
D.D
E.E
第6题:
You added a PHONE_NUMBER column of NUMBER data type to an existing EMPLOYEES table. The EMPLOYEES table already contains records of 100 employees. Now, you want to enter the phone numbers of each of the 100 employees into the table. Some of the employees may not have a phone number available. Which data manipulation operation do you perform?()
第7题:
To examine the Exhibit, press the Exhibit button. Which of the following addresses will be reachable without adding any routes?()
第8题:
0.947 Mbps
3.000 Mbps
4.065 Mbps
282.058 Mbps
第9题:
120M
320M
480M
600M
第10题:
MERGE
INSERT
UPDATE
ADD
ENTER
You cannot enter the phone numbers for the existing employee records.
第11题:
129.35.57.22
129.35.54.22
129.35.58.22
129.35.254.22
第12题:
The SELECT statement is syntactically accurate.
The SELECT statement does not work because there is no HAVING clause.
The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.
The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.
第13题:

A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));
第14题:
Click the Exhibit button and examine the data from the EMP table.The COMMISSION column shows the monthly commission earned by the employee.Which two tasks would require subqueries or joins in order to be performed in a single step? ()

A.listing the employees who earn the same amount of commission as employee 3
B.finding the total commission earned by the employees in department 10
C.finding the number of employees who earn a commission that is higher than the average commission of the company
D.listing the departments whose average commission is more than 600
E.listing the employees who do not earn commission and who are working for department 20 in descending order of the employee ID
F.listing the employees whose annual commission is more than 6000
第15题:

A.1
B.100
C.110
D.255
第16题:
Click the Exhibit button and examine the data in the EMPLOYEES table.On the EMPLOYEES table, EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID. The JOB_ID column is a NOT NULL column.Evaluate this DELETE statement:DELETE employee_id, salary, job_idFROM employeesWHERE dept_id = 90;Why does the DELETE statement fail when you execute it?()

A.There is no row with dept_id 90 in the EMPLOYEES table.
B.You cannot delete the JOB_ID column because it is a NOT NULL column.
C.You cannot specify column names in the DELETE clause of the DELETE statement.
D.You cannot delete the EMPLOYEE_ID column because it is the primary key of the table.
第17题:

A.1+0
B.1+1
C.1:1
D.1:N
第18题:
To examine the Exhibit, press the Exhibit button. Which of the following addresses should be reachable without adding any routes?()
第19题:
Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?()
第20题:
xxx-xxx-xxxx
(xxx) xxxxxxx
(xxx) xxx-xxxx
xxx-(xxx)-xxxx
第21题:
static source pool
interface source pool
source pool with PAT
souce pool without PAT
第22题:
SELECT last_name, department_name FROM employees NATURAL JOIN departments;
SELECT last_name, department_name FROM employees JOIN departments ;
SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);
SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);
SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
第23题:
Exhibit A
Exhibit B
The query returns no rows
The query fails because the outer query is retrieving more than one column
The query fails because both the inner and outer queries are retrieving data from the same table.