We discussed the problem three or four times, but could come to no ()A. endB. conclusionC. resultD. judgment

题目
We discussed the problem three or four times, but could come to no ()

A. end

B. conclusion

C. result

D. judgment

相似考题

1.How many price choices does the man offer？A.Three. B.Four. C.Five.

2.From the passage, how many places have the name Valencia?A. One.B. Two.C. Three.D. Four.

3.We _____ rather talk about football or the weather or what we had for lunch.A: willB: shouldC: wouldD: could

4.How many generators does the shuttle carry?A．One.B．Two.C．Three.D．Four.

参考答案和解析
参考答案：B
更多“We discussed the problem three or four times, but could come to no () ”相关问题

  • 第1题：

    Roundline is a ______.

    A.four-stranded, left- or right-handed line

    B.three-stranded, right-handed line

    C.three-stranded, left-handed line

    D.small tarred hempline of three strands laid left-handed


    正确答案：B
    细圆绳时三股，右旋。

  • 第2题：

    下列语句能给数组赋值，而不使用for循环的是

    A．myArray{[1]="One"；[2]="Two"；[3]="Three"；}

    B．String s[5]=new String[] {"Zero","One","Two","Three","Four"}；

    C．String s[]=new String[] {"Zero","One","Two","Three","Four"}；

    D．String s[]=new String[]= {"Zero","One","Two","Three","Four"}；


    正确答案：C
    解析：字符串数组赋初值的方法有两种，一种是如选项C一样初始化。另外一种是先为每个数组元素分配引用空间，再为每个数组元素分配空间并赋初值。例如还可做如下赋值：
      string s[]=new String[5]；
      s[0]="Zero"；
      s[1]="One"；
      s[2]="Two"；
      s[3]="Three"；
      s[4]="Four"；

  • 第3题：

    How many morphemes does the word "impossible" consist of?

    A．One.
    B．Two.
    C．Three.
    D．Four.

    答案：C
    解析：
    考查词素知识。impossible这个单词包含三个语素，分别是前缀im-，词根possi和后缀-ble。故选C。

  • 第4题：

    How many approaches are mentioned to define a narrative?

    A．One.

    B．Two.

    C．Three.

    D．Four.


    正确答案：C
    解析：细节理解题。由文章第二段中“Another”、“A third”可知定义故事的方法共有三种。

  • 第5题：

    Howmanypiecesofadvicearegiventotheteenagerswhohaveproblemsinthispassage?

    A.Two.

    B.Three.

    C.Four.

    D.Five.


    正确答案：B

  • 第6题：

    下列给字符串二维数组进行赋值的语句中，错误的是（）。

    A．String s[ ] [ ] = new String [ ] [ ] { { “One “ , “ Two “ }, { “ Three “ , “ Four “ } } ;

    B．String s[ ] [ ] = { { “ One “ , “Two “},{ “ Three “ , “ Four “ } } ;

    C．String s[ ] [ ] = new String [ ] [ ] { { “Zero”} , { “ One ” , “Two” , “ Three” , “ Four” } } ;

    D．String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;


    String s[ 2] [2 ] = { { “ One ” , “Two”},{“ Three” , “ Four” } } ;

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