If a refrigeration compressor is short cycling on high head pressure, you shouldA.purge the condenser if the waterside is dirtyB.check for proper water flow through the condenserC.increase the high pressure cutout settingD.reduce the cooling water flow

题目

If a refrigeration compressor is short cycling on high head pressure, you should

A.purge the condenser if the waterside is dirty

B.check for proper water flow through the condenser

C.increase the high pressure cutout setting

D.reduce the cooling water flow

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更多“If a refrigeration compressor is short cycling on high head pressure, you shouldA.purge th ”相关问题

  • 第1题：

    __________ pressure 减轻压力


    压力对…施加压力

  • 第2题：

    _________ pressure: 同辈压力，同侪压力


    peer

  • 第3题：

    对于环境已经恶化的区域，更适合采用（）制定指标 For regions where the environment has been deteriorated, it is more appropriate to adopt （） for indicator settlement

    A．pressure-state-response框架 The pressure-state-response framework

    B．state-pressure-response框架 The state-pressure-response framework

    C．response-pressure-state框架 The response-pressure-state framework

    D．response-state-pressure框架 The response-state-pressure framework


    细嫩

  • 第4题：

    以下对于列表的相关操作中哪些项有正确的输出结果？

    A.＞＞＞ language = list('PHP'); ＞＞＞ language[1:] = 'ython'; ＞＞＞ print(language) ['P', 'y', 't', 'h', 'o', 'n']#B.＞＞＞ print(list('Life is short, you need Python.').count('is')) 1#C.＞＞＞ x = [2, 3, 0, 4, 1] ＞＞＞ x.sort() ＞＞＞ print(x) [0, 1, 2, 3, 4]#D.＞＞＞ words = ['Life', 'is', 'short', 'you', 'need', 'Python'] ＞＞＞ words.index('you') 4
    ＞＞＞ language = list('PHP'); ＞＞＞ language[1:] = 'ython'; ＞＞＞ print language ['P', 'y', 't', 'h', 'o', 'n'];＞＞＞ x = [2, 3, 0, 4, 1]＞＞＞ x.sort()＞＞＞ print x[0, 1, 2, 3, 4]

  • 第5题：

    对于环境已经恶化的区域，更适合采用state-pressure-response框架制定管理指标体系（）For an area where the environment has deteriorated, the State-Pressure-Response framework will be more suitable for the development of its management index system（）


    C答案：C优化开发区域是指国土开发密度已经较高、资源环境承载能力开始减弱的区域。

  • 第6题：

    以下对于列表的相关操作中哪些项有正确的输出结果？

    A.＞＞＞ language = list('PHP'); ＞＞＞ language[1:] = 'ython'; ＞＞＞ print language ['P', 'y', 't', 'h', 'o', 'n']#B.＞＞＞ print list('Life is short, you need Python.').count('is') 1#C.＞＞＞ x = [2, 3, 0, 4, 1] ＞＞＞ x.sort() ＞＞＞ print x [0, 1, 2, 3, 4]#D.＞＞＞ words = ['Life', 'is', 'short', 'you', 'need', 'Python'] ＞＞＞ words.index('you') 4
    ＞＞＞ language = list('PHP'); ＞＞＞ language[1:] = 'ython'; ＞＞＞ print language ['P', 'y', 't', 'h', 'o', 'n'];＞＞＞ x = [2, 3, 0, 4, 1]＞＞＞ x.sort()＞＞＞ print x[0, 1, 2, 3, 4]

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