更多“What's more, it's not always so ______ for us to pay online as hackers might steal our and password. ”相关问题
  • 第1题:

    Given:What,insertedatline39,willsortthekeysinthepropsHashMap?()

    A.Arrays.sort(s);

    B.s=newTreeSet(s);

    C.Collections.sort(s);

    D.s=newSortedSet(s);


    参考答案:B

  • 第2题:

    【填空题】单位换算:(答案直接写整数,不要用科学计数法) 1us = ___________ ns 1ms = ___________ us 1s = ___________ ms 1s = ___________ us


    1at=10.33m H 2 O

  • 第3题:

    可以直接用来求Ag2SO4的溶度积的电池是

    A.Pt|H2(p)|H2SO4(a)| Ag2SO4(s)|Ag

    B.Ag|AgNO3(a)||K2SO4(a)|PbSO4(s)|Pb(s)

    C.Ag(s)|Ag2SO4(s)|K2SO4(a)||HCl(a)|AgCl(s)|Ag(s)

    D.Ag|AgNO3(a)||H2SO4(a)|Ag2SO4(s)|Ag(s)


    Ag|AgNO 3 ( a ) ||H 2 SO 4 ( a ) |Ag 2 SO 4 (s) |Ag(s)

  • 第4题:

    4、以下的描述中,必然是对Mealy型状态机的描述的是?

    A.always @(*) case (state) S0: begin out = 0; if (in) next_state = S1; else next_state = S2; end ……#B.always @(*) case (state) S0: begin if (in) next_state = S1; else next_state = S0; end ……#C.always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……#D.以上答案均不正确
    always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……

  • 第5题:

    下列Moore型状态机采用Verilog语言主控时序部分正确的是:

    A.always@(posedge clk or negedge reset) begin if(!reset) current_state<=s0; else current_state<=next_state; end

    B.always@(posedge clk ) begin if(!reset) current_state<=s0; else current_state<=next_state; end

    C.always@(posedge clk t) if(reset) current_state<=s0; else current_state<=next_state;

    D.always@(posedge clk or negedge reset) if(reset) current_state<=s0; else current_state<=next_state;


    always@(posedge clk or negedge reset) begin if(!reset) current_state<=s0; else current_state<=next_state; end

  • 第6题:

    以下的描述中,必然是对Mealy型状态机的描述的是?

    A.always @(*) case (state) S0: begin out = 0; if (in) next_state = S1; else next_state = S2; end ……#B.always @(*) case (state) S0: begin if (in) next_state = S1; else next_state = S0; end ……#C.always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……#D.以上答案均不正确
    always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……