更多“Let me __________ the case carefully before I draw a conclusion. ”相关问题
  • 第1题:

    根据下面资料,回答题
    T:同学们,我们来唱首歌:Let’s sing and dance.
    S: OK.
    ....
    T: (point to a picture) What′ s this
    S: It′ s a picture.
    T: Good. Look at the picture, what′ s the boy doing He is drawing. Read after me, draw, draw.
    T: Well done. Now let′ s play a game. I do, you say. (教师做画画动作,学生说"draw")
    T: Now let′s listen and do. (教师说"draw",学生做动作)

    找出老师值得借鉴的地方并说明理由。(5分)


    答案:
    解析:
    该老师讲授新单词draw时运用了TPR教学法,在课堂上充分调动学生的多种感官,有利于活跃课堂气氛并且帮助学生保持较长时间的注意力。该教学法又称“全身反应法”,强调身体的互动性和教学的生动性。学生在做出“draw”的动作时.也加深了对词义的理解和记忆。所以这种教学法可供借鉴。

  • 第2题:

    I'd like towithdraw 500 from my current account.

    A:leave
    B:pay
    C:put
    D:draw

    答案:D
    解析:
    本句意思:我想从我的活期存款中取出500。withdraw的意思是“提取”,与draw意思相 近。leave离开;pay付款;put放置。

  • 第3题:

    若int i=20;执行下列程序后,变量i的正确结果是____。 switch(i) { case 9: i+=1; case 10:i+=1; case 11: i+=1; default : i-=1; }


    13

  • 第4题:

    根据下面资料,回答题
    T:同学们,我们来唱首歌:Let’s sing and dance.
    S: OK.
    ....
    T: (point to a picture) What′ s this
    S: It′ s a picture.
    T: Good. Look at the picture, what′ s the boy doing He is drawing. Read after me, draw, draw.
    T: Well done. Now let′ s play a game. I do, you say. (教师做画画动作,学生说"draw")
    T: Now let′s listen and do. (教师说"draw",学生做动作)

    找出老师不合理的行为并进行修改。(10分)


    答案:
    解析:
    ①该老师的课堂导入不够合理。根据新课讲授部分的对话可知,该片段的教学内容是单词draw。但是该课堂导入却与新课毫无关系,只是起到了活跃课堂的作用,没有起到导入新课并引起学生学习兴趣的作用。 修改如下:
    T: Now look at four cartoon pictures.
    S: OK.
    T: Do you like them
    S: Yes.
    T: Look at another picture. What's the boy doing He is drawing cartoon pictures. Read after me, draw, draw.
    通过学生喜欢的卡通人物的图片进行导入,由图片联系到“画”的动作,从而引入生词。
    ②教师在引导学生进行练习时。单纯地靠“做一说”“说一做”来强化学生对“draw”的记忆,缺乏意义性与交际性。
    修改如下:
    把“说一做”活动修改成如下活动:
    T:(PPT呈现一个学生画画的场景)Now please make a dialogue in pairs according to the picture,using the new word“draw”.

  • 第5题:

    写出以下程序的运行结果: main() {int i,j=4; for(i=j;i<=2*j;i++) switch(i/j) {case 0: case 1: printf(“*”);break; case 2: printf(“#”); } }


    9

  • 第6题:

    程序的运行结果是()。 main() { int a=0,i; for(i=0;i<5;i++) { switch(i) { case 0: case 3:a+=2; case 1: case 2:a+=3; default:a+=5; } } printf("%dn",a); }

    A.41

    B.13

    C.10

    D.20


    2,1