Why did the woman leave her hometown?
A.To lead a city life.
B.To open a restaurant.
C.To find a job.
第1题:
#include <fstream>
#include <iostream>
using namespace std;
int main()
{
fstream inout;
inout.open("city.txt",ios::out);
inout<<"Dallas"<<" "<<"tonghua"<<" "<<"长春"<<" " ;
inout.close();
inout.open("city.txt",ios::app | ios::out);
inout<<"罗马"<<" "<<"巴黎"<<" ";
inout.close();
char city[20];
inout.open("city.txt",ios::in);
while(!inout.eof())
{inout>>city;
cout<<city<<" ";
}
inout.close();
system("PAUSE");
return 0;
}
定义一个字符型数组city[20],将从文本文件“city.txt”所读取的数据,暂时存在city[20]中,然后通过输出函数cout将数据输出。
第2题:
Woman : Hello, Mr. Johnson&39; s office.
Man : Good morning._____56_____ ?
Woman : Sorry,he&39; s in a meeting at the moment._____57_____ ?
Man:Yes. This is Steve Lee from Brightlight Systems._____58_____ ?
Woman:Tomorrow afternoon in your office.
Man : _____59_____
Woman : Okay._____60_____
Man : Thank you.
56_________
57
58
59
60
请帮忙给出每个问题的正确答案和分析,谢谢!
A
第3题:
BookStore数据库中有客户表Customer(CustomerCode, Name, Sex, Hometown, Email, Telephone, LoginDate, Password) 查询Customer表中所有客户的信息,要求显示CustomerCode、Name、Hometown和Telephone字段信息。SQL语句: SELECT _________ FROM Customer
A.*
B.ALL
C.CustomerCode、Name、Hometown、Telephone
D.CustomerCode,Name,Hometown,Telephone
第4题:
关系模式CSZ(CITY,ST,ZIP)其属性组上的函数依赖集为F={(CITY,ST)+ZIP, ZIP→CITY},关系模式CSZ的主属性是
A.ZIP
B.CITY,ST,ZIP
C.CITY,ZIP
D.ST,ZIP
第5题:
关系模式CSZ(CITY,ST,ZIP)其属性组上的函数依赖集为F={(CITY,ST)→ZIP, P→CITY},关系模式CSZ的主属性是
A.ZIP
B.CITY,ST,ZIP
C.CITY,ZIP
D.ST,ZIP
第6题:
BookStore数据库中有客户表Customer(CustomerCode, Name, Sex, Hometown, Email, Telephone, LoginDate, Password) 查询Customer表中所有客户的信息,SQL语句: SELECT ________ FROM Customer
A.*#B.CustomerCode, Name, Hometown, Sex, Email, Telephone, LoginTime, PassWord#C.CustomerCode, Hometown, Telephone, Name, Sex, Email, LoginTime, PassWord#D.CustomerCode ~ PassWord