Dear Mr. Ge Yongming,Thank you for your letter 1) _______ congratulations to me on the award.I am of course happy that anything I may have done should be rewarded by an 2) _______, but at the same time I regard the award as something of a tribute to the t
题目
Dear Mr. Ge Yongming,
Thank you for your letter 1) _______ congratulations to me on the award.
I am of course happy that anything I may have done should be rewarded by an 2) _______, but at the same time I regard the award as something of a tribute to the teamwork of my colleagues, rather than to me 3) _______.
Indeed I have always enjoyed the willing help and 4) _______ of many contributors, who include you, my 5) _______ partner from the other side of the world. May our pleasant relations continue to expand in future.
Yours truly,
Adam Adel
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更多“Dear Mr. Ge Yongming, Thank you for your letter 1) _______ congratulations to me on the ”相关问题
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第1题：
Merry Christmas, George! Here is a card for ________, with ________ best withes.A.you…your
B.you…our
C.us…our
D.us…your
参考答案：B
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第2题：
49．—What about some drinks?
—__________．
A． Help， yourself
B． Good idea
C． You're welcome
D． Me，too
正确答案：B
49．B【解析】句意t——来些饮料怎么样？——好主意。选项A的意思是“自用／随便吃”；选项D的意思“我也是”，两个选项均不符合题意;选项C是用来回答 Thank you的问题，故也排除。 -
第3题：
Me,you是两个初始集合，则下列关于派生集合定义方式正确的是
A．link/me,you/:a;
B．link(me,you):a;
C．link/me you/a;
D．link(me,you)/a;
link(me,you):a; -
第4题：
（ ） – Is Miss White __________ English teacher, Maria?
– No, she teaches __________ geography.
A．your；my
B．you；mine
C．you；us
D．your；us
正确答案：D
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第5题：
将一批单词存入一个字符串数组中，例如：{"good","word","work","mean","thank","me","you","or","and"} 进行如下处理： 1) 统计含有子字符串or的单词个数； 2) 统计以字符m开头的单词个数。
D 解析：选项A是逐个字符赋值，字符数组末尾无“'\\0'”结束符，因此不是字符串。选项A应更正为：chars[5]={'g','o','o','d','!','\\0'}。选项B的错误在于，在赋值语句中对字符数组进行整体赋值。通常，在定义时可以对字符数组进行字符串的整体赋值。chars[5]='good!';是对选项B的更正。选项C存在语法错误。数组类型为int型，不是char型，不能进行初始化。chars[5]='good!';是对选项C的更正。选项D的“char*s;s='good!';”，是通过指针s指向字符串'good!'。 -
第6题：
me是一个包含3个成员属性为a的集合，you是一个包含2个成员属性为b的集合，则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是
A．ps(me,you):c;
B．ps(you,me):c;
C．ps(a,b):c;
D．ps(b,a):c;
ps(you,me):c;