If I couldn't get a scholarship, I might get a job () to graduate school next semester.
A、A instead go
B、B instead going
C、C instead to go
D、D instead of going
第1题:
snmpv1实现的请求/响应原语包括()。
A.get-request、set-request、get-next-request、get-response、trap
B.get、getNext、set、trap
C.get-request、set-request、get-next-request、get-response
D.get、set、trap
第2题:
A.for(inti=0;i<a.size();i++) System.out.println(a.get(i)));
B.for(inti=0;i<a.size();i++) System.out.println(a[i]);
C.while(iter.hasNext()) System.out.println(iter.next());
D.for(inti=0,i<a.size();i++) System.out.println(iter[i]);
E.for(inti=0;i<a.size();i++) System.out.println(iter.get(i));
第3题:
第4题:
此题为判断题(对,错)。
第5题:
A.Get-request
B.Get-next-request
C.Set-request
D.Set-next-request
第6题:
下面的代码用于输出字符数组ch中每个字符出现的次数,应该填入的代码是()public static void main(String[] args) { char[] ch = { 'a', 'c', 'a', 'b', 'c', 'b' }; HashMap map = new HashMap(); for (int i = 0; i < ch.length; i++) { < 填入代码 > } System.out.println(map); }
A.if (map.contains(ch[i])) { map.put(ch[i], map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }
B.if (map.contains(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }
C.if (map.containsKey(ch[i])) { map.put(ch[i], (int) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }
D.if (map.containsKey(ch[i])) { map.put(ch[i], (Integer) map.get(ch[i]) + 1); } else { map.put(ch[i], 1); }