The program will fail to compile.
The program will not terminate normally.
The program will write 10 to the standard output.
The program will write 0 to the standard output.
The program will write 9 to the standard output.
第1题:
控制台应用程序 example.java 如下:
public class example
{
public static void main(String[] args)
{
int i=0, j=9;
do
{
if(i++>--j) break;
} while(i<4);
System.out.println("i="+i+" and j="+j);
}
}
第2题:
What will be the result of attempting to compile and run the following code?() public class Q6b0c { public static void main(String args[]) { int i = 4; float f = 4.3; double d = 1.8; int c = 0; if (i == f) c++; if (((int) (f + d)) == ((int) f + (int) d)) c += 2; System.out.println(c); } }
第3题:
public class test ( public static void main(string args) { int 1= 0; while (i) { if (i==4) { break; } ++i; } } ) What is the value of i at line 10?()
第4题:
public class Test { public static void leftshift(int i, int j) { i<<=j; } public static void main(String args[]) { int i = 4, j = 2; leftshift(i, j); System.out.printIn(i); } } What is the result?()
第5题:
public class test( public int aMethod()[ static int i=0; i++; return I; ) public static void main (String args){ test test = new test(); test.aMethod(); int j = test.aMethod(); System.out.printIn(j); ] } What is the result?()
第6题:
public class Test { public int aMethod() { static int i = 0; i++; return i; } public static void main (String args[]) { Test test = new Test(); test.aMethod(); int j = test.aMethod(); System.out.println(j); } } What is the result?()
第7题:
class super ( public int I = 0; public super (string text) ( I = 1 ) ) public class sub extends super ( public sub (string text) ( i= 2 ) public static void main (straing args) ( sub sub = new sub (“Hello”); system.out. PrintIn(sub.i); ) ) What is the result?()
第8题:
Compilation will fail.
Compilation will succeed and the program will print “0”
Compilation will succeed and the program will print “1”
Compilation will succeed and the program will print “2”
第9题:
The code will fail to compile.
0 will be written to the standard output.
1 will be written to the standard output.
2 will be written to the standard output.
3 will be written to the standard output.
第10题:
0
1
2
Compilation fails.
第11题:
Compilation will fail.
Compilation will succeed and the program will print “0”
Compilation will succeed and the program will print “1”
Compilation will succeed and the program will print “2”
第12题:
The program prints “0”
The program prints “4”
The program prints “8”
The program prints “12”
The code does not complete.
第13题:
下列程序输出结果为( )。 public class test { public static void main (String args[]) { int a=0; outer:for(int i=0;i<2;i + +) { for(int j=0;j<2;j+ +) { if(j>i) { continue outer; } a+ +; } } System.out.println(a); } }
A.0
B.2
C.3
D.4
第14题:
class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?()
第15题:
public class Foo { public static void main (String []args) { int i = 1; int j = i++; if ((i>++j) && (i++ ==j)) { i +=j; } } } What is the final value of i?()
第16题:
public class ForBar { public static void main(String args) { int i = 0, j = 5; tp: for (;;) { i ++; for(;;) if(i > --j) break tp; } system.out.printIn(“i = ” + i + “, j = “+ j); } } What is the result? ()
第17题:
What will be the result of attempting to compile and run the following program?() public class Q28fd { public static void main(String args[]) { int counter = 0; l1: for (int i=10; i<0; i--) { l2: int j = 0; while (j < 10) { if (j > i) break l2; if (i == j) { counter++; continue l1; } } counter--; } System.out.println(counter); } }
第18题:
public class test ( private static int j = 0; private static boolean methodB(int k) ( j += k; return true; ) public static void methodA(int i)( boolean b: b = i < 10 | methodB (4); b = i < 10 || methodB (8); ) public static void main (String args[])( methodA (0); system.out.printIn(j); ) ) What is the result?()
第19题:
The program runs and prints “i=1, j=0”
The program runs and prints “i=1, j=4”
The program runs and prints “i=3, j=4”
The program runs and prints “i=3, j=0”
An error at line 4 causes compilation to fail.
An error at line 7 causes compilation to fail.
第20题:
0
3
4
5
The code will not compile.
第21题:
0
1
2
Compilation fails.
第22题:
12
18
8
9
27
第23题:
2
4
8
16
The code will not compile.