The value of b is 2.
The value of a is 3.14.
The value of b is 2.00.
The value of a is 3.141.
The value of a is 3.1415.
The value of a is 3.1416.
The value of b is 2.0000.
第1题:
Given:12.NumberFormatnf=NumberFormat.getInstance();13.nf.setMaximumFractionDigits(4);14.nf.setMinimumFractionDigits(2);15.Stringa=nf.format(3.1415926);16.Stringb=nf.format(2);WhichtwostatementsaretrueabouttheresultifthedefaultlocaleisLocale.US?()
A.Thevalueofbis2.00.
B.Thevalueofais3.141.
C.Thevalueofais3.14.
D.Thevalueofbis2.0000.
E.Thevalueofais3.1415.
F.Thevalueofais3.1416.
G.Thevalueofbis2.
第2题:
下列程序的功能是对两个整数进行比较,由考生通过输入窗口分别输入两个整数,程序
比较出结果。例如:输入第1个整数为12,第2个整数为33。比较结果显示:
12!=33
12<33
12<=33
程序有多个遗漏和错误。本题要求改一个错,填三个空。
注意:不改动程序结构,不得增行或删行。
import javax.swing.JOptionPane;
public class ex3
{
public static void main(String args[])
{
String firstNumber, //用户输入第1个字符串
secondNumber, //户输入第2个字符串
result; // a string containing the output
int number1, //较的第1个数
number2; //的第2个数
//读用户输入的第1个字符串read first number from user as a string
firstNumber=
JOptionPane.showlnputDialog("Enter first integer:");
//用户输入的第2个字符串read second number from user as a string
secondNumber=
JOptionPane.showInputDialog("Enter second integer:");
//字符串类型转换成整数类型
number1=Integer.parseInt(firstNumber);
number2=Integer.parseInt(secondNumber);
result="";
if(String.valueOf(numberl)=String.valueOf(number2))
result=String.valueOf(numberl)+"= ="+String.valueOf(number2);
if(String.valueOf(number1)!=String.valueOf(number2))
result=String.valueOf(number1)+" !="+String.valueOf(number2);
if(String.valueOf(numberl)< String.valueOf(number2))
result=result+"\n" +String.valueOf(numberl)+"<"
+String.valueOf(number2);
if(String.valueOf(numberl)>String.valueOf(number2))
result=result+"\n" +String.valueOf(numberl)+" >"
+String.valueOf(number2);
if(String.valueOf(numberl)<=String.valueOf(number2))
result=result+"\n"+String.valueOf(numberl)+" <="
+String.valueOf(number2);
if(String.valueOf(numberl)>=String.valueOf(number2))
result=result+"\n"+String.valueOf(numberl)+ ">="
+String.valueOf(number2);
______(null,result,"比较结果",______INFORMATION_MESSAGE);
//程序正常退出
______;
}
}
第3题:
NumberFormat nf= NumberFormat.getInstance(); nf.setMaximumFractionDigits(4); nf.setMinimumFractionDigits(2); String a = nf.format(3.1415926); String b = nf.format(2); Which two are true about the result if the default locale is Locale.US?()
第4题:
Which two statements are true about precedence values in policy?() (Choose two.)
第5题:
Given: 12. NumberFormat nf = NumberFormat.getInstance(); 13. nf.setMaximumFractionDigits(4); 14. nf.setMinimumFractionDigits(2); 15. String a = nf.format(3.1415926); 16. String b = nf.format(2); Which two statements are true about the result if the default locale is Locale.US?()
第6题:
The code will fail to compile.
The constructor in a that takes an int as an argument will never be called as a result of constructing an object of class b or c.
Class c has three constructors.
Objects of class b cannot be constructed.
At most one of the constructors of each class is called as a result of constructing an object of class c.
第7题:
The function method must have the signature: public String spin().
The method must be mapped to the logical name spin in the web.xml file.
The function method must have the signature: public String spinIt().
The function method must have the signature public static String spin().
The function method must have the signature: public static String spinIt().
The function class must be named Spinner, and must be in the package com.example.
第8题:
Tunnels are initiated by the LAC
Tunnels are initiated by the LNS
By default, subscriber authentication occurs on the LNS
By default, subscriber authentication occurs on the LAC
第9题:
b = nf.parse( input);
b = nf.format( input);
b = nf.equals( input);
b = nf.parseObject( input);
第10题:
The value of b is 2.
The value of a is 3.14.
The value of b is 2.00.
The value of a is 3.141.
The value of a is 3.1415.
The value of a is 3.1416.
The value of b is 2.0000.
第11题:
The value of b is 2.00.
The value of a is 3.141.
The value of a is 3.14.
The value of b is 2.0000.
The value of a is 3.1415.
The value of a is 3.1416.
The value of b is 2.
第12题:
The switchport belongs only to VLAN 2
Interface fa0/0 will be in both VLAN 1 (by default) and VLAN 2
The exhibit shows interface fa0/0 to be dynamically mapped to VLAN 2
A network host can be connected to this interface
第13题:
A.b=nf.parse(input);
B.b=nf.format(input);
C.b=nf.equals(input);
D.b=nf.parseObject(input);
第14题:
下列语句能给数组赋值而不使用for循环的是
A.myArray{[1]="One";[2]="Two";[3]="Three";}
B.String s[5]=new String[]{"Zero", "One", "Two", "There", "Four"};
C.String s[]=new String[]{"Zero", "One", "Two", "There", "Four"};
D.String s[]=new String[]=|"Zero", "One", "Two", "There", "Four"};
第15题:
11. double input = 314159.26; 12. NumberFormat nf= NumberFormat.getInstance(Locale.ITALIAN); 13. String b; 14. //insert code here Which code, inserted at line 14, sets the value of b to 3 14.159,26?()
第16题:
Given: 11.double input = 314159.26; 12.NumberFormat nf = NumberFormat.getInstance(Locale.ITALIAN); 13.String b; 14.//insert code here Which code, inserted at line 14, sets the value of b to 314.159,26?()
第17题:
The first 2 octets represent the manufacturer OUI.
The first 3 octets represent the manufacturer OUI.
The last 3 octets are assigned by the organization itseIf.
The last 4 octets are assigned by the organization itseIf.
第18题:
The path cost can be changed for an interface using the spanning-tree cost command
The path cost can be changed for an interface using the stp path-cost command
The SPT default path cost depends on the interface speed
The STP default path cost is similar for all interface
第19题:
b = nf.parse( input );
b = nf.format( input );
b = nf.equals( input );
b = nf.parseObject( input );
第20题:
(a == Hello)
(a == b)
(a == c)
a.equals(b)
a.equals(d)
第21题:
The line marked (1).
The line marked (2).
The line marked (3).
The line marked (4).
The line marked (5).
第22题:
1 is the default precedence.
A lower number is preferred.
A higher number is preferred.
100 is the default precedence.
第23题:
b = nf.parse( input );
b = nf.format( input );
b = nf.equals( input );
b = nf.parseObject( input );