The value “4” is printed at the command line.
Compilation fails because of an error in line 5.
Compilation fails because of an error in line 9.
A NullPointerException occurs at runtime.
A NumberFormatException occurs at runtime.
An IllegalStateException occurs at runtime.
第1题:
1. public class X implements Runnable( 2. private int x; 3. private int y; 4. 5. public static void main(String[]args) 6. X that = new X(); 7. (new Thread(that)).start(); 8. (new Thread(that)).start(); 9. ) 10. 11. public void run() ( 12. for (;;) ( 13. x++; 14. y++; 15. System.out.printIn(“x=” + x + “, y = ” + y); 16. ) 17. ) What is the result?()
第2题:
1. public class Target { 2. private int i = 0; 3. public int addOne() { 4. return ++i; 5. } 6. } And: 1. public class Client { 2. public static void main(String[] args) { 3. System.out.println(new Target().addOne()); 4. } 5. } Which change can you make to Target without affecting Client?()
第3题:
1. public class A { 2. void A() { 3. System.out.println(“Class A”); 4. } 5. public static void main(String[] args) { 6. new A(); 7. } 8. } What is the result?()
第4题:
1. public class SwitchTest { 2. public static void main (String []args) { 3. System.out.PrintIn(“value =” +switchIt(4)); 4. } 5. public static int switchIt(int x) { 6. int j = 1; 7. switch (x) { 8. case 1: j++; 9. case 2: j++; 10. case 3: j++; 11. case 4: j++; 12. case 5: j++; 13. default:j++; 14. } 15. return j + x; 16. } 17. } What is the output from line 3?()
第5题:
1. public class Test { 2. public static String output =””; 3. 4. public static void foo(int i) { 5. try { 6. if(i==1) { 7. throw new Exception(); 8. } 9. output += “1”; 10. } 11. catch(Exception e) { 12. output += “2”; 13. return; 14. } 15. finally { 16. output += “3”;17. } 18. output += “4”; 19. } 20. 21. public static void main(String args[]) { 22. foo(0); 23. foo(1); 24. 25. }26. } What is the value of the variable output at line 23?()
第6题:
1. import java.util.*; 2. public class Example { 3. public static void main(String[] args) { 4. // insert code here 5. set.add(new integer(2)); 6. set.add(new integer(l)); 7. System.out.println(set); 8. } 9. } Which code, inserted at line 4, guarantees that this program will output [1,2]? ()
第7题:
1. public class A { 2. public String doit(int x, int y) { 3. return “a”; 4. } 5. 6. public String doit(int... vals) { 7. return “b”; 8. } 9. } Given: 25. A a=new A(); 26. System.out.println(a.doit(4, 5)); What is the result?()
第8题:
Line 26 prints “a” to System.out.
Line 26 prints „b” to System.out.
An exception is thrown at line 26 at runtime.
Compilation of class A will fail due to an error in line 6.
第9题:
Compilation fails.
Cannot add Toppings
The code runs with no output.
A NullPointerException is thrown in Line 4.
第10题:
Value = 3
Value = 4
Value = 5
Value = 6
Value = 7
Value = 8
第11题:
Compilation succeeds and 1 is printed.
Compilation succeeds and 2 is printed.
An error at line 8 causes compilation to fail.
An error at line 13 causes compilation to fail.
An error at line 14 causes compilation to fail.
第12题:
Class A
Compilation fails.
An exception is thrown at line 2.
An exception is thrown at line 6.
The code executes with no output.
第13题:
public class Test { public static void add3 (Integer i) { int val = i.intValue(); val += 3; i = new Integer(val); } public static void main(String args[]) { Integer i = new Integer(0); add3(i); System.out.println(i.intValue()); } } What is the result? ()
第14题:
1. public class A { 2. public void doit() { 3. } 4. public String doit() { 5. return “a”; 6. } 7. public double doit(int x) { 8. return 1.0; 9. } 10.} What is the result?()
第15题:
1. public class X { 2. public static void main (String[]args) { 3. int [] a = new int [1] 4. modify(a); 5. System.out.printIn(a[0]); 6. } 7. 8. public static void modify (int[] a) { 9. a[0] ++; 10. } 11. } What is the result?()
第16题:
1. class Pizza { 2. java.util.ArrayList toppings; 3. public final void addTopping(String topping) { 4. toppings.add(topping); 5. } 6. } 7. public class PepperoniPizza extends Pizza { 8. public void addTopping(String topping) { 9. System.out.println(”Cannot add Toppings”); 10. } 11. public static void main(String[] args) { 12. Pizza pizza = new PepperoniPizza(); 13. pizza.addTopping(”Mushrooms”); 14. } 15. } What is the result?()
第17题:
1. public class Boxer1 { 2. Integer i; 3. int x; 4. public Boxer1(int y) { 5. x=i+y; 6. System.out.println(x); 7. } 8. public static void main(String[] args) { 9. new Boxer1(new Integer(4)); 10. } 11. } What is the result?()
第18题:
1. public class test ( 2. public static void main(string args[]) { 3. int 1= 0; 4. while (i) { 5. if (i==4) { 6. break; 7. } 8. ++i; 9. } 10. 11. } 12. ) What is the value of i at line 10?()
第19题:
The program runs and prints “0”
The program runs and prints “1”
The program runs but aborts with an exception.
An error “possible undefined variable” at line 4 causes compilation to fail.
An error “possible undefined variable” at line 9 causes compilation to fail.
第20题:
0
3
4
5
The code will not compile.
第21题:
Value is: 8
Compilation fails.
Value is: 12
Value is: -12
The code runs with no output.
An exception is thrown at runtime.
第22题:
0
3
Compilation fails.
An exception is thrown at runtime.
第23题:
Line 4 of class Target can be changed to return i++;
Line 2 of class Target can be changed to private int i = 1;
Line 3 of class Target can be changed to private int addOne() {
Line 2 of class Target can be changed to private Integer i = 0;