单选题Why is an STM-1 2F-MS-SPRing NOT feasible？（）AAn equal amount of working and protect bandwidth is required.BDCC bandwidth is not large enough to handle K1/K2 processing.CSwitch times would exceed 50 ms for an STM-1 MS-SPRing ring.DThere is not enough ba

题目
单选题
Why is an STM-1 2F-MS-SPRing NOT feasible？（）
A

 An equal amount of working and protect bandwidth is required.

B

 DCC bandwidth is not large enough to handle K1/K2 processing.

C

 Switch times would exceed 50 ms for an STM-1 MS-SPRing ring.

D

 There is not enough bandwidth in an STM-1 ring to justify MS-SPRing protection.

相似考题

1.He doesn’t understand __________ so early in the morning.(A) why to start(B) why start(C) why to starting(D) why they should be start

2.It is not feasible to wait four days until the body______(use)to the new time zone.

3.Why is an OC－3 2F－BLSR not feasible?()A. Switch times would exceed 50 ms for an OC-3 BLSR ring.B. An equal amount of working and protect bandwidth is required.C. DCC bandwidth is not large enough to handle K1/K2 processing.D. There is not enough bandwidth in an OC-3 ring to justify BLSR protection.

4.You have overworked yourself.() a holiday to relax?A、Why not to go onB、Why don't go onC、Why don't haveD、Why not go on

参考答案和解析
正确答案： D
解析： 暂无解析
更多“Why is an STM-1 2F-MS-SPRing NOT feasible？（）”相关问题

  • 第1题：

    Router R1 lists 4 routes for subnet 10.1.1.0/24 in the output of the show ip eigrp topology all - links command. The variance 200 command is configured, but no other related commands are configured. Which of the following rules are true regarding R1‘s decision of what r outes to add to the IP routing table?Note that RD refers to reported distance and FD to feasible distanc E.（）

    A. Adds all routes for which the metric is <= 200 * the best metric among all routes

    B. Adds all routes because of the ridiculously high variance setting

    C. Adds all successor and feasible successor routes

    D. Adds all successor and feasible successor routes for which the metric is<=200 * the best metric among all routes


    参考答案：D

  • 第2题：

    请在（16）处填上最佳答案。

    [A] feasible

    [B] available

    [C] reliable

    [D] applicable


    正确答案：B

  • 第3题：

    甚高频的英文全称（）

    • A、Very high fantasy
    • B、Very high frequency
    • C、Very high feasible

    正确答案:B

  • 第4题：

    Which condition must be satisfied before an EIGRP neighbor can be considered a feasiblesuccessor?（）

    • A、The neighbor's advertised distance must be less than or equal to the feasible distance of the current successor.
    • B、The neighbor's advertised distance must be less than the f easible distance of the current successor.
    • C、The neighbor's advertised distance must be greater than the feasible distance of the current successor.
    • D、The neighbor's advertised distance must be equal to the feasible distance of the current successor .
    • E、The neighbor's advertised distance must be greater than or equal to the feasible distance of the current successor.

    正确答案:A

  • 第5题：

    STM-1光信号采用的码型为（）；STM-1电信号采用的码型为CMI。


    正确答案:加扰NRZ

  • 第6题：

    中兴通讯的RNC可以支持E1、STM-1、信道化STM-1，可以根据运营商的资源情况，灵活组网。


    正确答案:正确

  • 第7题：

    按C-12复用进STM-1可以传（）个2M，按C-3复用进STM-1可以传（）个2M，按C-4复用进STM-1可以传（）个2M。


    正确答案:63；48；64

  • 第8题：

    从34Mbit/s的信号复用进STM-1信号，STM-1可容纳3个34Mbit/s的信号，此时STM-1信号的容量为（）。

    • A、76.5×2Mbit/s
    • B、48×2Mbit/s
    • C、17×2Mbit/s
    • D、51×2Mbit/s

    正确答案:B

  • 第9题：

    Router R1 lists 4 routes for subnet 10.1.1.0/24 in the output of the show ip eigrp topology all - links command. The variance 200 command is configured, but no other related commands are configured. Which of the following rules are true regarding R1's decision of what r outes to add to the IP routing table? Note that RD refers to reported distance and FD to feasible distanc E.（）

    • A、Adds all routes for which the metric is <= 200 * the best metric among all routes
    • B、Adds all routes because of the ridiculously high variance setting
    • C、Adds all successor and feasible successor routes
    • D、Adds all successor and feasible successor routes for which the metric is<=200 * the best metric among all routes

    正确答案:D

  • 第10题：

    SDH中STM-1的速率是多少？是如何计算出来的？STM-1的结构包括哪三个部分的内容？


    正确答案: STM-1是SDH中最基本的最重要的模块，其传输速率为：155.520Mbit/s，
    SDH的帧由纵向9行和横向270×N列字节组成，传输时按由左至右，由上到下的顺序排成串型码流依次传输，传输一帧的时间为125μs，每秒传输8000帧，对STM-1而言，传输速率为8×9×270×8000=155.520Mbit/s。
    整个帧结构包含段开销（SDH），STM—N净负荷和管理单元指针（AU—PTR）三个部分

  • 第11题：

    单选题
    Why is an OC-3 2F-BLSR not feasible?（）
    A

    Switch times would exceed 50 ms for an OC-3 BLSR ring.

    B

    An equal amount of working and protect bandwidth is required.

    C

    DCC bandwidth is not large enough to handle K1/K2 processing.

    D

    There is not enough bandwidth in an OC-3 ring to justify BLSR protection.


    正确答案： C
    解析： 暂无解析

  • 第12题：

    单选题
    Vehicles（）only the simplest of the engine improvements that methanol makes feasible would still contribute to an immediate lessening of urban air pollution.
    A

    corporate

    B

    cooperating

    C

    operating

    D

    incorporating


    正确答案： B
    解析： 暂无解析

  • 第13题：

    Refer to the exhibit. EIGRP has been configured on al l routers in the network. The command metric weights 0 0 1 0 0 has been added to the EIGRP process so that only the delay metric is used in the path calculations. Which router will R1 select as the successor and feasible successor for Network A?（）

    A. R 4 becomes the successor for Network A and will be placed in the routing table. R2 becomes the feasible successor for Network A

    B. R4 becomes the successor for Network A and will be included in the routing table. No feasible successor will be selected a s the advertised distance from R2 is higher than the feasible distance

    C. R2 becomes the successor and will be placed in the routing table. R4 becomes the feasible successor for Network A

    D. R2 becomes the successor and will be placed in the routing t able. No feasible successor will be selected as the reported distance from R4 is lower than the feasible distance


    参考答案：B

  • 第14题：

    It's prudent to start any exercise program gradually at first.

    A:workable
    B:sensible
    C:possible
    D:feasible

    答案：B
    解析：
    本句意思：初期逐渐开始锻炼计划比较慎重。prudent审慎的，精明的。sensible明智的， 合理的；possible可能的；feasible可行的。

  • 第15题：

    Miss Wang wanted to know（）for the film.

    • A、why was he late
    • B、why is he late
    • C、why he is late
    • D、why he was late

    正确答案:D

  • 第16题：

    STM-1光信号采用的码型为STM-1电信号采用的码型为（）。

    • A、HDB3
    • B、CMI
    • C、加扰NRZ
    • D、AMI

    正确答案:B,C

  • 第17题：

    ZXCTN设备上C-POS单板是将（），通道化单板是将（）

    • A、下游业务的E1信号映射至STM－1信号；下游业务的FE信号映射至STM－1信号
    • B、下游业务的FE信号映射至STM－1信号；下游业务的E1信号映射至STM－1信号
    • C、下游业务的E1信号映射至FE信号；下游业务的FE信号映射至STM－1信号
    • D、下游业务的FE信号映射至STM－1信号；下游业务的FE信号映射至STM－1信号

    正确答案:B

  • 第18题：

    ZXCTN设备上C-POS单板是将下游业务的FE信号映射至STM－1信号，通道化单板是将（）。

    • A、下游业务的FE信号映射至STM－1信号
    • B、下游业务的E1信号映射至STM－1信号
    • C、下游业务的AF信号映射至STM－1信号
    • D、下游业务的BE信号映射至STM－1信号

    正确答案:B

  • 第19题：

    N个STM-1帧复用成STM-N时，第一个STM-1帧的段开销字节被完整保留，其余N-1个STM-1帧的段开销仅保留（）、（）、（）字节。


    正确答案:A1；A2；B2

  • 第20题：

    STM-1的ADM可构成（）。


    正确答案:单向复用段保护环

  • 第21题：

    Why is an STM-1 2F-MS-SPRing NOT feasible？（）

    • A、 An equal amount of working and protect bandwidth is required.
    • B、 DCC bandwidth is not large enough to handle K1/K2 processing.
    • C、 Switch times would exceed 50 ms for an STM-1 MS-SPRing ring.
    • D、 There is not enough bandwidth in an STM-1 ring to justify MS-SPRing protection.

    正确答案:A

  • 第22题：

    单选题
    He is opposed to the project for the reason why it is not feasible for the time being.
    A

    to

    B

    for the reason why

    C

    feasible

    D

    for the time being


    正确答案： B
    解析：

  • 第23题：

    单选题
    Which condition must be satisfied before an EIGRP neighbor can be considered a feasiblesuccessor?（）
    A

    The neighbor's advertised distance must be less than or equal to the feasible distance of the current successor.

    B

    The neighbor's advertised distance must be less than the f easible distance of the current successor.

    C

    The neighbor's advertised distance must be greater than the feasible distance of the current successor.

    D

    The neighbor's advertised distance must be equal to the feasible distance of the current successor .

    E

    The neighbor's advertised distance must be greater than or equal to the feasible distance of the current successor.


    正确答案： A
    解析： 暂无解析

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