but
not
or
nor
第1题:
下面结构体的定义语句中,错误的是( )。
A.struct ord{int x;int y;int z;};struct ord a;
B.struct ord{int x;int y;int z;};ord a;
C.struct ord{int x;int y;int z;}a;
D.struct{int x;int y;int z;}a;
第2题:
A、eats nor drank
B、eating nor drinking
C、ate nor drinking
D、ate nor drank
第3题:
She hardly ever eats ______ potatoes.
A、bread not
B、bread or
C、neither bread or
D、neither bread nor
第4题:
A) but
B) because
C) unless
D) when
第5题:
【C10】
A.but
B.because
C.while
D.in order that
第6题:
第7题:
布尔检索技术包括()。
第8题:
已知变量ch是字符型变量,下面PASCAL赋值语句正确的是()
第9题:
H
h
72
104
第10题:
ch:=’ab cd’
ch:=chr(ord(succ(‘c’)+1))
ch:=ord(‘b ’)+ord(‘a’)
ch:=pred(succ(succ(‘f’)))
第11题:
SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');
SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');
第12题:
struct ord{int x;int y;int z;};struct ord a;
struct ord{int x;int y;int z;}struct ord a;
struct ord{int x;int y;int z;}a;
struct {int x;int y;int z;}a;
第13题:
Many people believe we are heading for environmental disaster ______ we radically change way we live
A) but B) although C) unless D) lest
很多人认为我们正朝向环境灾难,除非我们从根本上改变我们的生活方式
选C
第14题:
下面结构体的定义语句中,错误的是( )。
A.struct ord{int x;int Y;int Z;};struet ord a;
B.struct ord{int x;int y;int Z;}struct ord a;
C.struct ord{int X;int Y;int Z;}a;
D.struct{int X;int y;int Z;}a;
第15题:
() the plot is weak, the action is really fantastic.
A、But
B、Although
C、Because
第16题:
下面结构体的定义语句中,错误的是
A.struct ord{int x;int y;int z;};struet ord a;
B.atruet ord{int x;int y;int z;}struct ord a;
C.struet ord{int x;int y;int z;}a;
D.struct{int x;int y;int z;)a;
第17题:
( )
A.But
B.However
C.And
D.So
第18题:
Mr. John was busy,()he could not come.
第19题:
Hurry up,()you’ll be late.
第20题:
Examine the data from the ORDERS and CUSTOMERS table. ORDERS ORD_ID ORD_DATE CUST_ID ORD_TOTAL 100 12-JAN-2000 15 10000 09-MAR- 101 40 8000 09-MAR- 102 35 12500 15-MAR- 103 15 12000 104 25-JUN-2000 15 6000 105 18-JUL-2000 20 5000 106 18-JUL-2000 35 7000 107 21-JUL-2000 20 6500 04-AUG- 108 10 8000 CUSTOMERS CUST_ID CUST_NAME CITY 10 Smith Los Angeles 15 Bob San Francisco 20 Martin Chicago 25 Mary New York 30 Rina Chicago 35 Smith New York 40 Linda New York Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin places his orders?()
第21题:
SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Martin' AND ord_date IN ('18-JUL-2000','21-JUL-2000');
SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'Martin'));
SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders, customers WHERE cust_name = 'Martin');
SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust_name = 'Martin');
第22题:
neither you nor I are
neither you nor me is
neither you nor I am
neither me nor you are
第23题:
CREATE SYNONYM ord FOR orders; This command is issued by OE
CREATE PUBLIC SYNONYM ord FOR orders; This command is issued by OE
CREATE SYNONYM ord FOR oe.orders; This command is issued by the database administrator
CREATE PUBLIC SYNONYM ord FOR oe.orders; This command is issued by the database administrator
第24题:
SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');
SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');