单选题Which SQL statement accepts user input for the columns to be displayed, the table name, and the WHERE condition?（）A SELECT &1, &2 FROM &3 WHERE last_name = '&4';B SELECT &1, '&2' FROM &3 WHERE '&last_name = '&4'';C SELECT &1, &2 FROM &3 WHERE last_name

题目
单选题
Which SQL statement accepts user input for the columns to be displayed, the table name, and the WHERE condition?（）
A

SELECT &1, &2 FROM &3 WHERE last_name = '&4';

B

SELECT &1, '&2' FROM &3 WHERE '&last_name = '&4'';

C

SELECT &1, &2 FROM &3 WHERE last_name = '&4';

D

SELECT &1, '&2' FROM EMP WHERE last_name = '&4';

相似考题

1.与 “ SELECT DISTINCT 歌手号 FROM 歌手 WHERE 最后得分＞ = ALL ;(SELECT 最后得分 FROM 歌手 WHERE SUBSTR( 歌手号 ,1,1)="2") ” 等价的 SQL 语句是A)SELECT DISTINCT 歌手号 FROM 歌手 WHERE 最后得分＞ = ;(SELECT MAX( 最后得分 ) FROM 歌手 WHERE SUBSTR( 歌手号 ,1,1)="2")B)SELECT DISTINCT 歌手号 FROM 歌手 WHERE 最后得分＞ = ;(SELECT MIN( 最后得分 ) FROM 歌手 WHERE SUBSTR( 歌手号 ,1,1)="2")C)SELECT DISTINCT 歌手号 FROM 歌手 WHERE 最后得分＞ =ANY ;(SELECT 最后得分 FROM 歌手 WHERE SUBSTR( 歌手号 ,1,1)="2")D)SELECT DISTINCT 歌手号 FROM 歌手 WHERE 最后得分＞ =SOME ;(SELECT 最后得分 FROM 歌手 WHERE SUBSTR( 歌手号 ,1,1)="2")

2.Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? ()A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

3. Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2 (25) LAST_NAME VARCHAR2 (25) HIRE_DATE DATE NEW EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid? （）A、DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);B、DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);C、DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = ('Carrey')'D、DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE last_ name = ('Carrey')'

4.Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? ()A. SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C. SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D. SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E. SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F. SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

更多“单选题Which SQL statement accepts user input for the columns to be displayed, the table name, and the WHERE condition?（）A SELECT 1, 2 FROM 3 WHERE last_name = '4';B SELECT 1, '2' FROM 3 WHERE 'last_name = '4'';C SELECT 1, 2 FROM 3 WHERE last_name = '4';D SEL”相关问题

  • 第1题：

    The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?（）

    • A、SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;
    • B、SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;
    • C、SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;
    • D、SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

    正确答案:D

  • 第2题：

    The EMPLOYEES table contains these columns: EMPLOYEE_ID NUMBER(4) LAST_NAME VARCHAR2 (25) JOB_ID VARCHAR2(10) You want to search for strings that contain 'SA_' in the JOB_ID column. Which SQL statement do you use?（）

    • A、SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA/_%' ESCAPE '/';
    • B、SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_';
    • C、SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_' ESCAPE "/";
    • D、SELECT employee_id, last_name, job_id FROM employees WHERE job_id = '%SA_';

    正确答案:A

  • 第3题：

    You need to display the last names of those employees who have the letter "A" as the second character in their names. Which SQL statement displays the required results? （）

    • A、SELECT last_name FROM EMP WHERE last_ name LIKE '_A%';
    • B、SELECT last_name FROM EMP WHERE last name ='*A%'
    • C、SELECT last_name FROM EMP WHERE last name ='_A%';
    • D、SELECT last_name FROM EMP WHERE last name LIKE '*A%'

    正确答案:A

  • 第4题：

    Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?（）

    • A、SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
    • B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • C、SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • D、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
    • E、SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
    • F、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

    正确答案:C,D,E

  • 第5题：

    You need to display the last names of those employees who have the letter “A” as the second character in their names.Which SQL statement displays the required results?（）

    • A、SELECT last_name   FROM EMP   WHERE last_name LIKE ‘_A%’;
    • B、SELECT last_name   FROM EMP   WHERE last name =’*A%’
    • C、SELECT last_name   FROM EMP   WHERE last name =’_A%’;
    • D、SELECT last_name   FROM EMP   WHERE last name LIKE ‘*A%’

    正确答案:A

  • 第6题：

    Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?（）

    • A、SELECT COUNT (*) FROM employees WHERE last _name='smith';
    • B、SELECT COUNT (dept_id) FROM employees WHERE last _name='smith';
    • C、SELECT DISTINCT (COUNT (dept_id) FROM employees WHERE last _name='smith';
    • D、SELECT COUNT (DISTINCT dept_id) FROM employees WHERE last _name='smith';
    • E、SELECT UNIQE (dept_id) FROM employees WHERE last _name='smith';

    正确答案:D

  • 第7题：

    Which SQL statement accepts user input for the columns to be displayed, the table name, and the WHERE condition?（）

    • A、SELECT &1, "&2" FROM &3 WHERE last_name = '&4';
    • B、SELECT &1, '&2' FROM &3 WHERE '&last_name = '&4'';
    • C、SELECT &1, &2 FROM &3 WHERE last_name = '&4';
    • D、SELECT &1, '&2' FROM EMP WHERE last_name = '&4';

    正确答案:C

  • 第8题：

    单选题
    Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?（）
    A

    SELECT COUNT(*) FROM employees WHERE last_name='Smith';

    B

    SELECT COUNT(dept_id) FROM employees WHERE last_name='Smith';

    C

    SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';

    D

    SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';

    E

    SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';


    正确答案： B
    解析： 暂无解析

  • 第9题：

    单选题
    The EMPLOYEES table contains these columns: EMPLOYEE_ID NUMBER(4) LAST_NAME VARCHAR2 (25) JOB_ID VARCHAR2(10) You want to search for strings that contain 'SA_' in the JOB_ID column. Which SQL statement do you use?（）
    A

    SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA/_%' ESCAPE '/';

    B

    SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_';

    C

    SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_' ESCAPE /;

    D

    SELECT employee_id, last_name, job_id FROM employees WHERE job_id = '%SA_';


    正确答案： A
    解析： 暂无解析

  • 第10题：

    单选题
    The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（）
    A

    The SQL statement displays the desired results.

    B

    The column in the WHERE clause should be changed to display the desired results.

    C

    The operator in the WHERE clause should be changed to display the desired results.

    D

    The WHERE clause should be changed to use an outer join to display the desired results.


    正确答案： C
    解析： 暂无解析

  • 第11题：

    单选题
    Which SQL statement accepts user input for the columns to be displayed, the table name, and WHERE condition? （）
    A

    SELECT &1, &2 FROM &3 WHERE last_name = '&8';

    B

    SELECT &1, '&2' FROM &3 WHERE '& last_name = '&8';

    C

    SELECT &1, &2 FROM &3 WHERE last_name = '&8';

    D

    SELECT &1, '&2' FROM EMP WHERE last_name = '&8';


    正确答案： A
    解析： 暂无解析

  • 第12题：

    多选题
    Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）
    A

    SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);

    B

    SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    C

    SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    D

    SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);

    E

    SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);

    F

    SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));


    正确答案： D,B
    解析： 暂无解析

  • 第13题：

    Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?（）

    • A、SELECT last_name, 12*salary* commission_pct FROM emp;
    • B、SELECT last_name, 12*salary* (commission_pct,0) FROM emp;
    • C、SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;
    • D、SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

    正确答案:C

  • 第14题：

    Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) Which statement produces the number of different departments that have employees with last name Smith?（）

    • A、SELECT COUNT(*) FROM employees WHERE last_name='Smith';
    • B、SELECT COUNT(dept_id) FROM employees WHERE last_name='Smith';
    • C、SELECT DISTINCT(COUNT(dept_id)) FROM employees WHERE last_name='Smith';
    • D、SELECT COUNT(DISTINCT dept_id) FROM employees WHERE last_name='Smith';
    • E、SELECT UNIQUE(dept_id) FROM employees WHERE last_name='Smith';

    正确答案:D

  • 第15题：

    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid?（）

    • A、DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);
    • B、DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);
    • C、DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');
    • D、DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');

    正确答案:C

  • 第16题：

    Which SQL statement accepts user input for the columns to be displayed, the table name, and WHERE condition? （）

    • A、SELECT &1, "&2" FROM &3 WHERE last_name = '&8';
    • B、SELECT &1, '&2' FROM &3 WHERE '& last_name = '&8';
    • C、SELECT &1, &2 FROM &3 WHERE last_name = '&8';
    • D、SELECT &1, '&2' FROM EMP WHERE last_name = '&8';

    正确答案:C

  • 第17题：

    Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）

    • A、SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department _ id);
    • B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • C、SELECT distinct department_id FROM employees Where salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • D、SELECT department_id FROM employees WHERE SALARY > ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);
    • E、SELECT last_name FROM employees Where salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);
    • F、SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

    正确答案:C,D,E

  • 第18题：

    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2(60) Which DELETE statement is valid?（）

    • A、DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);
    • B、DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_employees);
    • C、DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name ='Carrey');
    • D、DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE last_name ='Carrey');

    正确答案:C

  • 第19题：

    单选题
    You need to display the last names of those employees who have the letter “A” as the second character in their names.Which SQL statement displays the required results?（）
    A

    SELECT last_name   FROM EMP   WHERE last_name LIKE ‘_A%’;

    B

    SELECT last_name   FROM EMP   WHERE last name =’*A%’

    C

    SELECT last_name   FROM EMP   WHERE last name =’_A%’;

    D

    SELECT last_name   FROM EMP   WHERE last name LIKE ‘*A%’


    正确答案： B
    解析： 暂无解析

  • 第20题：

    单选题
    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid?（）
    A

    DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);

    B

    DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);

    C

    DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');

    D

    DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = 'carrey');


    正确答案： C
    解析： 暂无解析

  • 第21题：

    单选题
    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2 (25) LAST_NAME VARCHAR2 (25) HIRE_DATE DATE NEW EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2 (60) Which DELETE statement is valid? （）
    A

    DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);

    B

    DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_ employees);

    C

    DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = ('Carrey')'

    D

    DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE last_ name = ('Carrey')'


    正确答案： A
    解析： 暂无解析

  • 第22题：

    单选题
    You need to display the last names of those employees who have the letter "A" as the second character in their names. Which SQL statement displays the required results? （）
    A

    SELECT last_name FROM EMP WHERE last_ name LIKE '_A%';

    B

    SELECT last_name FROM EMP WHERE last name ='*A%'

    C

    SELECT last_name FROM EMP WHERE last name ='_A%';

    D

    SELECT last_name FROM EMP WHERE last name LIKE '*A%'


    正确答案： D
    解析： 暂无解析

  • 第23题：

    单选题
    Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: EMPLOYEES EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) HIRE_DATE DATE NEW_EMPLOYEES EMPLOYEE_ID NUMBER Primary Key NAME VARCHAR2(60) Which DELETE statement is valid?（）
    A

    DELETE FROM employees WHERE employee_id = (SELECT employee_id FROM employees);

    B

    DELETE * FROM employees WHERE employee_id = (SELECT employee_id FROM new_employees);

    C

    DELETE FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name ='Carrey');

    D

    DELETE * FROM employees WHERE employee_id IN (SELECT employee_id FROM new_employees WHERE last_name ='Carrey');


    正确答案： B
    解析： 暂无解析

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