填空题If 6w is an integer and 21/2 < 5w < 31/2, what is the value of w?____

题目
填空题
If 6w is an integer and 21/2 < 5w < 31/2, what is the value of w?____

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更多“If 6w is an integer and 21/2 < 5w < 31/2, what is the value”相关问题
  • 第1题:

    单击一次窗体之后,下列程序代码的执行结果为______。 Private Sub Command1_ Click() Dim a As Integer, b As Integer, c As Integer a = 1: b = 2: c = 4 Print Value(a, b,C)End Sub Function Num(x As Integer, y As Integer, z As Integer) Num = x * x + y * y + z * z End Function Function Value(x As Integer, y As Integer, z As Integer) Value = Num(x, y, z) + 2 * x End Function

    A.21

    B.23

    C.19

    D.35


    正确答案:B

  • 第2题:

    以下程序运行后,单击命令按钮,窗体显示的结果是 ______。 Private Function p1(x As Integer,y As Integel,z As Integer) p1=2*x+y+3*z End Function Private Function p2(x As Integer,y As Integer,z As Integer) p2=p1(2,y,x)+x End Function Private SubCommandl_Click() Dim a As Integer Dim b As Integer Dim c As Integer a=2:b=3:c=4 Print p2(c,b,A)

    End Sub

    A.19

    B.21

    C.22

    D.23


    正确答案:D
    解析:当程序执行到Print p2(c,b,a)语句时,首先调用函数过程p2,将实参c、b、a,的值4、3、2按顺序传递给p2的形参x、y、z,使形参x、y、z的值分别是4、3、2。当执行到函数过程p2中的语句p2=p1(z,y,x)+x时,又去调用函数过程p1,并将实参x、y、x的值2、3、4按顺序传递给形参x、y、z,使函数过程p1的形参x、y、z的值分别是2、3、4。于是执行p1中的语句p1=2*x+y+3*x=2*2+3+3*4=4+3+12=19。即函数过程p2中p1(2,y,x)的值为19,因此p2=p1(2,y,x)+x=19+4=23。该值返回给Command1_Click事件过程中的p2(c,b,a),所以窗体显示的值是23。

  • 第3题:

    Q4 :

    int iVal1 = 0, iVal2 = 0;

    int * ipVal;

    ipVal = &iVal1; What is the Value of ipVal = *ipVal =

    ipVal = (int*)iVal1; What is the Value of ipVal = *ipVal =

    iVal2 = (int)&iVal1; What is the Value of ipVal = *ipVal =


    正确答案:
     

  • 第4题:


    按上述(2)方案,18W灯管配电子镇流器,输入功率为20W,设计之照明功率密 度(LPD)为( )。

    A. 6. 8W/m2 ; B. 7. 6W/m2 C. 8. 5W/m2 ; D. 9.4W/m2。

    答案:D
    解析:

  • 第5题:

    5W2H法中5W和2H分别代表:What、Where、When、()、()、()、()。


    正确答案:Who;Why;How;Howmuch

  • 第6题:

    单选题
    What is the typical marked DSCP value for a voice signaling packet in VoIP technology?()
    A

    BE

    B

    AF41

    C

    AF21

    D

    EF

    E

    AF31


    正确答案: E
    解析: 暂无解析

  • 第7题:

    填空题
    5W2H法中5W和2H分别代表What、Where、When、W()、W()、H()、()。

    正确答案: ho,hy,ow,How much
    解析: 暂无解析

  • 第8题:

    填空题
    In the xy-plane, the graph of y = 2x2 + hx - 6 passes through the point (-3, -21), what is the value of h ?____

    正确答案: 11
    解析:
    因为(-3, -21)经过二次方程式,所以-21 = 2(-3)2 + h(-3) – 6,-21 = 18-3h-6= 12-3h,-33 =-3h,h = 11。

  • 第9题:

    问答题
    If 4 percent of (p + q) is 8 and p is a positive integer, what is the greatest possible value of q ?

    正确答案: 199
    解析:
    这是一道数学题,(p + q)的4%是8,因此p+q=200,设p=1,1是最小的正整数,则可知q的最大值是199。

  • 第10题:

    单选题
    What is the smallest integer value of x that satisfies the inequality 4-3x < 11?
    A

    -3

    B

    -2

    C

    -1

    D

    0

    E

    1


    正确答案: B
    解析:
    Solution 1: If 4-3x < 11, then -3x < 7, so x > -7/3. Since -7/3 is between -2 and -3, the smallest integer value of x that satisfies this inequality is -2. Solution 2: Plug each of the answer choices for x, starting with A., into 4-3x < 11 until you find one that makes the inequality a true statement. Choice A. gives 4-3(-3) < 11, 13 < 11 which is not a true statement. Choice B. gives 4-3(-2) < 11, 10 < 11 which is true, so there is no need to continue.

  • 第11题:

    填空题
    If t is a positive integer, and 18t is the cube of an integer, then what is the least possible value of t ?____

    正确答案: 12
    解析:
    因为13=1, 23 =8, 33=27, 43 =64, 53=125这几项等不能被18整除,而第六项63=216能被18整除因为216= 18×12,所以t=12。

  • 第12题:

    填空题
    k is an integer between 50 and 90 and is a multiple of 4. When k is divided by 5, the remainder is 3. When k is divided by 3, the remainder is 2. What is the value of k?____

    正确答案: 68
    解析:
    因为50和90之间的是4的倍数的数为52, 56, 60, 64, 68, 72, 76, 80, 84, 88。被5除余3的数为68和88。被3除余2的数为68。

  • 第13题:

    单击一次命令按钮,下列程序代码的执行结果为( )。 Private Sub Commandl_Click() Dima As Integer,b As Integer,CASInteger a=2:b=3:c=4 PrintP2(c,b,A) End Sub PrivateFunctionPl(X As Integer,y As Intege;z As Integer) P1=2*x+y+3*Z End Function Priva

    A.21

    B.19

    C.17

    D.34


    正确答案:A

  • 第14题:

    Q2 : Declare Function Multiply_Add Lib “test” (ByRef A as integer ,VeRef B as integer , ByVal c as integer ) as integer

    Q2.1: Explain what is Declare Function used for ?

    Ans :

    Q2.2 : Explain the difference between ByRef and ByVal ?

    Ans :


    正确答案:
     

  • 第15题:

    下列程序的执行结果为 Private Sub Comrnandl_Click( ) Dim p As Integer, q As Integer p=12:q=20 Call Value(p, q) Print p; q End Sub Private Sub Value(ByVal m As Integer, ByVal n As Integer) m=m * 2: n=n - 5 Print m; n End Sub

    A.20 12 20 15

    B.12 20 12 25

    C.24 15 12 20

    D.24 12 12 15


    正确答案:C
    解析:被调过程Value的两个参数m和n前面都有关键字“ByVal”修饰,即在主调过程调用此过程时,实参与形参之间是以传值方式传递信息的,而当实参与形参以传值方式相结合时,形参的改变并没有影响到实参,单单就这一点来说,我们可知,当程序代码执行主调过程中的PrimP;q语句时,p和q的值应不变,还是12,20,这样就能够排除选项A)和选项B)了。当主调过程调用被调过程时,把实参p,q的值分别传给形参m和n,这就是说此时形参m值为12,n值为20,执行被调过程中的m=m*2:n=n-5语句后,m值为24,n值为15,所以Printm;n后,程序输出的结果为24和15。最后程序输出的结果如选项C)所示。

  • 第16题:


    按上述(1)方案,36W灯管配电子镇流器,输入功率为37W,设计之照明功率密 度(LPD)为( )。

    A. 6. 8W/m2 ; B. 7. 6W/m2; C. 8. 5W/m2 ; D. 9. 4W/m2 。

    答案:A
    解析:

  • 第17题:

    What is the typical marked DSCP value for a voice media packet in Voice over IP technology?()

    • A、AF41
    • B、AF31
    • C、AF21
    • D、BE
    • E、EF

    正确答案:E

  • 第18题:

    单选题
    What is the typical marked DSCP value for a voice media packet in Voice over IP technology?()
    A

    AF41

    B

    AF31

    C

    AF21

    D

    BE

    E

    EF


    正确答案: B
    解析: 暂无解析

  • 第19题:

    填空题
    5W2H法中5W和2H分别代表:What、Where、When、()、()、()、()。

    正确答案: Who,Why,How,Howmuch
    解析: 暂无解析

  • 第20题:

    单选题
    If x is an integer and y=7x+11, what is the greatest value of x for which Y is less than 50?
    A

    7

    B

    6

    C

    5

    D

    4

    E

    3


    正确答案: A
    解析:
    解答这道题的快速方法是把选项中的数值依次代入方程式,计算y的数值,直到满足条件y<50为止,即可得出答案。

  • 第21题:

    填空题
    What is the value of 2×4-3 ?____

    正确答案: 1/32
    解析:
    2×4-3 =2×(1/64)=1/32。

  • 第22题:

    单选题
    If (p-q)2=16 and pq=21, what is the value of (p+q)2?
    A

    16

    B

    37

    C

    84

    D

    100

    E

    121


    正确答案: B
    解析:
    Expand(p-q) 2=16:(p-q) 2=p2-2pq+q2=p2+q2-2×21=16, p2+q2=58.
    Now expand (p+q)2: (p+q)2=p2+q2+2pq=58+2×21=100.

  • 第23题:

    填空题
    If 10a+4b=32 and 9a+2b=24, what is the value of a+2b?____

    正确答案: 8
    解析:
    两式相减得出(10a+4b) -(9a+2b)=a+2b=8。