参考答案和解析
正确答案: C
解析:
更多“The main difference between/m/,/n/, and /ŋ/lies in________.”相关问题
  • 第1题:

    The main problem with China's exhibition industry lies in a lack of investments.()


    正确答案:错

  • 第2题:

    运行以下程序后,如果从键盘上输入6514<回车>,则输出结果为______。 main() { int m,n; printf("En

    运行以下程序后,如果从键盘上输入6514<回车>,则输出结果为______。 main() { int m,n; printf("Enter m,n:"); scanf("%d%d",&m,&n); while(m!=n) { while(m>n)m-=n; while(n>m)n-=m; } printf("m=%d\n",m); }

    A.m=3

    B.m=2

    C.m=1

    D.m=0


    正确答案:C

  • 第3题:

    下面程序的运行结果是( )。 include main() {int a,s,n,m; a=2;s=0;n=1;m=1; while(m<=4

    下面程序的运行结果是( )。 include<stdio.h> main() {int a,s,n,m; a=2;s=0;n=1;m=1; while(m<=4){n=n*a;s=s+n;++m;} printf("s=%d",s); }


    正确答案:s=30
    s=30 解析:分析循环条件“m=1,m=4”,所以循环4次。第1次:n=n*a=2,s=s+n=2;m=2。第2次:n=n*a=4,s=s+n=6;m=3。第3次:n=n*a=8,s=s+n=14;m=4。第4次:n=n*a=16,s=s+n=30。

  • 第4题:

    The height of tide is the ______.

    A.depth of water at a specific time due to tidal effect

    B.difference between the depth of the water and the area's tidal datum

    C.difference between the depth of the water and the high water tidal level

    D.difference between the depth of the water at high tide and the depth of the water at low tide


    正确答案:B

  • 第5题:

    The main difference between /m/, /n/, and /?/lies in( ).

    A.manner of articulation
    B.sound duration
    C.place of articulation
    D.voicing

    答案:C
    解析:
    本题考查辅音的分类。A项意为“发音方式”,按照发音方式,三者都属于鼻音;B项意为“音长”,三者在该方面并无明显区别;C项意为“发音部位”,按照发音部位,/m/是双唇音,/n/是齿龈音,//是软腭音;D项意为“带声性”,三者均带声。故本题选C。

  • 第6题:

    what is the difference between the HSRP and VRRP?


    正确答案: (1)VRRP is an IEEE standard (RFC 2338) for router redundancy; HSRP is a Cisco proprietary protocol.
    (2)VRRP allows actual router IP address to be the same with the virtual IP,and if the same the router which get the IP will become Master router of the VRRP group;HSRP do not allow actual router IP address to be the same with the virtual IP.
    (3)HSRP uses the multicast address 224.0.0.2 which represent all router in the subnet , while VRRP uses the multicast address 224.0.0.18;HSRP uses UDP port 1985 while VRRP uses a protocol number of 112.
    (4)HSRP may have one active router,one standby router,multiple listening router.While VRRP may have one master router,multiple backup router.
    (5)HSRP exchange three kinds of message, hello message,coup message ,resign message. VRRP exchange only one kind of message, advertisement message.
    (6)In VRRP,preempt is enable by default.But in HSRP preemt is disable by default.

  • 第7题:

    What is difference between OSPF neighbor and adjacencies?


    正确答案: Neighbor:
    A neighbor is another OSPF router that is attached to the local router’s directly connected links, and ospf hello packet sended by the router have consistance parameter (such as hello time,dead time,area ID, mask and so on) with each other.
    Adjacency:
    An OSPF adjacency is a conceptual link to a neighbor over which LSAs can be sent.

  • 第8题:

    单选题
    What does the command show | compare rollback 1 display?()
    A

    the difference between the current candidate configuration and the candidate configuration from one commit ago

    B

    the difference between the current active configuration and the current candidate configuration

    C

    the difference between the current active configuration and the active configuration from one commit ago

    D

    the difference between the current candidate configuration and the archived configuration from one commit ago


    正确答案: C
    解析: 暂无解析

  • 第9题:

    单选题
    Which of the following statements represents the main difference between a relay and a contactor?()
    A

    Contactors control current and relays control voltage

    B

    A relay is series connected and a contactor is parallel connected

    C

    Contactors can handle heavier loads than relays

    D

    Contactors are made from silver and relays are made from copper


    正确答案: A
    解析: 暂无解析

  • 第10题:

    单选题
    The main difference between/m/,/n/, and /ŋ/lies in________.
    A

    manner of articulation

    B

    sound duration

    C

    place of articulation

    D

    voicing


    正确答案: C
    解析:

  • 第11题:

    单选题
    What does the command show | compare rollback 1 display?()
    A

    the difference between the current candidate configuration and the candidate configuration from one commit ago

    B

    the difference etween the current active configuration and the active configuration from the one commit ago

    C

    the difference between the current active configuration and the active configuration from one commit ago

    D

    the difference between the current candidate configuration and the archived configuration from one commit ago


    正确答案: D
    解析: 暂无解析

  • 第12题:

    单选题
    On what do you depend having the air cooler of main engine chemically washed?()
    A

    increased air pressure differenced before and aft air cooler

    B

    reduced exhaust temperature in all cylinders

    C

    reduced temperature difference between water inlet and outlet

    D

    both A and C


    正确答案: A
    解析: 暂无解析

  • 第13题:

    请补充main 函数,该函数的功能是:计算两个自然数n和m(m<10000)之间所有数的和(n和m从键盘输入)。

    例如:当n=1,m=100时,sum=5050:当n=100,m=1000时,sum=495550。

    注意:部分源程序给出如下。

    请勿改动主函数main和其他函数中的任何内容,仅在 main 函数的横线上填入所编写的若干表达式或语句。

    试题程序:

    include<stdio.h>

    include<conio.h>

    main ()

    {

    int n, m;

    long sum;

    【 】

    clrscr ();

    printf ("\nInput n,m\n");

    scanf ("%d, %d", &n, &m);

    while (n<=m)

    {

    【 】

    n++;

    }

    printf ("sum=%【 】\n", sum);

    }


    正确答案:sum=0 sum+=n 1d
    sum=0 sum+=n 1d 解析:第一空:变量sum 进行了类型声明,但没有进行初始化,而后面的程序用sum 来存放最后的结果,所以要在使用前将sum 初始化为0。第三空:通过while 循环将自然数n和m之间的数进行累加,结果存于sum 中。第三空:由于sum 为长整型,所以标准输出函数printf ()中的格式控制符为“%1d”。

  • 第14题:

    运行以下程序后,如果从键盘上输入65 14<回车>,则输出结果为_____。main(){int m,n;printf("Enter

    运行以下程序后,如果从键盘上输入65 14<回车>,则输出结果为_____。 main() { int m,n; printf("Enter m,n:"); scanf("%d%d",&m,&n); while(m!=n) { while(m>n)m-=n; while(n>m)n-=m; } printf("m=%d\n",m); }

    A.m=3

    B.m=2

    C.m=1

    D.m=0


    正确答案:C
    解析:分析程序可知,该程序实现的功能是对数m,n求其最大公约数。在本题中m与n的值分别为65与14,其最大公约数为1,故其输出结果为m=1。

  • 第15题:

    有以下程序: include main( ){ int m =12,n=34;printf( "% d% d" ,m++ , ++n);printf(

    有以下程序: #include <stdio.h>main( ){ int m =12,n=34; printf( "% d% d" ,m++ , ++n); printf("% d% d \n" ,n ++ , ++m); }程序运行后的输出结果是( )。

    A.12353514

    B.12353513

    C.12343514

    D.12343513


    正确答案:A
    解析:程序执行printf("%d%d",m++,++n);后,输出的是m和n+1的值1235,然后m+1=13,再执行printf("%d%d\n",n++,++m);输出n和m+1的值3514,之后n+1=36。这里要注意的是m++和++m的区别:m++是先输出m的值,再执行m++;++m是先执行++m,再输出m的值。

  • 第16题:

    The main difference between/m/and/n/lies in _________.


    A.manner of articulation

    B.place of articulation

    C.voicing

    D.length

    答案:B
    解析:
    考查英语音素。在发音方式上,二者都是鼻音;按照带声性,二者都带声,都是浊辅音;在发音部位上,/m/是双唇音,/n/是齿龈音。故选B。length指音的长度,是元音的特征。

  • 第17题:

    The main difference between/e/and//lies in the__________.


    A.tongue position

    B.sound duration

    C.openness of the mouth

    D.shape of the lips

    答案:A
    解析:
    考查元音的发音。根据发音时舌头在口腔中抬起的位置可分为:前元音、中元音、后元音。 根据发音时唇形的圆展可分为:圆唇元音和非圆唇元音。根据元音的长度可分为:长元音和短元音。根据以上分类方式,/e/可以描述为前、非圆唇、短元音,//为中、非圆唇、短元音。由此可知/e/和//的主要区别为发音时舌的位置。故选A。

  • 第18题:

    What does the command show | compare rollback 1 display?()

    • A、the difference between the current candidate configuration and the candidate configuration from one commit ago
    • B、the difference etween the current active configuration and the active configuration from the one commit ago
    • C、the difference between the current active configuration and the active configuration from one commit ago
    • D、the difference between the current candidate configuration and the archived configuration from one commit ago

    正确答案:D

  • 第19题:

    What does the command show | compare rollback 1 display?()

    • A、the difference between the current candidate configuration and the candidate configuration from one commit ago
    • B、the difference between the current active configuration and the current candidate configuration
    • C、the difference between the current active configuration and the active configuration from one commit ago
    • D、the difference between the current candidate configuration and the archived configuration from one commit ago

    正确答案:D

  • 第20题:

    单选题
    The difference between /ʃ/and /ʒ/ lies in________.
    A

    the place of articulation

    B

    the manner of articulation

    C

    sound duration

    D

    voicing


    正确答案: C
    解析:

  • 第21题:

    单选题
    The main difference between/m/and/n/lies in _________.
    A

    manner of articulation

    B

    place of articulation

    C

    voicing

    D

    length


    正确答案: C
    解析:

  • 第22题:

    单选题
    The main difference between/e/and/ə/lies in the__________.
    A

    tongue position

    B

    sound duration

    C

    openness of the mouth

    D

    shape of the lips


    正确答案: A
    解析:

  • 第23题:

    单选题
    A wind has caused a difference between drafts starboard and port. This difference is().
    A

    list

    B

    heel

    C

    trim

    D

    flotation


    正确答案: D
    解析: 暂无解析

  • 第24题:

    单选题
    What is the main idea of this passage?
    A

    The difference between the primary school and the secondary school.

    B

    The method that pupils get help from the teachers.

    C

    The personal development of the pupils in the secondary school.

    D

    The function of the secondary school.


    正确答案: A
    解析:
    主旨题。根据篇幅原则可知文章着重介绍了中学阶段在学生个人成长过程中的重要作用,故答案为C。D选项表述过为笼统,故不正确。