基准折现率i0是反映投资决策者对资金时间价值估计的一个参数,它的确定不仅取决于资金来源的构成和未来的投资机会,还要考虑()和()等因素的影响。
第1题:
基准折现率i0的影响因素有哪些?
(1)必须大于以任何方式筹措的资金成本(项目筹措资金和使用资金所付出的代价);
(2)必须大于投资的机会成本(最佳投资机会所获得的盈利);
(3)考虑不同项目的风险水平或风险补偿系数(投资者对投资风险要求补偿的主观判断);
(4)考虑通货膨胀因素。
第2题:
以下程序的运行结果是( ) #define MAX 10 int a[MAX],i; main() { printf("\n");sub1();sub3(A) ,sub2(),sub3(A) ; } sub2() { int a[MAX],i,max; max=5; for(i=0;i<max;i++)a[i]=i; } sub1() {for(i=0;i<MAX;i++)a[i]=i+i; } sub3(int a[]) { int i; for(i=0;i<MAX,i++)printf("%d",a[i]); printf("\n"); }
A.0 2 4 6 8 10 12 14 16 18 0 1 2 3 4
B.0 1 2 3 4 0 2 4 6 8 10 12 14 16 18
C.0 1 2 3 4 5 6 7 8 9 0 1 2 3 4
D.0 2 4 6 8 10 12 14 16 18 0 2 4 6 8 10 12 14 16 18
第3题:
下面程序的输出结果是【 】。
Private Sub Form_Click()
i=0
Do Until 0
i=i+1
if i>10 then Exit Do
Loop
Print i
End Sub
第4题:
在窗体上画一个名称为CoilTlilandl的命令按钮,然后编写如下事件过程: Private Sub command1 Click() Dim m As Integer, i As Integer, x(3)As Integer For i=0 To 3:x(i)=i:Next i For i = 1 To 2: Call sub1(x,i):Next i For i = 0 To 3: Print x(i);: Next i End Sub Private Sub sub1(a()As Integer,k As Integer) Dim i As Integer Do a(k)=a(k)+a(k+1) j = j + 1 Loop While j < 2 End Sub 程序运行后,单击命令按钮,则窗体上显示的内容是
A.0 3 7 5
B.0 1 2 3
C.3 2 4 5
D.0 5 8 3
第5题:
有如下程序: Private Sub Form_Click() Dim i As Integer, Sum As Integer sum=0 For i=2 To 10 If i Mod 2<>0 And i Mod 3=0 Then sum=sum+i End If Next i Print sum End Sub 程序运行后,单击窗体,输出结果为______。
A.12
B.30
C.24
D.18
第6题:
单击命令按钮后,下列程序代码的执行结果是______。
Public Sub fun (a As Integer, b As Integer, c As Integer)
Do
a=b+ c
n=n+1
Loop While n > 3
End Sub
Private Sub command1_ click()
Dim m As Integer, n As Integer, i As Integer
For i = 0 To 2: m = n + 1: Next i
For i = 1 To 2: Call fun (m, n, i): Next i
For i = 0 To 3
Print m;
Next i
End Sub
第7题:
下列程序运行后的输出结果是______。
Private Sub f(k,s)
s=1
For j=1 To k
s=s*j
Next
End Sub
Private Sub Command1_Click()
Sum=0
For i=1 To 3
Call f(i,s)
Sum=Sum+s
Next
Print Sum
End Sub
第8题:
第9题:
第10题:
class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?()
第11题:
0
1
2
Compilation fails.
第12题:
m<sub>0</sub><m<sub>e</sub><(x
m<sub>0</sub>=m<sub>e</sub>=(x
m<sub>0</sub>>m<sub>e</sub>>(x
m<sub>e</sub><m<sub>0</sub><(x
第13题:
下面程序的输出结果是【 】。
Private Sub Form_Click()
i=0
Do Until 0
i=i+1
if i>10 then Exit Do
Loop
Print i
End Sub
第14题:
有如下程序: Private Sub Form_Click( ) Dim i As Integer, Sum As Integer Sum = 0 For i = 2 To 10 If i Mod 2=0 And i Mod 3<>0 Then Sum = Sum + i End If Next Print Sum End Sub 程序运行后,单击窗体,输出结果为
A.12
B.30
C.24
D.18
第15题:
单击一次命令按钮之后,窗体中的输出结果为______。 Private Sub Command1_ Click() Dim a As Integer, b As Integer For i = 1 To 6 a=i*i+i Next i Call writein(a,B)Print a, b End Sub Sub writein(a, ByValB)b = 1 For i = 1 To 6 a=b* 4 b = b + 1 Next i End Sub
A.24 6
B.24 0
C.12 6
D.12 0
第16题:
有如下程序:: Private Sub Form. Click() Dim i As Integer,sum As Integer sum=0 For i=2 To 10 If i Mod 2 <>0 And i Mod 3=0 Then sum=sum+i End If Next i Print sum End Sub 程序运行后,单击窗体,输出结果为______。
A. 12
B.30
C.24
D.18
第17题:
以下能够正确计算1+2+3+…+10的程序是
A.Private Sub Command1_Click() Sum=0 ForI=1 To 10 Sum=Sum+I Next I Print Sum End Sub
B.Private Sub Command1_Click() Sum=0,I=1 Do While I<=10 Sum=Sum+I I=I+1 Print Sum End Sub
C.Private Sub Command1_Click() Sum=0: I=1 Do Sum=Sum+I I=I+1 Loop While I<10 Print Sum End Sub
D.Private Sub Command1_Click() Sum=0: I=1 Do Sum=Sum+I I=I+1 Loop Until I<10 Print Sum End Sub
第18题:
以下能够正确计算1+2+3+…+10的程序是
A.Private sub Command1_Click( ) sum=0 For 1=1 To 10 Sum=sum+1, Next I Print Sum End Sub
B.Private sub Command1_Click( ) Sum=0,I=1 Do While l<=10 Sum=Sum+1 I=I+1 Print Sum End Sub
C.Private Sub command1_click( ) Sum=0:I=1 Do Sum=Sum+1 I=I+1 Loop While I<10 Print Sum End Sub
D.Private Sub command1_Click( ) Sum=0:I=1 Do Sum=Sum+1 l=I+1 Loop Until I<10 Print Sum End Sub
第19题:
9.程序执行结果s的值是 [9] 。
Private Sub Commandl_Click()
i = 0
Do
i = i + l
s = i + s
Loop Until i > = 4
Print s
End Sub
第20题:
第21题:
如果某投资项目的净现值为0,则说明()。
A内部收益率为0
B内部收益率等于基准折现率
C内部收益率大于基准折现率
D内部收益率小于基准折现率
第22题:
第23题:
Compilation will fail.
Compilation will succeed and the program will print “0”
Compilation will succeed and the program will print “1”
Compilation will succeed and the program will print “2”