public String makinStrings() { String s = “Fred”; s = s + “47”; s = s.substring(2, 5); s = s.toUpperCase(); return s.toString(); } How many String objects will be created when this method is invoked?()
第1题:
A.1
B.2
C.3
D.4
E.5
F.6
第2题:
下列程序段: String s1=new String("How"); String s2=new String("How"); System.out.println(!(s1==s2)); 的结果为
A.false
B.true
C.1
D.0
第3题:
下列代码的执行结果是( )。 public class Test{ public static void main String args[]){ String s1=new String("welcome"); String s2=new String("welcome"); System.out.println(s1==s2); System.out.println(s1.equals(s2)); } }
A.false,false
B.false,true
C.true,true
D.true,false
第4题:
下列语句输出结果为( )。 public class test { public static void main(StringArgsl[]) { String s1=new String("How"); String s2=new String("How"); System.out.println(!(s1==s2)); } }
A.false
B.true
C.1
D.0
第5题:
下列的( )程序段可能导致错误。
A.String s="hello": Sting t="good"; String k=s+t;
B.Sting s="hello"; String t; t=s [3] + "one";
C.Sting s="hello"; String standard=s.toUpperCase( );
D.String s="hello": Stringt s +"good";
第6题:
有如下代码段 public class OperatorAndExceptions { public static void main(String args[]) { int i=10,j=15; System.out.println(i==j); String s1=new String("how are you!"); String s2=new String("how are you!"); System.out.println(s1==s2); } } 其输出为( )。
A.true false
B.true true
C.false true
D.false false
第7题:
下面程序的输出结果是() public class Test{ public static void main(String[] args){ String s = “abc dsf ghi”; String[] arr = s.split(“/s”); System.out.println(arr.length); } }
第8题:
class Mineral { static String shiny() { return "1"; } } class Granite extends Mineral { public static void main(String [] args) { String s = shiny() + getShiny(); s = s + super.shiny(); System.out.println(s); } static String getShiny() { return shiny(); } } 结果为:()
第9题:
public class foo { static String s; public static void main (String[]args) { system.out.printIn (“s=” + s); } } What is the result?()
第10题:
String s = “Gone with the wind”; String t = “ good”; String k = s + t;
String s = “Gone with the wind”; String t; t = s[3] + “one”;
String s = “Gone with the wind”; String standard = s.toUpperCase();
String s = “home directory”; String t = s – “directory”;
第11题:
“bc”
“cd”
“bcd”
“cde”
第12题:
1
2
3
4
5
6
第13题:
下列的哪个程序段可能导致错误? ( )
A.String s="hello"; String t="good"; String k=s+t;
B.String s="hello"; String t; t=s[3]+"one";
C.String s="hello"; String standard=s.toUpperCase();
D.String s="hello"; String t=s+"good";
第14题:
下列语句输出结果为( )。 public class test { public static void main(String args[]) String s1 =newString("HOW"); String s2=newString("How"): System.out.pnntln(!(s1.equals(s2))); } }
A.假
B.真
C.0
D.1
第15题:
阅读下面程序 public class OperatorsAndExpressions { void equalsMethodl(){ String s1=new String("how are you"); String s2=new String("how are you"); System.out.println(s1==s2); } public static void main(String args[]){ OperatorsAndExpressions perAndExp=new OperatorsAndExpressions(); OperAndExp.equalsMethod1(); } } 程序运行结果是( )。
A. ==
B.true
C.假
D.equal
第16题:
下列代码段的执行结果是( )。 public class Test { public static void main(String args[ ]) { String s1= new String("hello"); String s2= new String("hello"); System.out.println(s1==s2); System.out.println(s1.equal(s2)); } }
A.true false
B.true true
C.false true
D.false false
第17题:
下列的哪个程序段可能导致错误?
A.String s = "hello"; String t = "good"; String k = s + t;
B.String s = "hello"; String t; t = s[3] + "one";
C.String s = " hello "; String standard = s.toUpperCase( );
D.String s = "hello"; String t = s + "good";
第18题:
执行下列两条语句后,结果s2的值为() string s=“abcdefgh”; string s2=s.Substring(2,3);
第19题:
public class foo { public static void main (Stringargs) { String s; system.out.printIn (“s=” + s); } } What is the result?()
第20题:
public class foo { public static void main (String[]args) { String s; system.out.printIn (“s=” + s); } } What is the result?()
第21题:
Which of the following fragments might cause errors?()
第22题:
String s = Gone with the wind;String t = good ;String k = s + t;
String s = Gone with the wind;String t;t = s[3] + one;
String s = Gone with the wind;String standard = s.toUpperCase();
String s = home directory;String t = s - directory;
第23题:
3
12
111
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