A manufacturing customer has liminted space remaining in their data center and is concerned about rising power costs. The customer applications require very large amounts of memory. They want server redundancy and no downtime. Which of the following architectural features should be discussed with them?()
第1题:
A.Thememberjobswouldgetdroppedwhenthejobclassisdropped.
B.Boththejobswouldbeexecutedconcurrently.
C.Thememberjobswouldgetdisabledwhenthejobclassisdropped.
D.Theattributesdefinedattheclasslevelwouldbeappliedtoboththejobs.
E.Jobsinthejobclassmusthavebeenassignedthesamepriority.
第2题:
Click the Exhibit button and examine the data from the ORDERS and CUSTOMERS tables.Evaluate the SQL statement:SELECT *FROM ordersWHERE cust_id = (SELECT cust_idFROM customersWHERE cust_name = ‘Smith‘);What is the result when the query is executed?()
A.A
B.B
C.C
D.D
E.E
第3题:
A.CREATE PUBLIC SYNONYM cust ON mary.customer
B.CREATE PUBLIC SYNONYM cust FOR mary.customer
C.CREATE SYNONYM cust ON mary.customer FOR PUBLIC
D.不能创建CUSTOMER的公用同义词
第4题:
英译中:Manufacturing resource planning(MRP)
第5题:
You need to ensure that the Cust_CalcData column is implemented appropriately. What should you do?()
第6题:
CREATE PUBLIC SYNONYM cust ON mary.客户
CREATE PUBLIC SYNONYM cust FOR mary.客户
CREATE SYNONYM cust ON mary.客户FORPUBLIC
CREATE SYNONYM cust ON mary.客户;GRANT SELECT ON cust TO PUBLIC
第7题:
ORD_ID ORD_DATE CUST_ID ORD_TOTAL 09-MAR- 102 35 12500 18-JUL- 106 35 7000 04-AUG- 108 10 8000
ORD_ID ORD_DATE CUST_ID ORD_TOTAL 09-MAR- 102 35 12500 18-JUL- 106 35 7000
ORD_ID ORD_DATE CUST_ID ORD_TOTAL 04-AUG- 108 10 8000
The query fails because the subquery returns more than one row.
The query fails because the outer query and the inner query are using different tables.
第8题:
&p_where_clause
:p_where_clause
WHERE CUST_ID=P_CUST_ID or cust_name=:p_cust_name or cust_phone=:p_cust_phone
Where cust_ID=&p_custid cust_name=&p_cust_name or cust_phone=&p_cust_phone
第9题:
SELECT* FROM customers;
SELECT name, address FROM customers;
SELECT id, name, address, phone FROM customers;
SELECT cust_name, cust_address FROM customers;
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
第10题:
Create a subdomain named manufacturing in the wingtiptoys.com zone.
Create a delegation named manufacturing in the wingtiptoys.com zone.
Create a stub zone for manufacturing.wingtiptoys.com.
Create a primary zone for manufacturing.wingtiptoys.com that is not Active Directory-integrated.
第11题:
ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;
ALTER TABLE customers MODIFY CONSTRAINT cust_name_nn CHECK customer_name IS NOT NULL;
ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn NOT NULL;
ALTER TABLE customers MODIFY customer_name CONSTRAINT cust_name_nn IS NOT NULL;
ALTER TABLE customers MODIFY name CONSTRAINT cust_name_nn NOT NULL;
ALTER TABLE customers ADD CONSTRAINT cust_name_nn CHECK customer_name NOT NULL;
第12题:
SELECT* FROM customers;
SELECT name, address FROM customers;
SELECT id, name, address, phone FROM customers;
SELECT cust_name, cust_address FROM customers;
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
第13题:
GMP是指下列哪组英文的简写( )
A、Good Manufacturing Practice
B、Good Manufacturing Practise
C、Good Manufacture Practise
D、Goods Manufacture Practice
第14题:
A.1ST_ID
B.CUST#
C.ADDRESS1
D.EXCEPTION
第15题:
You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: CUST_ID NUMBER(4) NOT NULL CUST_NAME VARCHAR2(100) NOT NULL CUST_ADDRESS VARCHAR2(150) CUST_PHONE VARCHAR2(20) Which SELECT statement accomplishes this task?()
第16题:
下列哪个是无效的列名?()
第17题:
A manufacturing company has a large facility which has its offices at one end and a manufacturing floor at the other. The company is looking to implement new equipment that requires access to the company’s SAN that is over 2.4 kilometers away in the office area. Which of the following solutions will satisfy this requirement?()
第18题:
SELECT* FROM customers;
SELECT name, address FROM customers;
SELECT id, name, address, phone FROM customers;
SELECT cust_name, cust_address FROM customers;
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
第19题:
The member jobs would get dropped when the job class is dropped.
Both the jobs would be executed concurrently.
The member jobs would get disabled when the job class is dropped.
The attributes defined at the class level would be applied to both the jobs.
Jobs in the job class must have been assigned the same priority.
第20题:
CREATE PUBLIC SYNONYM cust ON mary.customer
CREATE PUBLIC SYNONYM cust FOR mary.customer
CREATE SYNONYM cust ON mary.customer FOR PUBLIC
不能创建CUSTOMER的公用同义词
第21题:
SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');
SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');
第22题:
SELECT cust_last_name, cust_credit_limit FROM customers ORDER BY cust_credit_limit DESC
SELECT cust_last_name, cust_credit_limit FROM customers ORDER BY cust_credit_limit
SELECT cust_last_name, cust_credit_limit FROM customers ORDER BY cust_credit_limit NULLS LAST
SELECT cust_last_name, cust_credit_limit FROM customers ORDER BY cust_last_name, cust_credit_limit NULLSLAST
第23题:
SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Martin' AND ord_date IN ('18-JUL-2000','21-JUL-2000');
SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'Martin'));
SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders, customers WHERE cust_name = 'Martin');
SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust_name = 'Martin');
第24题:
SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));
SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');
SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');