varchar2最大多大()
第1题:
(2)问绳能承受的最大拉力多大?
第2题:
当电线积冰直径达到多大数值时,须测定一次积冰最大重量?
第3题:
最大的鸟巢多大?
第4题:
目前中华恐龙馆内珍藏的国内最大的恐龙叫什么?有多大?
第5题:
ORACLE中char类型与varchar2类型的区别,描述正确的是()
第6题:
9月18日,青岛港迎来世界最大集装箱船舶“()”号首航,世界最大船舶与世界最大码头的完美结合,凸显了青岛港“世界上有多大的船舶、青岛港就有多大的码头”的雄厚实力。
第7题:
RIP允许的最大网络范围是多大?
第8题:
第9题:
1000
2000
3000
4000
第10题:
COUNT(UPPER(country_address))
COUNT(DIFF(UPPER(country_address)))
COUNT(UNIQUE(UPPER(country_address)))
COUNT DISTINTC UPPER(country_address)
COUNT(DISTINTC (UPPER(country_address)))
第11题:
SELECT TOTAL(*) FROM customer;
SELECT COUNT(*) FROM customer;
SELECT TOTAL(customer_id) FROM customer;
SELECT COUNT(customer_id) FROM customer;
SELECT COUNT(customers) FROM customer;
SELECT TOTAL(customer_name) FROM customer;
第12题:
COUNT(UPPER(country_address))
COUNT(DIFF(UPPER(country_address)))
COUNT(UNIQUE(UPPER(country_address)))
COUNT DISTINCT UPPER(country_address)
COUNT(DISTINCT (UPPER(country_address)))
第13题:
(2)运动员要达到最大水平运动距离,B点的高度h应调为多大?对应的最大水平距离SBH为多少?
第14题:
FACULTY表包含以下各列: FACULTYID VARCHAR2(5) NOT NULL PRIMARY KEY FIRST_NAME VARCHAR2(20) LAST_NAME VARCHAR2(20) ADDRESS VARCHAR2(35) CITY VARCHAR2(15) STATE VARCHAR2(2) ZIP NUMBER(9) TELEPHONE NUMBER(10) STATUS VARCHAR2(2) NOT NULL COURSE 表包含以下各列: COURSEID VARCHAR2(5) NOT NULL PRIMARY KEY SUBJECT VARCHAR2(5) TERM VARCHAR2(6 FACULTYID VARCHAR2(5) NOT NULL FOREIGN KEY 您需要制定一个报表,用于确定在下学期任教的所有副教授。您要创建一个视图来简化报表的创建过程。以下哪条CREATE VIEW语句将完成此任务()
第15题:
我国面积最大的珊瑚岛是哪个岛?有多大?
第16题:
世界上最大的单体汉字“神”字王有多大?是谁书写的?
第17题:
临时磁盘最大允许多大()。
第18题:
修改表Department添加列Leader数据类型varchar2(10)的语句是:Alter table Department add Leader varchar2(10);
第19题:
第20题:
第21题:
SELECT customer_id, customer_name FROM customers WHERE postal_code CONTAINS NULL;
SELECT customer_id, customer_name FROM customers WHER postal_code = ' ___________';
SELECT customer_id, customer_name FROM customers WHERE postal _ code IS NULL;
SELECT customer_id, customer_name FROM customers WHERE postal code IS NVL;
SELECT customer_id, customer_name FROM customers WHERE postal_code = NULL;
第22题:
第23题:
SELECT city_address, COUNT(*) FROM customers WHERE city _ address IN ('Los Angeles','San Fransisco');
SELECT city_address, COUNT (*) FROM customers WHERE city address IN ( 'Los Angeles', 'San Fransisco') GROUP BY city_address;
SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ( 'Los Angeles', 'San Fransisco') GROUP BY city_address, customer_ id;
SELECT city_address, COUNT (customer_id) FROM customers GROUP BY city_ address IN ('Los Angeles','San Fransisco');