抖音企业号》:哪种广告主可以获得免费认证名额?()。
第1题:
以下哪种说法错误的是()
第2题:
广告主在创建广告时,以下哪些为GDT的投放平台()
第3题:
什么是云图平台?()
第4题:
客户进行抖音企业认证的途径有()。
第5题:
通过号外推广的文章和在AD后台推广文章有区别吗()
第6题:
哪些身份的用户有卡券平台使用权限?()
第7题:
()指通过聚合网络媒体广告资源,形成投放平台,帮助广告主实现多个媒体资源组合投放的投放形式。
第8题:
The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) Which statement finds the rows in the CUSTOMERS table that do not have a postal code? ()
第9题:
The ORDERS table has these columns: ORDER_ID NUMBER(4) NOT NULL CUSTOMER_ID NUMBER(12) NOT NULL ORDER_TOTAL NUMBER(10,2) The ORDERS table tracks the Order number, the order total, and the customer to whom the Order belongs. Which two statements retrieve orders with an inclusive total that ranges between 100.00 and 2000.00 dollars? ()
第10题:
SELECT TOTAL(*) FROM customer;
SELECT COUNT(*) FROM customer;
SELECT TOTAL(customer_id) FROM customer;
SELECT COUNT(customer_id) FROM customer;
SELECT COUNT(customers) FROM customer;
SELECT TOTAL(customer_name) FROM customer;
第11题:
对
错
第12题:
( 难度:中等)在Hive中,以下哪个SQL语句是错误的
A.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> LEFT OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID);
B.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> RIGHT OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID);
C.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> FULL OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID);
D.hive> SELECT ID, NAME, o.AMOUNT, o.DATE
> FROM CUSTOMERS c
> FULL OUTER JOIN ORDERS o
> ON (ID = o.CUSTOMER_ID OR Name = o.Name);
答案:D
第13题:
抖音竞价广告投放的问题支持在Debug平台查询吗()
第14题:
客户可以通过什么形式获得抖音企业认证?()
第15题:
关于Dou+GD以下说法正确的是()。
第16题:
客户想投放抖音,但是自己没有能力拍视频,我们能够提供给客户什么?()
第17题:
dou+GD一定要抖音企业号才可以投放。
第18题:
以下关于抖音直播的说法错误的是()
第19题:
The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which two statements find the number of customers? ()
第20题:
当需要删除某个序列seq_customer_id,可以使用如下()方式。
第21题:
SELECT customer_id, order_id, order_total FROM orders RANGE ON order _ total (100 AND 2000) INCLUSIVE;
SELECT customer_id, order_id, order_total FROM orders HAVING order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and <= 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and order_total <= 2000;
第22题:
SELECT customer_id, customer_name FROM customers WHERE postal_code CONTAINS NULL;
SELECT customer_id, customer_name FROM customers WHER postal_code = ' ___________';
SELECT customer_id, customer_name FROM customers WHERE postal _ code IS NULL;
SELECT customer_id, customer_name FROM customers WHERE postal code IS NVL;
SELECT customer_id, customer_name FROM customers WHERE postal_code = NULL;
第23题:
SELECT customer_id, order_id, order_total FROM orders RANGE ON order _ total (100 AND 2000) INCLUSIVE;
SELECT customer_id, order_id, order_total FROM orders HAVING order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order _ total BETWEEN 100 and 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and <= 2000;
SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and order_total <= 2000;