A. moved
B. launched
C. set
D. resumed
第1题:
Examine the structure of the EMPLOYEES and DEPARTMENTS tables:EMPLOYEESEMPLOYEE_ID NUMBERDEPARTMENT_ID NUMBERMANAGER_ID NUMBERLAST_NAME VARCHAR2(25)DEPARTMENTSDEPARTMENT_ID NUMBERMANAGER_ID NUMBERDEPARTMENT_NAME VARCHAR2(35)LOCATION_ID NUMBERYou want to create a report displaying employee last names, department names, and locations. Which query should you use to create an equi-join?()
A. SELECT last_name, department_name, location_id FROM employees , department ;
B. SELECT employees.last_name, departments.department_name, departments.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;
C. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE manager_id = manager_id;
D. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;
第2题:
Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?()

A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);
B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;
第3题:
A.netrpcjoin-mlocalhost-ldap="ldap.ldapserver.comComputers\BusinessUnit\Department\Servers"
B.rpcclient-c"joinComputers\BusinessUnit\Department\Servers"
C.netadsjoinou="Computers\BusinessUnit\Department\Servers"
D.netadsjoin"Computers\BusinessUnit\Department\Servers"
第4题:
Examine the data in the EMPLOYEES and DEPARTMENTS tables.EMPLOYEESLAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000Kochhar 5000DEPARTMENTSDEPARTMENT_ID DEPARTMENT_NAME10 Sales20 Marketing30 Accounts40 AdministrationYou want to retrieve all employees, whether or not they have matching departments in the departments table.Which query would you use?()
A. SELECT last_name, department_name FROM employees , departments(+);
B. SELECT last_name, department_name FROM employees JOIN departments(+);
C. SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments d
D. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
E. SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);
F. SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
第5题:
有如下SQL SELECT语句 SELECT*FORM. 工资表 WHERE 基本工资<=2000 AND 基本工资>=1500 下列与该语句等价的
A.SELECT*FORM. 工资表 WHERE 基本工资 BETWEEN 1500 AND 2000
B.SELECT*FORM. 工资表 WHERE 基本工资 BETWEEN 2000 AND 1500
C.SELECT*FORM. 工资表 WHERE 基本工资 FROM1500 INTO 2000
D.SELECT*FORM. 工资表 WHERE 基本工资 FROM 2000 INTO 1500
第6题:
有下列SQL SELECT语句: SELECT * FORM. 成绩表 WHERE 物理 BETWEEN 80 AND 90 下列与该语句等价的( )。
A.SELECT * FORM. 成绩表 WHERE 物理<=90 AND 物理 >=80
B.SELECT * FORM. 成绩表 WHERE 物理 <90 AND 物理>80
C.SELECT * FORM. 成绩表 WHERE 物理>=90 AND 物理<=80
D.SELECT * FORM. 成绩表 WHERE 物理>90 AND 物理<80