There was a knock at the door. It was the second time I that evening.()A. interruptedB. was interruptingC. had interruptedD. had been interrupted
题目
There was a knock at the door. It was the second time I that evening.()
A. interrupted
B. was interrupting
C. had interrupted
D. had been interrupted
相似考题
参考答案和解析
更多“There was a knock at the door. It was the second time I that evening.()A. interrupted ”相关问题
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第1题：
下面的程序的运行结果是__________
func main() {strs := []string{"one", "two", "three"}for _, s := range strs { go func() { time.Sleep(1 * time.Second) fmt.Printf("%s ", s) }()}time.Sleep(3 * time.Second)}
参考答案：three three three
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第2题：
执行下列程序，显示的结果是______。
first="china"
second=""
a=LEN(first)
i=a
DO WHILE i＞=1
second=second+SUBSTR(first,i,1)
i=i-1
ENDDO
?second
正确答案：anihc
anihc 解析：变量a使用LEN函数取得字符串变量first的长度，该变量包含5个字母，所以它的长度为5，即a=5，然后将a的值赋给i，那么i也等于5。使用一个DO WHILE循环语句来操作，判断条件是变量i是否大于等于0，如果小于0，则退出循环，否则执行循环体。此时SUBSTR(first,5,1)的值为a，(从“china”字符串的第5位开始取一位字符)；执行i=i-1后，i=4，重复此循环体的操作，变量second的值依次为a、an、ani、anih，anihc，最后i0，退出循环体。 -
第3题：
以下代码的执行结果是： n = 1 def func（a, b): c = a * b return c s = func（"knock~", 2) print（c)
A．knock~ 1
B．knock~knock~ 2
C．knock~knock~ 1
D．报错
3 -
第4题：
When you ______ at the door, I ______ some washing.
A、knocked; did
B、was knowcking; did
C、knocked; was doing
D、knock; am doing
正确答案:C
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第5题：
以下代码的执行结果是： n = 1 def func（a, b): n = b return a*b s = func（"knock~", 2) print（s, n)
A．knock~ 1
B．knock~knock~ 2
C．knock~knock~ 1
D．报错
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第6题：
接上题，下列代码实现对闹铃音的控制： assign alarm_time=stop_bell？（time_equ && （（（Second[0]==1'b1) && clk_500) || （（Second[0]==1'b0) && clk_1k))):1'b0; 这个表述可以改写为（）。
A.if (stop_bell==1'b1) begin case(Second[0]) 1'b1:alarm_time=clk_500; 1'b0:alarm_time=clk_1k; default:alarm_time=1'b0; endcase end else alarm_time=1'b0;#B.if (stop_bell) if(!time_equ) begin case(Second[0]) 1'b1:alarm_time=clk_500; 1'b0:alarm_time=clk_1k; default:alarm_time=1'b0; endcase end else alarm_time=1'b0; else alarm_time=1'b0;#C.if (stop_bell==1'b1) if(time_equ) begin case(Second[0]) 1'b1:alarm_time=clk_500; 1'b0:alarm_time减少华法林用量