Based on the description of a lahar deposit, how do clasts and matrix particles differ in size?A.Any clast is larger than the largest matrix particle.B.Any clast is smaller than the smallest matrix particle.C.Some, but not all, clasts are smaller than the

题目

Based on the description of a lahar deposit, how do clasts and matrix particles differ in size?

A.Any clast is larger than the largest matrix particle.

B.Any clast is smaller than the smallest matrix particle.

C.Some, but not all, clasts are smaller than the largest matrix particle.

D.Some, but not all, matrix particles are larger than the smallest clast.

相似考题

1.The strong matrix versus a weak matrix.A . team members are more likely to be assigned to the project office in a strong matrixB . strong matrix is more difficult to manage.C . the balance of power has shifted away from the PM.D . functional managers no longer has control over the technical processes.E . All of the above.

2.According to Figure 3, clasts and matrix particles having diameters greater than or equal to 0.5 mm made up approximately what percent of the total mass of the combined samples?A.13%B.33%C.63%D.83%

3.The value of the collateral must be ______.A．greater than the loan amountB．the same as or be greater than the loan amountC．smaller than the loan amountD．the same as the loan amount

4.In a matrix organizational form, MBO may be difficult to implement:A . If the functional employees are supervised closely by the line manager rather than the project managerB . Unless the project manager has an input into the employee's performance reviewC . Unless the project and line managers agree on the ultimate objectiveD . Unless the project and line managers agree to the duration of the taskE . None of the above are correct answers

更多“Based on the description of a lahar deposit, how do clasts and matrix particles differ in size?A.Any clast is larger than the largest matrix particle.B.Any clast is smaller than the smallest matrix particle.C.Some, but not all, clasts are smaller than the”相关问题

  • 第1题：

    下面语句中错误的是 ( )

    A．ReDim Preserve Matrix(10, UBound(Matrix, 2)+1)

    B．ReDim Preserve Matrix(UBound(Matrix, 1)-4-1, 10)

    C．ReDim Preserve DynArray(UBound(DynArray)+1)

    D．ReDim DynArray(UBound(DynArray)+1)


    正确答案：B
    解析：ReDim语句的一般格式为：ReDim [Preserve]数组名(下标上界[，下标上界]......)[As类型]如果想在程序中知道数组的下界值和上界值可以使用LBound和UBound函数，格式为：LBound(数组名[，维])UBound(数组名[，维])，题中可知数组 Matrix是二维的，故UBound(Matrix，1)有误，应为UBound (Matrix，2)。选项B的语句错误。

  • 第2题：

    Which two statements are true about MLP interleaving? ()

    A. It fragments and encapsulates all packets in a fragmentation header.

    B. Packets smaller than the fragmentation size are interleaved between the fragments of the larger packets.

    C. Packets larger than the fragmentation size are always fragmented, and cannot be interleaved, even if the traffic is voice traffic.

    D. It fragments and encapsulates packets that are longer than a configured size, but does not encapsulate smaller packets inside a fragmentation header.


    参考答案：B, D

  • 第3题：

    The total resistance of a parallel circuit is always______.

    A.larger than the greatest branch resistance

    B.smaller than the lowest branch resistance

    C.equal to the sum of the individual branch resistances

    D.one-half the sum of the individual branch resistances


    正确答案：B

  • 第4题：

    阅读下列Java程序，回答下列问题。
    [Java 程序]
    public int addAppTask(Activity activity, Intent intent,
    TaskDescription description, Bitmap thumbnail) {
    Point size = getSize1; //1
    final int tw = thumbnail.getWidth1;
    final int th = thumbnail.getHeight1;
    if (tw != size.x || th != size.y) { //2,3
    Bitmap bm = Bitmap.createBitmap(size.x, size.y, thumbnail
    .getConfig1); //4
    float scale;
    float dx = 0, dy = 0;
    if (tw * size.x ＞ size.y * th) { //5
    scale = (float) size.x / (float) th; //6
    dx = (size.y - tw * scale) * 0.5f;
    } else { //7
    scale = (float) size.y / (float) tw;
    dy = (size.x - th * scale) * 0.5f;
    }
    Matrix matrix = new Matrix1;
    matrix.setScale(scale, scale);
    matrix.postTranslate((int) (dx + 0.5f), 0);
    Canvas canvas = new Canvas(bm);
    canvas.drawBitmap(thumbnail, matrix, null);
    canvas.setBitmap(null);
    thumbnail = bm;
    }
    if (description == null) { //8
    description = new TaskDescription1; //9
    }
    } //10
    1、请简述基本路径测试法的概念。（2分）
    2、请画出上述程序的控制流图，并计算其控制流图的环路复杂度vfG.。（8分）
    3、请给出问题2中控制流图的线性无关路径。（5分）


    答案：
    解析：
    1、基本路径测试法是在程序控制流图的基础上，通过分析控制构造的环路复杂性，导出基本可执行路径集合，从而设计测试用例的方法。
    2、控制流图



    环路复杂度V(G)=5
    3、线性无关路径：
    1．1-2-4-5-6-8-9-10
    2．1-2-4-5-7-8-9-10(1-2-4-5-7-8-10)
    3．1-2-4-5-6-8-10(1-2-4-5-7-8-10)
    4．1-2-3-4-5-6-8-9-10(1-2-3-4-5-7-8-9-10，1-2-3-4-5-6-8-10，1-2-3-4-5-7-8-10)
    5．1-2-3-8-9-10(1-2-3-8-10)
    【解析】
    本题考查白盒测试法的应用。
    第一小题考查白盒测试用例设计方法中的基本路径测试法。
    基本路径测试法是在程序控制流图的基础上，通过分析控制构造的环路复杂性，导出基本可执行路径集合，从而设计测试用例的方法。
    第二小题考查白盒测试用例设计方法：基本路径测试法。涉及到的知识点包括根据代码绘制控制流图、计算环路复杂度。
    控制流图是描述程序控制流的一种图示方式，它由节点和定向边构成。控制流图的节点代表一个基本块，定向边代表控制流的方向。其中要特别注意的是，如果判断中的条件表达式是复合条件，即条件表达式是由一个或多个逻辑运算符连接的逻辑表达式，则需要改变复合条件的判断为一系列之单个条件的嵌套的判断。本题程序中，if(tw!=size.x || th!=size.y)这条判断语句中的判定由两个条件组成，因此在画控制流图的时候需要拆开成两条判断语句。需要注意的是，复合条件之间是“&&”的关系还是“||”的关系反应在控制流图的画法是不同的。
    程序的环路复杂度等于控制流图中判定节点的个数加1，本题控制流图中判定节点个数为4，所以V(G)=5。
    第三小题考查白盒测试用例设计方法：基本路径法。涉及到的知识点包括：根据控制流图和环路复杂度给出线性无关路径。
    线性无关路径是指包含一组以前没有处理的语句或条件的路径。从控制流图上来看，一条线性无关路径是至少包含一条在其他线性无关路径中从未有过的边的路径。程序的环路复杂度等于线性无关路径的条数，所以本题中应该有5条线性无关路径。

  • 第5题：

    For SONET ring switching， the 50ms switch time： Select all that apply？（）

    • A、Plncludes the detection time
    • B、Applies to rings smaller than 1200km
    • C、Applies to rings smaller than 1000km
    • D、Includes up to 16 nodes

    正确答案:B,D

  • 第6题：

    Why does RSTP have a better convergence time than 802.1D？（）

    • A、it is newer
    • B、it has smaller timers
    • C、it has less overhead
    • D、it is not timer-based

    正确答案:D

  • 第7题：

    单选题
    Generally speaking, men play ball games much better than women because ______.
    A

    men play ball games more often than women

    B

    men love ball games more than women do

    C

    men’s hand and eye movements are quicker in response

    D

    men have a smaller number of nerves in their brains than women


    正确答案： B
    解析：
    录音中提到“Boys also are generally faster in response than girls of hand and eye movements in ball games”，意思是：通常情况下，男孩子在球类运动中手眼运动反应比女孩子快，所以选项C的表述符合原文意思。

  • 第8题：

    单选题
    All of these alternatives are carbon-based fuels（）molecules are smaller and simpler than those of gasoline.
    A

    which

    B

    who

    C

    what

    D

    whose


    正确答案： C
    解析： 暂无解析

  • 第9题：

    单选题
    Cast iron pistons used in large propulsion diesel engines are constructed with （）
    A

    not taper what so ever

    B

    the skirt being tapered and smaller than the crown

    C

    the skirt being tapered and larger than the crown

    D

    the crown being tapered and smaller than the skirt


    正确答案： B
    解析： 暂无解析

  • 第10题：

    单选题
    On modern ships, centrifugal pump with a self-primer has replaced reciprocating pump as bilge pump because（）
    A

    centrifugal pump is cheaper than reciprocating pump

    B

    the size of centrifugal pump with same capacity is smaller than that of reciprocating pump

    C

    centrifugal pump makes maintenance easier than reciprocating pump does

    D

    all of the above


    正确答案： B
    解析： 暂无解析

  • 第11题：

    单选题
    As a white dwarf, the sun will be.
    A

    the same size as the planet Mercury

    B

    thousands of times smaller than it is today

    C

    around 35 million miles in diameter

    D

    cold and dark


    正确答案： B
    解析：
    细节题。第三段第二句指出“一旦太阳缩小到地球大小时，它就会变成一个白色的矮星”。而文章首段最后一句提到“The sun…is thousands of times larger than the Earth”，由此可知当太阳变成一个白色的矮星时，它就会比现在小几千倍。故选B。

  • 第12题：

    问答题
    Practice 2　　The laptop computer is a small, portable computer that’s light and small enough to hold on your lap. It is smaller than a luggage but larger than a notebook computer. A laptop usually weighs between 8 and 14 pounds, and when folded shut is about the size of a small briefcase. Laptops can be plugged in or run on batteries, although the batteries must be recharged every few hours. Laptop computers use a thin, light weight display screen called a flat-panel display, rather than the cathode ray tube technology of larger personal computers. Laptop displays vary widely in quality. Typically, their display screens show fewer lines than displays on larger computers and can be difficult to read in bright light. Laptops are self-contained units, having their own CPUs, memory, and disk drives. While more expensive than a desktop computer with equivalent computing power, a laptop can be ideal for the on-the-go user who needs a second, portable computer. Laptops aren’t always a suitable replacement for desktop computer, since they can’t be expanded or modified easily should your computing needs change. Also, the display is inferior to standard video graphics array（VGA）displays, although active matrix displays compete well except for size.

    正确答案：
    【参考译文】
    膝上型计算机是一种小型便携式计算机,重量轻,机型小,可以放在膝上使用。其形状比行李箱小,但比笔记本电脑大,重量一般在8到14磅左右,折叠起来和小号公文包差不多大小。可以插电源也可以使用电池运行,电池每隔几个小时就必须充电。这类计算机不像较大型的个人电脑那样采用阴极射线管技术,而是采用一种名叫平板显示器的薄型轻质显示屏。膝上型计算机显示器的质量良莠不一。一般而言,其显示屏显示的行数比大型个人计算机少,且在强光下很难看清。膝上型电脑机型虽小然而五脏俱全,拥有自己的中央处理器、内存和光驱。尽管膝上型计算机比功能相当的台式机贵很多,然而对于经常到处奔波而另外需要一台便携式计算机的人来说这种计算机还是很理想的选择。如果用户使用计算机处理信息的需求发生变化,膝上型计算机很难相应地扩大容量或做出其他调整,因此有时用这类计算机来取代台式机也不太合适。而且,虽然膝上型计算机的活性矩阵显示器的屏幕大小可以与影像列阵显示器相媲美,但是总的来说,膝上型计算机的显示器不如标准的影像列阵显示器好。
    解析： 暂无解析

  • 第13题：

    Why is IPv6 packet processing more effective than IPv4 packet processing?()

    A. fixed header size

    B. smaller header size

    C. fewer header fields

    D. variable header size


    参考答案：A

  • 第14题：

    阅读文章回答第65~68题C People diet to look more attractive. Fish diet to avoid being beaten up, thrown out of their social group, and getting eaten as a result. That is the fascinating conclusion of the latest research into fish behavior. by a team of Australian scientists.

    The research team have discovered that subordinate fish voluntarily diet to avoid challenging their larger competitors. “In studying gobies we noticed that only the largest two individuals, a male and female, had breeding （繁殖） rights within the group,” explains Marian Wong. “All other group members are nonbreeding females, each being 5-10% smaller than its next largest competitor. We wanted to find out how they maintain this precise size separation.”

    The reason for the size difference was easy to see. Once a subordinate fish grows to within 5-10% of the size of its larger competitor, it causes a fight which usually ends in the smaller goby being driven away from the group. More often than not, the evicted fish is then eaten up.

    It appeared that the smaller fish were keeping themselves small in order to avoid challenging the boss fish. Whether they did so voluntarily, by restraining how much they ate, was not clear. The research team decided to do an experiment. They tried to fatten up some of the subordinate gobies to see what happened. To their surprise, the gobies simply refused the extra food they were offered, clearly preferring to remain small and avoid fights, over having a feast.

    The discovery challenges the traditional scientific view of how boss individuals keep their position in a group. Previously it was thought that large individuals simply used their weight and size to threaten their subordinates and take more of the food for themselves, so keeping their competitors small.

    While the habits of gobies may seem a little mysterious, Dr. Wong explains that understanding the relationships between boss and subordinate animals is important to understanding how hierarchical （等级的） societies remain stable.

    The research has proved the fact that voluntary dieting is a habit far from exclusive to humans. “As yet, we lack a complete understanding of how widespread the voluntary reduction of food intake is in nature,” the researchers comment. “Data on human dieting suggests that, while humans generally diet to improve health or increase attractiveness, rarely does it improve long-term health and males regularly prefer females that are fatter than the females’ own ideal.”

    第10题：When a goby grows to within 5-10% of the size of its larger competitor, it .

    A． faces danger

    B． has breeding rights

    C． eats its competitor

    D． leaves the group itself


    正确答案：A

  • 第15题：

    A VLCC（100，000 DWT+）with a 30，000 Shaft Horsepower Steam Turbine is slow to respond to engine movements and has less stopping power than normal ships because it has a ______．

    A.Bigger propeller

    B.Smaller power weight ratio

    C.Smaller propeller

    D.Larger power weight ratio


    正确答案：B

  • 第16题：

    Which two statements are true about MLP interleaving？ （）

    • A、 It fragments and encapsulates all packets in a fragmentation header.
    • B、 Packets smaller than the fragmentation size are interleaved between the fragments of thelarger packets.
    • C、 Packets larger than the fragmentation size are always fragmented， and cannot be interleaved，even if the traffic is voice traffic.
    • D、 It fragments and encapsulates packets that are longer than a configured size， but does not encapsulate smaller packets inside a fragmentation header.

    正确答案:B,D

  • 第17题：

    The IT department requested a report to list each server name and the name of each department that utilizes resources from each server. You create a tabular layout that breaks on the server name. You ran the report and noticed that the department field is too large for most of the department names. Which field size setting would you use to allow the field to be smaller but not larger than the field layout size?（）

    • A、Fixed 
    • B、Expand 
    • C、Contract 
    • D、Variable

    正确答案:C

  • 第18题：

    Why is IPv6 packet processing more effective than IPv4 packet processing?（）

    • A、fixed header size
    • B、smaller header size
    • C、fewer header fields
    • D、variable header size

    正确答案:A

  • 第19题：

    单选题
    Most pump manufacturers recommend that the suction piping dimension for centrifugal pumps be （）.
    A

    one size smaller than the pump suction nozzle

    B

    the same size as the pump suction nozzle

    C

    one size larger than the pump suction nozzle

    D

    installed with a short radius elbow at the pump


    正确答案： C
    解析： 暂无解析

  • 第20题：

    单选题
    Most pump manufacturers recommended that the discharge piping for centrifugal pumps be （）.
    A

    one size larger than the pump discharge nozzle

    B

    the same size as the pump discharge nozzle

    C

    one size smaller than the pump discharge nozzle

    D

    installed with a short radius elbow at the pump


    正确答案： C
    解析： 暂无解析

  • 第21题：

    单选题
    “The hole must be just right” means it is _____.
    A

    big enough for the monkey to put its hand in

    B

    smaller than a monkey’s hand

    C

    bigger than a monkey’s fist

    D

    bigger than a monkey’s hand but smaller than its fist


    正确答案： D
    解析：
    通读下文可知，洞必须够大让猴子的手进去，但不能太大让它的拳头出来。

  • 第22题：

    单选题
    What does the underlined word “outnumber” mean?
    A

    To be smaller in size than another group.

    B

    To be more in number than another group.

    C

    To be bigger in area than another group.

    D

    To be smaller in area than another group.


    正确答案： D
    解析：
    词义猜测题。根据上下文语境可知，此处“outnumber”表示“数目超过，多于”。

  • 第23题：

    单选题
    Why does RSTP have a better convergence time than 802.1D？（）
    A

    it is newer

    B

    it has smaller timers

    C

    it has less overhead

    D

    it is not timer-based


    正确答案： C
    解析： 暂无解析

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